1 Introduction
1.1 Classical conjectures
In this paper, we study multiple zeta values (abbreviated as MZV’s) over function fields in positive characteristic introduced by Thakur [Reference Thakur31]. Our motivation arises from Zagier’s dimension conjecture and Hoffman’s basis conjecture for classical real MZV’s.
 The special value of the Riemann 
 $\zeta $
-function at positive integer
$\zeta $
-function at positive integer 
 $s\geq 2$
 is the following series:
$s\geq 2$
 is the following series: 
 $$\begin{align*}\zeta(s):=\sum_{n=1}^{\infty} \frac{1}{n^{s}}\in \mathbb{R}^{\times}. \end{align*}$$
$$\begin{align*}\zeta(s):=\sum_{n=1}^{\infty} \frac{1}{n^{s}}\in \mathbb{R}^{\times}. \end{align*}$$
Classical real MZV’s are generalizations of the special 
 $\zeta $
-values above. Their study was initiated by Euler on double zeta values and fully generalized by Zagier [Reference Zagier36] in the 1990s. An admissible index is an r-tuple of positive integer
$\zeta $
-values above. Their study was initiated by Euler on double zeta values and fully generalized by Zagier [Reference Zagier36] in the 1990s. An admissible index is an r-tuple of positive integer 
 $\mathfrak {s}=(s_{1},\ldots ,s_{r})\in \mathbb {Z}_{>0}^{r}$
 with
$\mathfrak {s}=(s_{1},\ldots ,s_{r})\in \mathbb {Z}_{>0}^{r}$
 with 
 $s_{1}\geq 2$
. The real MZV at
$s_{1}\geq 2$
. The real MZV at 
 $\mathfrak {s}$
 is defined by the following multiple series:
$\mathfrak {s}$
 is defined by the following multiple series: 
 $$\begin{align*}\zeta(\mathfrak{s}):=\sum_{n_{1}> \cdots > n_{r}\geq 1} \frac{1 }{n_{1}^{s_{1}} \cdots n_{r}^{s_{r}} } \in \mathbb{R}^{\times}. \end{align*}$$
$$\begin{align*}\zeta(\mathfrak{s}):=\sum_{n_{1}> \cdots > n_{r}\geq 1} \frac{1 }{n_{1}^{s_{1}} \cdots n_{r}^{s_{r}} } \in \mathbb{R}^{\times}. \end{align*}$$
We call 
 $\operatorname {\mathrm {wt}}(\mathfrak {s}):=\sum _{i=1}^{r}s_{i}$
 and
$\operatorname {\mathrm {wt}}(\mathfrak {s}):=\sum _{i=1}^{r}s_{i}$
 and 
 $\operatorname {\mathrm {dep}}(\mathfrak {s}):=r$
 the weight and depth of the presentation
$\operatorname {\mathrm {dep}}(\mathfrak {s}):=r$
 the weight and depth of the presentation 
 $\zeta (\mathfrak {s})$
, respectively. Over the past decades, the study of real MZV’s has attracted many researchers’ attention as MZV’s have many interesting and important connections with various topics. For example, MZV’s occur as periods of mixed Tate motives by Terasoma [Reference Terasoma29], Goncharov [Reference Goncharov18] and Deligne-Goncharov [Reference Deligne and Goncharov16], and MZV’s of depth two have close connection with modular forms by Gangl-Kaneko-Zagier [Reference Gangl, Kazeko and Zagier17] etc. For more details and relevant references, we refer the reader to the books [Reference André5, Reference Zhao37, Reference Burgos Gil and Fresán7].
$\zeta (\mathfrak {s})$
, respectively. Over the past decades, the study of real MZV’s has attracted many researchers’ attention as MZV’s have many interesting and important connections with various topics. For example, MZV’s occur as periods of mixed Tate motives by Terasoma [Reference Terasoma29], Goncharov [Reference Goncharov18] and Deligne-Goncharov [Reference Deligne and Goncharov16], and MZV’s of depth two have close connection with modular forms by Gangl-Kaneko-Zagier [Reference Gangl, Kazeko and Zagier17] etc. For more details and relevant references, we refer the reader to the books [Reference André5, Reference Zhao37, Reference Burgos Gil and Fresán7].
 By the theory of regularized double shuffle relations [Reference Racinet28, Reference Ihara, Kaneko and Zagier23], there are rich 
 $\mathbb {Q}$
-linear relations among the same weight MZV’s. One core problem on this topic is Zagier’s following dimension conjecture:
$\mathbb {Q}$
-linear relations among the same weight MZV’s. One core problem on this topic is Zagier’s following dimension conjecture:
Conjecture 1.1 (Zagier’s dimension conjecture).
 For an integer 
 $w\geq 2$
, we let
$w\geq 2$
, we let 
 $\mathfrak {Z}_w$
 be the
$\mathfrak {Z}_w$
 be the 
 $\mathbb {Q}$
-vector space spanned by real MZV’s of weight w. We put
$\mathbb {Q}$
-vector space spanned by real MZV’s of weight w. We put 
 $d_{0}:=1$
,
$d_{0}:=1$
, 
 $d_{1}:=0$
,
$d_{1}:=0$
, 
 $d_{2}:=1$
 and
$d_{2}:=1$
 and 
 $d_{w}:=d_{w-2}+d_{w-3}$
 for integers
$d_{w}:=d_{w-2}+d_{w-3}$
 for integers 
 $w\geq 3$
. Then for each integer
$w\geq 3$
. Then for each integer 
 $w\geq 2$
, we have
$w\geq 2$
, we have 
 $$\begin{align*}{\mathrm{dim}}_{\mathbb{Q}}\mathfrak{Z}_{w}=d_{w}. \end{align*}$$
$$\begin{align*}{\mathrm{dim}}_{\mathbb{Q}}\mathfrak{Z}_{w}=d_{w}. \end{align*}$$
 The best known result towards Zagier’s dimension conjecture until now has been the upper bound result proved by Terasoma [Reference Terasoma29] and Goncharov [Reference Goncharov18] independently. Namely, they showed that 
 ${\mathrm {dim}}_{\mathbb {Q}}\mathfrak {Z}_{w}\leq d_{w}$
 for all integers
${\mathrm {dim}}_{\mathbb {Q}}\mathfrak {Z}_{w}\leq d_{w}$
 for all integers 
 $w\geq 2$
. Furthermore, Hoffman [Reference Hoffman21] proposed the following conjectural basis for
$w\geq 2$
. Furthermore, Hoffman [Reference Hoffman21] proposed the following conjectural basis for 
 $\mathfrak {Z}_{w}$
 for each
$\mathfrak {Z}_{w}$
 for each 
 $w\geq 2$
.
$w\geq 2$
.
Conjecture 1.2 (Hoffman’s basis conjecture).
 For an integer 
 $w\geq 2$
, we let
$w\geq 2$
, we let 
 $\mathcal {I}_{w}^{\mathrm {H}}$
 be the set of admissible indices
$\mathcal {I}_{w}^{\mathrm {H}}$
 be the set of admissible indices 
 $\mathfrak {s}=(s_{1},\ldots ,s_{r})$
 with
$\mathfrak {s}=(s_{1},\ldots ,s_{r})$
 with 
 $s_{i}\in \left \{2,3 \right \}$
 satisfying
$s_{i}\in \left \{2,3 \right \}$
 satisfying 
 $\operatorname {\mathrm {wt}}(\mathfrak {s})=w$
. Then the following set
$\operatorname {\mathrm {wt}}(\mathfrak {s})=w$
. Then the following set 
 $$\begin{align*}\mathcal{B}_{w}^{\mathrm{H}}:=\left\{ \zeta(\mathfrak{s})|\mathfrak{s}\in \mathcal{I}_{w}^{\mathrm{H}} \right\}\end{align*}$$
$$\begin{align*}\mathcal{B}_{w}^{\mathrm{H}}:=\left\{ \zeta(\mathfrak{s})|\mathfrak{s}\in \mathcal{I}_{w}^{\mathrm{H}} \right\}\end{align*}$$
is a basis of the 
 $\mathbb {Q}$
-vector space
$\mathbb {Q}$
-vector space 
 $\mathfrak {Z}_{w}$
.
$\mathfrak {Z}_{w}$
.
 We mention that Hoffman’s basis conjecture implies Zagier’s dimension conjecture. In [Reference Brown6], Brown proved Hoffman’s basis conjecture for motivic MZV’s. As there is a surjective map from motivic MZV’s to real MZV’s, Brown’s theorem implies that Hoffman’s conjectural basis would be a generating set for 
 $\mathfrak {Z}_{w}$
, and as a consequence, the upper bound result of Terasoma and Goncharov would be derived. Our main results in this paper are to prove the analogues of Conjecture 1.1 and Conjecture 1.2 and give precise generators of all linear relations among MZV’s in positive characteristic.
$\mathfrak {Z}_{w}$
, and as a consequence, the upper bound result of Terasoma and Goncharov would be derived. Our main results in this paper are to prove the analogues of Conjecture 1.1 and Conjecture 1.2 and give precise generators of all linear relations among MZV’s in positive characteristic.
1.2 The main results
 In the positive characteristic setting, we let 
 $A:=\mathbb {F}_{q}[\theta ]$
 be the polynomial ring in the variable
$A:=\mathbb {F}_{q}[\theta ]$
 be the polynomial ring in the variable 
 $\theta $
 over a finite field
$\theta $
 over a finite field 
 $\mathbb {F}_{q}$
 of q elements, where q is a power of a prime number p. We let k be the field of fractions of A and
$\mathbb {F}_{q}$
 of q elements, where q is a power of a prime number p. We let k be the field of fractions of A and 
 $|\cdot |_{\infty }$
 be the normalized absolute value on k at the infinite place
$|\cdot |_{\infty }$
 be the normalized absolute value on k at the infinite place 
 $\infty $
 of k for which
$\infty $
 of k for which 
 $|\theta |_{\infty }=q$
. Let
$|\theta |_{\infty }=q$
. Let 
 $k_{\infty }:={\mathbb {F}_{q} (\!( 1/\theta )\!)}$
 be the completion of k with respect to
$k_{\infty }:={\mathbb {F}_{q} (\!( 1/\theta )\!)}$
 be the completion of k with respect to 
 $|\cdot |_{\infty }$
. We then fix an algebraic closure
$|\cdot |_{\infty }$
. We then fix an algebraic closure 
 $\overline {k_{\infty }}$
 of
$\overline {k_{\infty }}$
 of 
 $k_{\infty }$
 and still denote by
$k_{\infty }$
 and still denote by 
 $|\cdot |_{\infty }$
 the extended absolute value on
$|\cdot |_{\infty }$
 the extended absolute value on 
 $\overline {k_{\infty }}$
. We let
$\overline {k_{\infty }}$
. We let 
 $\mathbb {C}_{\infty }$
 be the completion of
$\mathbb {C}_{\infty }$
 be the completion of 
 $\overline {k_{\infty }}$
 with respect to
$\overline {k_{\infty }}$
 with respect to 
 $|\cdot |_{\infty }$
. Finally, we let
$|\cdot |_{\infty }$
. Finally, we let 
 $\overline {k}$
 be the algebraic closure of k inside
$\overline {k}$
 be the algebraic closure of k inside 
 $\mathbb {C}_{\infty }.$
$\mathbb {C}_{\infty }.$
 Let 
 $A_{+}$
 be the set of monic polynomials of A, which plays an analogous role to the set of positive integers now in the function field setting. In [Reference Thakur31], Thakur introduced the following positive characteristic MZV’s: for any r-tuple of positive integers
$A_{+}$
 be the set of monic polynomials of A, which plays an analogous role to the set of positive integers now in the function field setting. In [Reference Thakur31], Thakur introduced the following positive characteristic MZV’s: for any r-tuple of positive integers 
 $\mathfrak {s}=(s_{1},\ldots ,s_{r})\in \mathbb {Z}_{>0}^{r}$
,
$\mathfrak {s}=(s_{1},\ldots ,s_{r})\in \mathbb {Z}_{>0}^{r}$
, 
 $$ \begin{align} \zeta_{A}(\mathfrak{s}):=\sum_{a_{1},\cdots, a_{r}\in A_{+}} \frac{1 }{a_{1}^{s_{1}} \cdots a_{r}^{s_{r}} } \in k_{\infty} \end{align} $$
$$ \begin{align} \zeta_{A}(\mathfrak{s}):=\sum_{a_{1},\cdots, a_{r}\in A_{+}} \frac{1 }{a_{1}^{s_{1}} \cdots a_{r}^{s_{r}} } \in k_{\infty} \end{align} $$
with the restriction that 
 $|a_{1}|_{\infty }>\cdots >|a_{r}|_{\infty }$
. As our absolute value
$|a_{1}|_{\infty }>\cdots >|a_{r}|_{\infty }$
. As our absolute value 
 $|\cdot |_{\infty }$
 is non-archimedean, the series
$|\cdot |_{\infty }$
 is non-archimedean, the series 
 $\zeta _{A}(\mathfrak {s})$
 converges in
$\zeta _{A}(\mathfrak {s})$
 converges in 
 $k_{\infty }$
. However, Thakur [Reference Thakur32] showed that such series are in fact non-vanishing. The weight and the depth of the presentation
$k_{\infty }$
. However, Thakur [Reference Thakur32] showed that such series are in fact non-vanishing. The weight and the depth of the presentation 
 $\zeta _{A}(\mathfrak {s})$
 are defined to be
$\zeta _{A}(\mathfrak {s})$
 are defined to be 
 $\operatorname {\mathrm {wt}}(\mathfrak {s}):=\sum _{i=1}^{r}s_{i}$
 and
$\operatorname {\mathrm {wt}}(\mathfrak {s}):=\sum _{i=1}^{r}s_{i}$
 and 
 $\operatorname {\mathrm {dep}}(\mathfrak {s}):=r$
, respectively. When
$\operatorname {\mathrm {dep}}(\mathfrak {s}):=r$
, respectively. When 
 $\operatorname {\mathrm {dep}}(\mathfrak {s})=1$
, these values are now called Carlitz zeta values, as their study was initiated by Carlitz in [Reference Carlitz8].
$\operatorname {\mathrm {dep}}(\mathfrak {s})=1$
, these values are now called Carlitz zeta values, as their study was initiated by Carlitz in [Reference Carlitz8].
 As from now on, we focus on MZV’s in positive characteristic; in what follows, MZV’s will be Thakur’s (
 $\infty $
-adic) MZV’s. In [Reference Thakur34], Thakur established a product on MZV’s, which is called q-shuffle relation in this paper. Namely, the product of two MZV’s can be expressed as an
$\infty $
-adic) MZV’s. In [Reference Thakur34], Thakur established a product on MZV’s, which is called q-shuffle relation in this paper. Namely, the product of two MZV’s can be expressed as an 
 $\mathbb {F}_{p}$
-linear combination of MZV’s whose weights are the same. It follows that the k-vector space
$\mathbb {F}_{p}$
-linear combination of MZV’s whose weights are the same. It follows that the k-vector space 
 $\mathcal {Z}$
 spanned by all MZV’s forms an algebra.
$\mathcal {Z}$
 spanned by all MZV’s forms an algebra.
 Note that 
 $\overline {k}$
-algebraic relations among MZV’s are
$\overline {k}$
-algebraic relations among MZV’s are 
 $\overline {k}$
-linear relations among monomials of MZV’s, which can be expressed as
$\overline {k}$
-linear relations among monomials of MZV’s, which can be expressed as 
 $\overline {k}$
-linear relations among MZV’s by q-shuffle relations mentioned above. In [Reference Chang9], the first named author of the present paper proved that all
$\overline {k}$
-linear relations among MZV’s by q-shuffle relations mentioned above. In [Reference Chang9], the first named author of the present paper proved that all 
 $\overline {k}$
-linear relations come from k-linear relations among MZV’s of the same weight. Therefore, determination of the dimension of the k-vector space of MZV’s of weight w for
$\overline {k}$
-linear relations come from k-linear relations among MZV’s of the same weight. Therefore, determination of the dimension of the k-vector space of MZV’s of weight w for 
 $w\in \mathbb {Z}_{>0}$
 is the central problem in this topic. Via numerical computation, Todd [Reference Todd30] provided the following analogue of Zagier’s dimension conjecture.
$w\in \mathbb {Z}_{>0}$
 is the central problem in this topic. Via numerical computation, Todd [Reference Todd30] provided the following analogue of Zagier’s dimension conjecture.
Conjecture 1.3 (Todd’s dimension conjecture).
 For any positive integer w, let 
 $\mathcal {Z}_{w}$
 be the k-vector space spanned by all MZV’s of weight w. Define
$\mathcal {Z}_{w}$
 be the k-vector space spanned by all MZV’s of weight w. Define 
 $$\begin{align*}d_{w}' = \begin{cases} 2^{w-1} & \text{if}\ 1\leq w < q, \\ 2^{q-1}-1 & \text{if}\ w=q,\\ \sum_{i=1}^{q} d^\prime_{w-i} & \text{if}\ w>q. \end{cases} \end{align*}$$
$$\begin{align*}d_{w}' = \begin{cases} 2^{w-1} & \text{if}\ 1\leq w < q, \\ 2^{q-1}-1 & \text{if}\ w=q,\\ \sum_{i=1}^{q} d^\prime_{w-i} & \text{if}\ w>q. \end{cases} \end{align*}$$
Then one has
 $$\begin{align*}\dim_{k} \mathcal{Z}_{w}=d_{w}'.\end{align*}$$
$$\begin{align*}\dim_{k} \mathcal{Z}_{w}=d_{w}'.\end{align*}$$
In analogy with Hoffman’s basis conjecture, Thakur [Reference Thakur35] proposed the following conjecture.
Conjecture 1.4 (Thakur’s basis conjecture).
 Let w be a positive integer and let 
 $\mathcal {I}^{\mathrm {T}}_{w}$
 be the set consisting of all
$\mathcal {I}^{\mathrm {T}}_{w}$
 be the set consisting of all 
 $\mathfrak {s}= (s_{1}, \ldots , s_{r} )\in \mathbb {Z}_{>0}^{r}$
 (varying positive integers r) for which
$\mathfrak {s}= (s_{1}, \ldots , s_{r} )\in \mathbb {Z}_{>0}^{r}$
 (varying positive integers r) for which 
- 
•  $\operatorname {\mathrm {wt}}(\mathfrak {s})=w$
; $\operatorname {\mathrm {wt}}(\mathfrak {s})=w$
;
- 
•  $s_{i} \leq q$
 for all $s_{i} \leq q$
 for all $1 \leq i \leq r - 1$
; $1 \leq i \leq r - 1$
;
- 
•  $s_{r}<q$
. $s_{r}<q$
.
Then the following set
 $$\begin{align*}\mathcal{B}_{w}^{\mathrm{T}}:=\left\{\zeta_{A}(\mathfrak{s})| \mathfrak{s}\in \mathcal{I}^{\mathrm{T}}_{w} \right\} \end{align*}$$
$$\begin{align*}\mathcal{B}_{w}^{\mathrm{T}}:=\left\{\zeta_{A}(\mathfrak{s})| \mathfrak{s}\in \mathcal{I}^{\mathrm{T}}_{w} \right\} \end{align*}$$
is a basis of the k-vector space 
 $\mathcal {Z}_{w}$
.
$\mathcal {Z}_{w}$
.
 We mention that for every positive integer w, the cardinality of 
 $\mathcal {I}^{\mathrm {T}}_w$
 is equal to
$\mathcal {I}^{\mathrm {T}}_w$
 is equal to 
 $d_{w}'$
 given in Conjecture 1.3. It follows that as in the classical case, Thakur’s basis conjecture implies Todd’s dimension conjecture. The main result of this paper is to prove Thakur’s basis conjecture.
$d_{w}'$
 given in Conjecture 1.3. It follows that as in the classical case, Thakur’s basis conjecture implies Todd’s dimension conjecture. The main result of this paper is to prove Thakur’s basis conjecture.
Theorem 1.5. For any positive integer w, Conjecture 1.4 is true. As a consequence, Conjecture 1.3 is also true.
 As we have determined the dimension of 
 $\mathcal {Z}_{w}$
 for each
$\mathcal {Z}_{w}$
 for each 
 $w\in \mathbb {N}$
, it is a natural question about how to describe all the k-linear relations among the MZV’s of weight w. We establish a concrete and simple mechanism in Theorem 5.3 that (5.3) accounts for all the k-linear relations. Note that Theorem 5.3 basically verifies the
$w\in \mathbb {N}$
, it is a natural question about how to describe all the k-linear relations among the MZV’s of weight w. We establish a concrete and simple mechanism in Theorem 5.3 that (5.3) accounts for all the k-linear relations. Note that Theorem 5.3 basically verifies the 
 $\mathscr {B}^{*}$
-version of [Reference Todd30, Conjecture 5.1].
$\mathscr {B}^{*}$
-version of [Reference Todd30, Conjecture 5.1].
Remark 1.6. In [Reference Ngo Dac26], Ngo Dac showed that for each 
 $w\geq 1$
,
$w\geq 1$
, 
 $\mathcal {B}_{w}^{\mathrm {T}}$
 is a generating set for the k-vector space
$\mathcal {B}_{w}^{\mathrm {T}}$
 is a generating set for the k-vector space 
 $\mathcal {Z}_{w}$
. As a consequence of Ngo Dac’s result, one has the upper bound result:
$\mathcal {Z}_{w}$
. As a consequence of Ngo Dac’s result, one has the upper bound result: 
 $$\begin{align*}\dim_{w}\mathcal{Z}_{w}\leq d_{w}',\ \forall w\geq 1. \end{align*}$$
$$\begin{align*}\dim_{w}\mathcal{Z}_{w}\leq d_{w}',\ \forall w\geq 1. \end{align*}$$
Theoretically, to prove Thakur’s basis conjecture, it suffices to show that his conjectural basis is linearly independent over k. However, when developing our approaches in a unified framework, we reprove Ngo Dac’s result mentioned above in Corollary 3.7, which also provides a generating set for the k-vector space spanned by the special values 
 $\operatorname {\mathrm {Li}}_{\mathfrak {s}}(\mathbf {1})$
 for all indices
$\operatorname {\mathrm {Li}}_{\mathfrak {s}}(\mathbf {1})$
 for all indices 
 $\mathfrak {s}$
 with
$\mathfrak {s}$
 with 
 $\operatorname {\mathrm {wt}}(\mathfrak {s})=w$
 and which is described in the next section.
$\operatorname {\mathrm {wt}}(\mathfrak {s})=w$
 and which is described in the next section.
Remark 1.7. As mentioned above, by [Reference Chang9], k-linear independence of MZV’s implies 
 $\overline {k}$
-linear independence. It follows that for each positive integer w,
$\overline {k}$
-linear independence. It follows that for each positive integer w, 
 $\mathcal {B}_{w}^{\mathrm {T}}$
 is also a basis for the
$\mathcal {B}_{w}^{\mathrm {T}}$
 is also a basis for the 
 $\overline {k}$
-vector space spanned by the MZV’s of weight w.
$\overline {k}$
-vector space spanned by the MZV’s of weight w.
 Given a finite place v of k, we mention that v-adic MZV’s 
 $\zeta _{A}(\mathfrak {s})_{v}$
 were introduced in [Reference Chang and Mishiba13] for
$\zeta _{A}(\mathfrak {s})_{v}$
 were introduced in [Reference Chang and Mishiba13] for 
 $\mathfrak {s}\in \mathbb {Z}_{>0}^{r}$
. By [Reference Chang and Mishiba13, Thm. 1.2.2], there is a natural k-linear map from (
$\mathfrak {s}\in \mathbb {Z}_{>0}^{r}$
. By [Reference Chang and Mishiba13, Thm. 1.2.2], there is a natural k-linear map from (
 $\infty $
-adic) MZV’s to v-adic MZV’s, and it was further shown in [Reference Chang, Chen and Mishiba11] that the map is indeed an algebra homomorphism with kernel containing the ideal generated by
$\infty $
-adic) MZV’s to v-adic MZV’s, and it was further shown in [Reference Chang, Chen and Mishiba11] that the map is indeed an algebra homomorphism with kernel containing the ideal generated by 
 $\zeta _{A}(q-1)$
 since
$\zeta _{A}(q-1)$
 since 
 $\zeta _{A}(q - 1)_{v} = 0$
 by [Reference Goss19]. As a consequence of Theorem 1.5, we have the following upper bound result for v-adic MZV’s.
$\zeta _{A}(q - 1)_{v} = 0$
 by [Reference Goss19]. As a consequence of Theorem 1.5, we have the following upper bound result for v-adic MZV’s.
Corollary 1.8. Let v be a finite place of k. For a positive integer w, we let 
 $\mathcal {Z}_{v,w}$
 be the
$\mathcal {Z}_{v,w}$
 be the 
 $\overline {k}$
-vector space space by v-adic MZV’s of weight w defined in [Reference Chang and Mishiba13]. Then we have
$\overline {k}$
-vector space space by v-adic MZV’s of weight w defined in [Reference Chang and Mishiba13]. Then we have 
 $$\begin{align*}\dim_{k} \mathcal{Z}_{v,w}\leq d_{w}'-d_{w-(q-1)}', \end{align*}$$
$$\begin{align*}\dim_{k} \mathcal{Z}_{v,w}\leq d_{w}'-d_{w-(q-1)}', \end{align*}$$
where 
 $d_{0}':=1$
 and
$d_{0}':=1$
 and 
 $d_{n}':=0$
 for
$d_{n}':=0$
 for 
 $n< 0$
.
$n< 0$
.
1.3 Strategy of proofs
 The key ingredient of our proof of Theorem 1.5 is to switch the study of MZV’s to that of the special values of Carlitz multiple polylogarithms (abbreviated as CMPL’s) 
 $\operatorname {\mathrm {Li}}_{\mathfrak {s}}$
 for
$\operatorname {\mathrm {Li}}_{\mathfrak {s}}$
 for 
 $\mathfrak {s}\in \mathbb {Z}_{>0}^{r}$
 defined by the first named author in [Reference Chang9]. For the definition of
$\mathfrak {s}\in \mathbb {Z}_{>0}^{r}$
 defined by the first named author in [Reference Chang9]. For the definition of 
 $\operatorname {\mathrm {Li}}_{\mathfrak {s}}$
, see (2.3). Note that CMPL’s are higher depth generalization of the Carlitz polylogarithms initiated by Anderson-Thakur [Reference Anderson and Thakur3]. Based on the interpolation formula of Anderson-Thakur [Reference Anderson and Thakur3, Reference Anderson and Thakur4], one knows from [Reference Chang9] that
$\operatorname {\mathrm {Li}}_{\mathfrak {s}}$
, see (2.3). Note that CMPL’s are higher depth generalization of the Carlitz polylogarithms initiated by Anderson-Thakur [Reference Anderson and Thakur3]. Based on the interpolation formula of Anderson-Thakur [Reference Anderson and Thakur3, Reference Anderson and Thakur4], one knows from [Reference Chang9] that 
 $\zeta _{A}(\mathfrak {s})$
 can be expressed as a k-linear combination of CMPL’s at some integral points, and in the particular case for
$\zeta _{A}(\mathfrak {s})$
 can be expressed as a k-linear combination of CMPL’s at some integral points, and in the particular case for 
 $\mathfrak {s} \in \mathcal {I}^{\mathrm {T}}_{w}$
, one has the simple identity (2.7) that
$\mathfrak {s} \in \mathcal {I}^{\mathrm {T}}_{w}$
, one has the simple identity (2.7) that 
 $$\begin{align*}\zeta_{A}(\mathfrak{s}) =\operatorname{\mathrm{Li}}_{\mathfrak{s}}(\mathbf{1}), \end{align*}$$
$$\begin{align*}\zeta_{A}(\mathfrak{s}) =\operatorname{\mathrm{Li}}_{\mathfrak{s}}(\mathbf{1}), \end{align*}$$
where 
 $\mathbf {1} := (1,\ldots ,1) \in \mathbb {Z}_{>0}^{\operatorname {\mathrm {dep}}(\mathfrak {s})}$
.
$\mathbf {1} := (1,\ldots ,1) \in \mathbb {Z}_{>0}^{\operatorname {\mathrm {dep}}(\mathfrak {s})}$
.
 Given a positive integer w, we let 
 $\mathcal {I}^{\mathrm {ND}}_{w}$
 be the set consisting of all tuples of positive integers
$\mathcal {I}^{\mathrm {ND}}_{w}$
 be the set consisting of all tuples of positive integers 
 $\mathfrak {s} = (s_{1}, \ldots , s_{r})$
 with
$\mathfrak {s} = (s_{1}, \ldots , s_{r})$
 with 
 $\operatorname {\mathrm {wt}}(\mathfrak {s})=w$
 and
$\operatorname {\mathrm {wt}}(\mathfrak {s})=w$
 and 
 $q \nmid s_{i}$
 for all
$q \nmid s_{i}$
 for all 
 $1 \leq i \leq r$
, and note that
$1 \leq i \leq r$
, and note that 
 $\mathcal {I}^{\mathrm {ND}}_{w}$
 was used and studied in [Reference Ngo Dac26]. The overall arguments in the proof of Theorem 1.5 are divided into the following two parts:
$\mathcal {I}^{\mathrm {ND}}_{w}$
 was used and studied in [Reference Ngo Dac26]. The overall arguments in the proof of Theorem 1.5 are divided into the following two parts: 
- 
(I) We show in Corollary 3.7 that the two sets  $ \mathcal {B}_{w}^{\operatorname {\mathrm {Li}},\mathrm {T}}:=\left \{\operatorname {\mathrm {Li}}_{\mathfrak {s}}(\mathbf {1}) | \mathfrak {s}\in \mathcal {I}^{\mathrm {T}}_{w} \right \}$
 and $ \mathcal {B}_{w}^{\operatorname {\mathrm {Li}},\mathrm {T}}:=\left \{\operatorname {\mathrm {Li}}_{\mathfrak {s}}(\mathbf {1}) | \mathfrak {s}\in \mathcal {I}^{\mathrm {T}}_{w} \right \}$
 and $\mathcal {B}_{w}^{T}$
 are generating sets of the k-vector space $\mathcal {B}_{w}^{T}$
 are generating sets of the k-vector space $\mathcal {Z}_{w}$
 for every positive integer w (the latter one was known by Ngo Dac [Reference Ngo Dac26]) and further show in Theorem 3.8 that the set $\mathcal {Z}_{w}$
 for every positive integer w (the latter one was known by Ngo Dac [Reference Ngo Dac26]) and further show in Theorem 3.8 that the set $\left \{ \operatorname {\mathrm {Li}}_{\mathfrak {s}}(\mathbf {1})| \mathfrak {s}\in \mathcal {I}^{\mathrm {ND}}_{w} \right \}$
 is a generating set for $\left \{ \operatorname {\mathrm {Li}}_{\mathfrak {s}}(\mathbf {1})| \mathfrak {s}\in \mathcal {I}^{\mathrm {ND}}_{w} \right \}$
 is a generating set for $\mathcal {Z}_{w}$
. $\mathcal {Z}_{w}$
.
- 
(II) We prove in Theorem 5.2 that  $\left \{ \operatorname {\mathrm {Li}}_{\mathfrak {s}}(\mathbf {1})| \mathfrak {s}\in \mathcal {I}^{\mathrm {ND}}_{w} \right \}$
 is a linearly independent set over k. Since $\left \{ \operatorname {\mathrm {Li}}_{\mathfrak {s}}(\mathbf {1})| \mathfrak {s}\in \mathcal {I}^{\mathrm {ND}}_{w} \right \}$
 is a linearly independent set over k. Since $|\mathcal {I}^{\mathrm {T}}_{w}|=|\mathcal {I}^{\mathrm {ND}}_{w}|$
 (see Proposition 2.1), it follows that $|\mathcal {I}^{\mathrm {T}}_{w}|=|\mathcal {I}^{\mathrm {ND}}_{w}|$
 (see Proposition 2.1), it follows that $\mathcal {B}_{w}^{T}$
 is a k-basis of $\mathcal {B}_{w}^{T}$
 is a k-basis of $\mathcal {Z}_{w}$
. $\mathcal {Z}_{w}$
.
 Regarding the part (I) above, we try to abstract and unify our methods to have a wide scope. We consider a formal k-space 
 $\mathcal {H}$
 generated by indices, on which the harmonic product
$\mathcal {H}$
 generated by indices, on which the harmonic product 
 $*^{\operatorname {\mathrm {Li}}}$
 and q-shuffle product
$*^{\operatorname {\mathrm {Li}}}$
 and q-shuffle product 
 $*^{\zeta }$
 are defined. We also consider the power/truncated sums maps arising from
$*^{\zeta }$
 are defined. We also consider the power/truncated sums maps arising from 
 $\operatorname {\mathrm {Li}}_{\mathfrak {s}}(\mathbf {1})$
 and
$\operatorname {\mathrm {Li}}_{\mathfrak {s}}(\mathbf {1})$
 and 
 $\zeta (\mathfrak {s})$
. We then define the maps
$\zeta (\mathfrak {s})$
. We then define the maps 
 $\mathscr {L}^{\operatorname {\mathrm {Li}}}, \mathscr {L}^{\zeta } \colon \mathcal {H}\rightarrow k_{\infty }$
 as the CMPL and MZV-realizations. These realizations preserve the harmonic product and q-shuffle product, respectively, illustrating the stuffle relations [Reference Chang9] for CMPL’s and the q-shuffle relations [Reference Thakur34, Reference Chen15] for MZV’s in a formal framework. See Theorem 2.7.
$\mathscr {L}^{\operatorname {\mathrm {Li}}}, \mathscr {L}^{\zeta } \colon \mathcal {H}\rightarrow k_{\infty }$
 as the CMPL and MZV-realizations. These realizations preserve the harmonic product and q-shuffle product, respectively, illustrating the stuffle relations [Reference Chang9] for CMPL’s and the q-shuffle relations [Reference Thakur34, Reference Chen15] for MZV’s in a formal framework. See Theorem 2.7.
 Then we adopt the ideas and methods rooted in [Reference Todd30, Reference Ngo Dac26] to achieve Theorem 3.6, which enables us to show the results mentioned in (I). Since some essential arguments are from those in [Reference Ngo Dac26], we leave the detailed proofs in the appendix. However, under such abstraction, the maps 
 $\mathscr {U}^{\bullet }$
 given in Definition 3.4 are explicit. In particular, Theorem 3.6 (2) allows us to provide a concrete and effective way to express
$\mathscr {U}^{\bullet }$
 given in Definition 3.4 are explicit. In particular, Theorem 3.6 (2) allows us to provide a concrete and effective way to express 
 $\operatorname {\mathrm {Li}}_{\mathfrak {s}}(\mathbf {1})$
 (resp.
$\operatorname {\mathrm {Li}}_{\mathfrak {s}}(\mathbf {1})$
 (resp. 
 $\zeta _{A}(\mathfrak {s})$
) as linear combinations in terms of
$\zeta _{A}(\mathfrak {s})$
) as linear combinations in terms of 
 $\mathcal {B}_{w}^{\operatorname {\mathrm {Li}},\mathrm {T}}$
 (resp.
$\mathcal {B}_{w}^{\operatorname {\mathrm {Li}},\mathrm {T}}$
 (resp. 
 $\mathcal {B}_{w}^{T}$
) simultaneously. This is more concrete and explicit than those developed in [Reference Ngo Dac26] and enables us to establish a simple mechanism in Theorem 5.3 that generates all the k-linear relations among MZV’s of the same weight (cf. the
$\mathcal {B}_{w}^{T}$
) simultaneously. This is more concrete and explicit than those developed in [Reference Ngo Dac26] and enables us to establish a simple mechanism in Theorem 5.3 that generates all the k-linear relations among MZV’s of the same weight (cf. the 
 $\mathscr {B}^{*}$
-version of [Reference Todd30, Conjecture 5.1]).
$\mathscr {B}^{*}$
-version of [Reference Todd30, Conjecture 5.1]).
Concerning the second part (II), the primary tool that we use is the Anderson-Brownawell-Papanikolas criterion [Reference Anderson, Brownawell and Papanikolas2, Thm. 3.1.1] (abbreviated as ABP-criterion), which has very strong applications in transcendence theory in positive characteristic. We prove (II) by induction on w. We start with a linear equation
 $$ \begin{align} \sum_{\mathfrak{s}\in \mathcal{I}^{\mathrm{ND}}_{w} }\alpha_{\mathfrak{s}}(\theta) \operatorname{\mathrm{Li}}_{\mathfrak{s}}(\mathbf{1})=0,\ \text{ for } \alpha_{\mathfrak{s}}=\alpha_{\mathfrak{s}}(t)\in \mathbb{F}_{q}(t), \ \forall \mathfrak{s}\in \mathcal{I}^{\mathrm{ND}}_{w} \end{align} $$
$$ \begin{align} \sum_{\mathfrak{s}\in \mathcal{I}^{\mathrm{ND}}_{w} }\alpha_{\mathfrak{s}}(\theta) \operatorname{\mathrm{Li}}_{\mathfrak{s}}(\mathbf{1})=0,\ \text{ for } \alpha_{\mathfrak{s}}=\alpha_{\mathfrak{s}}(t)\in \mathbb{F}_{q}(t), \ \forall \mathfrak{s}\in \mathcal{I}^{\mathrm{ND}}_{w} \end{align} $$
and aim to show that 
 $\alpha _{\mathfrak {s}}=0$
 for all
$\alpha _{\mathfrak {s}}=0$
 for all 
 $\mathfrak {s}\in \mathcal {I}^{\mathrm {ND}}_{w}$
. We outline our arguments as below.
$\mathfrak {s}\in \mathcal {I}^{\mathrm {ND}}_{w}$
. We outline our arguments as below. 
- 
(II-1) Using the period interpretation [Reference Chang9, (3.4.5)] for special values of CMPL’s (inspired by [Reference Anderson and Thakur4] for MZV’s), we can construct a system of difference equations  $\widetilde {\psi }^{(-1)}=\widetilde {\Phi } \widetilde {\psi }$
 fitting into the conditions of ABP-criterion for which (1.2) can be expressed as a k-linear identity among the entries of $\widetilde {\psi }^{(-1)}=\widetilde {\Phi } \widetilde {\psi }$
 fitting into the conditions of ABP-criterion for which (1.2) can be expressed as a k-linear identity among the entries of $\widetilde {\psi }(\theta )$
. We then apply the arguments in the proof of [Reference Chang, Papanikolas and Yu14, Thm. 2.5.2], and eventually we obtain the big system of Frobenius difference equations (E
w
), which is essentially from [Reference Chang, Papanikolas and Yu14, (3.1.3)]. $\widetilde {\psi }(\theta )$
. We then apply the arguments in the proof of [Reference Chang, Papanikolas and Yu14, Thm. 2.5.2], and eventually we obtain the big system of Frobenius difference equations (E
w
), which is essentially from [Reference Chang, Papanikolas and Yu14, (3.1.3)].
- 
(II-2) Denote by  $\mathscr {X}_{w}$
 the $\mathscr {X}_{w}$
 the $\mathbb {F}_{q}(t)$
-vector space of the solution space of (E
w
). We then show in Theorem 4.8 that $\mathbb {F}_{q}(t)$
-vector space of the solution space of (E
w
). We then show in Theorem 4.8 that $\dim _{\mathbb {F}_{q}(t)}\mathscr {X}_{w}$
 is either $\dim _{\mathbb {F}_{q}(t)}\mathscr {X}_{w}$
 is either $1$
 if $1$
 if $(q-1) \mid w$
 or $(q-1) \mid w$
 or $0$
 if $0$
 if $(q-1) \nmid w$
. $(q-1) \nmid w$
.
- 
(II-3) Using the trick of [Reference Chang9, Reference Chang, Papanikolas and Yu14] together with the induction hypothesis, we establish Lemma 5.1. By the first part of Lemma 5.1, we see that if  $\alpha _{\mathfrak {s}} \neq 0$
, then $\alpha _{\mathfrak {s}} \neq 0$
, then $\mathfrak {s}$
 must be in $\mathfrak {s}$
 must be in $\mathcal {I}^{\mathrm {ND}_{0}}_{w}$
, which is given in (4.1). Then we apply Lemma 5.1 (2) to conclude that there exists $\mathcal {I}^{\mathrm {ND}_{0}}_{w}$
, which is given in (4.1). Then we apply Lemma 5.1 (2) to conclude that there exists $(\varepsilon _{\mathfrak {s}})\in \mathscr {X}_w$
 for which $(\varepsilon _{\mathfrak {s}})\in \mathscr {X}_w$
 for which $\alpha _{\mathfrak {s}}=\varepsilon _{\mathfrak {s}}$
 for all $\alpha _{\mathfrak {s}}=\varepsilon _{\mathfrak {s}}$
 for all $\mathfrak {s} \in \mathcal {I}^{\mathrm {ND}_{0}}_{w}$
. Note that the description of indices in $\mathfrak {s} \in \mathcal {I}^{\mathrm {ND}_{0}}_{w}$
. Note that the description of indices in $\mathcal {I}^{\mathrm {ND}_{0}}_{w}$
 arises from the simultaneously Eulerian phenomenon in [Reference Chang, Papanikolas and Yu14, Cor. 4.2.3], which was first witnessed by Lara Rodríguez and Thakur in [Reference Lara Rodríguez and Thakur25]. $\mathcal {I}^{\mathrm {ND}_{0}}_{w}$
 arises from the simultaneously Eulerian phenomenon in [Reference Chang, Papanikolas and Yu14, Cor. 4.2.3], which was first witnessed by Lara Rodríguez and Thakur in [Reference Lara Rodríguez and Thakur25].
- 
(II-4) When  $(q - 1) \nmid w$
, we use the fact of this case that $(q - 1) \nmid w$
, we use the fact of this case that $\mathscr {X}_{w}=0$
 to conclude that $\mathscr {X}_{w}=0$
 to conclude that $\varepsilon _{\mathfrak {s}}=0$
 for every $\varepsilon _{\mathfrak {s}}=0$
 for every $\mathfrak {s}$
, and hence $\mathfrak {s}$
, and hence $\alpha _{\mathfrak {s}}(\theta )=0$
 for every $\alpha _{\mathfrak {s}}(\theta )=0$
 for every $\mathfrak {s}$
. When $\mathfrak {s}$
. When $(q-1) \mid w$
, we apply Theorem 3.8 together with the fact of this case that $(q-1) \mid w$
, we apply Theorem 3.8 together with the fact of this case that $\dim _{\mathbb {F}_{q}(t)}\mathscr {X}_{w}=1$
. Having one trick further in the proof of Theorem 5.2 shows that $\dim _{\mathbb {F}_{q}(t)}\mathscr {X}_{w}=1$
. Having one trick further in the proof of Theorem 5.2 shows that $\alpha _{\mathfrak {s}}(\theta )=0$
 for every $\alpha _{\mathfrak {s}}(\theta )=0$
 for every $\mathfrak {s}$
. $\mathfrak {s}$
.
Remark 1.9. The above is the overall strategy of our proof. However, to save some length without affecting logical arguments, we avoid many details in (II-1). Instead, we directly go to (1.2) in this paper.
1.4 Organization of the paper
 In Section 2.1, we introduce the abstract k-vector space 
 $\mathcal {H}$
, on which the harmonic product
$\mathcal {H}$
, on which the harmonic product 
 $*^{\operatorname {\mathrm {Li}}}$
 and q-shuffle product
$*^{\operatorname {\mathrm {Li}}}$
 and q-shuffle product 
 $*^{\zeta }$
 are defined. The purpose of Section 2.1 is to derive the product formulae, stated as Proposition 2.7, for the CMPL and MZV realizations
$*^{\zeta }$
 are defined. The purpose of Section 2.1 is to derive the product formulae, stated as Proposition 2.7, for the CMPL and MZV realizations 
 $\mathscr {L}^{\operatorname {\mathrm {Li}}}$
 and
$\mathscr {L}^{\operatorname {\mathrm {Li}}}$
 and 
 $\mathscr {L}^{\zeta }$
. In Section 3, we follow [Reference Todd30, Reference Ngo Dac26] to transfer their
$\mathscr {L}^{\zeta }$
. In Section 3, we follow [Reference Todd30, Reference Ngo Dac26] to transfer their 
 $\mathscr {B}, \mathscr {C}, \mathscr {BC}$
 maps into our formal framework in a concrete way. The primary result of this section is to establish Theorem 3.8, which is an application of Theorem 3.6, whose detailed proof is given in the appendix.
$\mathscr {B}, \mathscr {C}, \mathscr {BC}$
 maps into our formal framework in a concrete way. The primary result of this section is to establish Theorem 3.8, which is an application of Theorem 3.6, whose detailed proof is given in the appendix.
 We study the specific system of Frobenius difference equations (E
w
) mentioned in the (II) above in Section 4. We carefully analyze the solution space 
 $\mathscr {X}_{w}$
 of (E
w
), and determine its dimension in Theorem 4.8. In Section 5, we establish the key Lemma 5.1, which is used to prove the k-linear independence of
$\mathscr {X}_{w}$
 of (E
w
), and determine its dimension in Theorem 4.8. In Section 5, we establish the key Lemma 5.1, which is used to prove the k-linear independence of 
 $\left \{ \operatorname {\mathrm {Li}}_{\mathfrak {s}}(\mathbf {1})| \mathfrak {s}\in \mathcal {I}^{\mathrm {ND}}_{w} \right \}$
 in Theorem 5.2. With these results at hand, we prove Theorem 1.5 in Section 5.3 as a short conclusion. Finally, combining Theorems 3.6 and 1.5, we give a proof of Theorem 5.3 in Section 5.4. As mentioned above, the appendix consists of a detailed proof of Theorem 3.6.
$\left \{ \operatorname {\mathrm {Li}}_{\mathfrak {s}}(\mathbf {1})| \mathfrak {s}\in \mathcal {I}^{\mathrm {ND}}_{w} \right \}$
 in Theorem 5.2. With these results at hand, we prove Theorem 1.5 in Section 5.3 as a short conclusion. Finally, combining Theorems 3.6 and 1.5, we give a proof of Theorem 5.3 in Section 5.4. As mentioned above, the appendix consists of a detailed proof of Theorem 3.6.
Remark 1.10. When this paper was nearly in its final version, we announced our results of Theorem 1.5 to Thakur, and soon after, Ngo Dac sent his paper [Reference Im, Kim, Le, Ngo Dac and Pham22] to Thakur on the same day announcing that he and his coauthors show the same results for alternating MZV’s. Our paper was finished a few days later than theirs. The key strategy of their proofs is in the same direction as ours. They switch the study of alternating MZV’s to the k-vector space spanned by the following special values of CMPL’s:
 $$\begin{align*}\left\{ \operatorname{\mathrm{Li}}_{\mathfrak{s}} (\gamma_{1},\ldots,\gamma_{r} )| \mathfrak{s}\in \mathcal{I}^{\mathrm{T}}_{w},\ (\gamma_{1},\ldots,\gamma_{r} )\in (\mathbb{F}_{q^{q-1}}^{\times})^{r}\right\} .\end{align*}$$
$$\begin{align*}\left\{ \operatorname{\mathrm{Li}}_{\mathfrak{s}} (\gamma_{1},\ldots,\gamma_{r} )| \mathfrak{s}\in \mathcal{I}^{\mathrm{T}}_{w},\ (\gamma_{1},\ldots,\gamma_{r} )\in (\mathbb{F}_{q^{q-1}}^{\times})^{r}\right\} .\end{align*}$$
Note that any value in the set above is equal to an alternating MZV at 
 $\mathfrak {s}$
 up to an algebraic multiple (cf. [Reference Chen and Harada12, Prop. 2.12]). However, by the first author’s result [Reference Chang9, Thm. 5.4.3] showing that CMPL’s at algebraic points form a
$\mathfrak {s}$
 up to an algebraic multiple (cf. [Reference Chen and Harada12, Prop. 2.12]). However, by the first author’s result [Reference Chang9, Thm. 5.4.3] showing that CMPL’s at algebraic points form a 
 $\overline {k}$
-graded algebra defined over k, one can remove the algebraic factor without affecting the study for the k-vector space of alternating MZV’s. We find that some directions of our ideas and theirs are similar and the primary methods rooted in [Reference Anderson, Brownawell and Papanikolas2, Reference Chang9, Reference Todd30, Reference Chang, Papanikolas and Yu14, Reference Ngo Dac26] are the same, but presentations and detailed arguments are different. However, we prove Theorem 5.3 explicitly describing all k-linear relations among MZV’s, but there is no such a result proved in [Reference Im, Kim, Le, Ngo Dac and Pham22].
$\overline {k}$
-graded algebra defined over k, one can remove the algebraic factor without affecting the study for the k-vector space of alternating MZV’s. We find that some directions of our ideas and theirs are similar and the primary methods rooted in [Reference Anderson, Brownawell and Papanikolas2, Reference Chang9, Reference Todd30, Reference Chang, Papanikolas and Yu14, Reference Ngo Dac26] are the same, but presentations and detailed arguments are different. However, we prove Theorem 5.3 explicitly describing all k-linear relations among MZV’s, but there is no such a result proved in [Reference Im, Kim, Le, Ngo Dac and Pham22].
2 Two products on 
 $\mathcal {H}$
$\mathcal {H}$
2.1 Indices
 By an index, we mean the empty set 
 $\emptyset $
 or an r-tuple of positive integers
$\emptyset $
 or an r-tuple of positive integers 
 $\mathfrak {s}=(s_{1},\ldots ,s_{r})$
. In the former case, its depth and weight are defined to be
$\mathfrak {s}=(s_{1},\ldots ,s_{r})$
. In the former case, its depth and weight are defined to be 
 $\operatorname {\mathrm {dep}}(\emptyset )=0$
 and
$\operatorname {\mathrm {dep}}(\emptyset )=0$
 and 
 $\operatorname {\mathrm {wt}}(\emptyset )=0$
. The depth and weight of the latter case are defined to be
$\operatorname {\mathrm {wt}}(\emptyset )=0$
. The depth and weight of the latter case are defined to be 
 $\operatorname {\mathrm {dep}}(\mathfrak {s})=r$
 and
$\operatorname {\mathrm {dep}}(\mathfrak {s})=r$
 and 
 $\operatorname {\mathrm {wt}}(\mathfrak {s})=\sum _{i=1}^{r}s_{i}$
, respectively. We denote by
$\operatorname {\mathrm {wt}}(\mathfrak {s})=\sum _{i=1}^{r}s_{i}$
, respectively. We denote by 
 $\mathcal {I} := \bigsqcup _{r \geq 0} \mathbb {Z}_{> 0}^{r}$
 the set of indices, where
$\mathcal {I} := \bigsqcup _{r \geq 0} \mathbb {Z}_{> 0}^{r}$
 the set of indices, where 
 $\mathbb {Z}_{> 0}^{0} := \{\emptyset \}$
.
$\mathbb {Z}_{> 0}^{0} := \{\emptyset \}$
.
Throughout this paper, we adapt the following notations.
 $$ \begin{align*} \mathcal{I}_{w} &:= \{ \mathfrak{n} \in \mathcal{I} \ | \ \operatorname{\mathrm{wt}}(\mathfrak{n}) = w \} \ \ (w \geq 0), \\ \mathcal{I}_{> 0} &:= \{ \mathfrak{n} \in \mathcal{I} \ | \ \operatorname{\mathrm{wt}}(\mathfrak{n}) > 0 \} = \mathcal{I} \setminus \{ \emptyset \}, \\ \mathcal{I}^{\mathrm{T}}_{w} &:= \{ (s_{1}, \ldots, s_{r} ) \in \mathcal{I}_{w} \ | \ s_{i} \leq q \ (1 \leq \forall i \leq r - 1) \ \mathrm{and} \ s_{r} < q \} \ \ (w> 0), \\ \mathcal{I}^{\mathrm{ND}}_{w} &:= \{ (s_{1}, \ldots, s_{r} ) \in \mathcal{I}_{w} \ | \ q \nmid s_{i} \ (1 \leq \forall i \leq r) \} \ \ (w > 0), \\ \mathcal{I}^{\mathrm{T}}_{0} &:= \mathcal{I}^{\mathrm{ND}}_{0} := \{ \emptyset \}. \end{align*} $$
$$ \begin{align*} \mathcal{I}_{w} &:= \{ \mathfrak{n} \in \mathcal{I} \ | \ \operatorname{\mathrm{wt}}(\mathfrak{n}) = w \} \ \ (w \geq 0), \\ \mathcal{I}_{> 0} &:= \{ \mathfrak{n} \in \mathcal{I} \ | \ \operatorname{\mathrm{wt}}(\mathfrak{n}) > 0 \} = \mathcal{I} \setminus \{ \emptyset \}, \\ \mathcal{I}^{\mathrm{T}}_{w} &:= \{ (s_{1}, \ldots, s_{r} ) \in \mathcal{I}_{w} \ | \ s_{i} \leq q \ (1 \leq \forall i \leq r - 1) \ \mathrm{and} \ s_{r} < q \} \ \ (w> 0), \\ \mathcal{I}^{\mathrm{ND}}_{w} &:= \{ (s_{1}, \ldots, s_{r} ) \in \mathcal{I}_{w} \ | \ q \nmid s_{i} \ (1 \leq \forall i \leq r) \} \ \ (w > 0), \\ \mathcal{I}^{\mathrm{T}}_{0} &:= \mathcal{I}^{\mathrm{ND}}_{0} := \{ \emptyset \}. \end{align*} $$
We mention that 
 $\mathcal {I}^{\mathrm {T}}_{w}$
 refers to the set of indexes arising from Thakur’s basis, and
$\mathcal {I}^{\mathrm {T}}_{w}$
 refers to the set of indexes arising from Thakur’s basis, and 
 $\mathcal {I}^{\mathrm {ND}}_{w}$
 is the set studied in [Reference Ngo Dac26]. For any subset S of
$\mathcal {I}^{\mathrm {ND}}_{w}$
 is the set studied in [Reference Ngo Dac26]. For any subset S of 
 $\mathcal {I}$
, we denote by
$\mathcal {I}$
, we denote by 
 $|S|$
 the cardinality of S when no confusions arise.
$|S|$
 the cardinality of S when no confusions arise.
Proposition 2.1. For each weight 
 $w\geq 0$
, we have a bijection between
$w\geq 0$
, we have a bijection between 
 $\mathcal {I}^{\mathrm {ND}}_{w}$
 and
$\mathcal {I}^{\mathrm {ND}}_{w}$
 and 
 $\mathcal {I}^{\mathrm {T}}_{w}$
, and hence,
$\mathcal {I}^{\mathrm {T}}_{w}$
, and hence, 
 $|\mathcal {I}^{\mathrm {ND}}_{w}|=|\mathcal {I}^{\mathrm {T}}_{w}|$
.
$|\mathcal {I}^{\mathrm {ND}}_{w}|=|\mathcal {I}^{\mathrm {T}}_{w}|$
.
Proof. The desired result follows from the following correspondence:
 $$ \begin{align*} (m_{1} q + n_{1}, \ldots, m_{r} q + n_{r}) \longleftrightarrow (q^{\{ m_{1} \}}, n_{1}, \ldots, q^{\{ m_{r} \}}, n_{r}) \ \ \ (m_{i} \geq 0, \ 1 \leq n_{i} \leq q - 1), \end{align*} $$
$$ \begin{align*} (m_{1} q + n_{1}, \ldots, m_{r} q + n_{r}) \longleftrightarrow (q^{\{ m_{1} \}}, n_{1}, \ldots, q^{\{ m_{r} \}}, n_{r}) \ \ \ (m_{i} \geq 0, \ 1 \leq n_{i} \leq q - 1), \end{align*} $$
where 
 $q^{\{m\}}$
 denotes the sequence
$q^{\{m\}}$
 denotes the sequence 
 $(q, \ldots , q) \in \mathbb {Z}_{> 0}^{m}$
. It is understood that in the case of
$(q, \ldots , q) \in \mathbb {Z}_{> 0}^{m}$
. It is understood that in the case of 
 $m=0$
,
$m=0$
, 
 $q^{\left \{0 \right \}}$
 is referred to the empty index
$q^{\left \{0 \right \}}$
 is referred to the empty index 
 $\emptyset $
.
$\emptyset $
.
 Given 
 $\ell $
 indices
$\ell $
 indices 
 $\mathfrak {s}_{1},\ldots ,\mathfrak {s}_{\ell } \in \mathcal {I}$
 with
$\mathfrak {s}_{1},\ldots ,\mathfrak {s}_{\ell } \in \mathcal {I}$
 with 
 $\mathfrak {s}_{i} = (s_{i1}, \ldots , s_{ir_{i}})$
 (
$\mathfrak {s}_{i} = (s_{i1}, \ldots , s_{ir_{i}})$
 (
 $1 \leq i \leq \ell $
), we define
$1 \leq i \leq \ell $
), we define 
 $$ \begin{align} (\mathfrak{s}_{1}, \ldots \mathfrak{s}_{\ell}) := (s_{11}, \ldots, s_{1r_{1}}, s_{21}, \ldots, s_{2r_{2}}, \ldots, s_{\ell 1}, \ldots, s_{\ell r_{\ell}}) \end{align} $$
$$ \begin{align} (\mathfrak{s}_{1}, \ldots \mathfrak{s}_{\ell}) := (s_{11}, \ldots, s_{1r_{1}}, s_{21}, \ldots, s_{2r_{2}}, \ldots, s_{\ell 1}, \ldots, s_{\ell r_{\ell}}) \end{align} $$
to be the index obtained by putting the given indices consecutively. For each nonempty index 
 $\mathfrak {s} = (s_{1}, \ldots , s_{r}) \in \mathcal {I}_{> 0}$
, we define
$\mathfrak {s} = (s_{1}, \ldots , s_{r}) \in \mathcal {I}_{> 0}$
, we define 
 $$ \begin{align} \mathfrak{s}_{+} := (s_{1}, \ldots, s_{r - 1}) \ \mathrm{and} \ \mathfrak{s}_{-} := (s_{2}, \ldots, s_{r}). \end{align} $$
$$ \begin{align} \mathfrak{s}_{+} := (s_{1}, \ldots, s_{r - 1}) \ \mathrm{and} \ \mathfrak{s}_{-} := (s_{2}, \ldots, s_{r}). \end{align} $$
In the depth one case, we note that 
 $\mathfrak {s}_{+}=\emptyset $
 and
$\mathfrak {s}_{+}=\emptyset $
 and 
 $\mathfrak {s}_{-}=\emptyset $
.
$\mathfrak {s}_{-}=\emptyset $
.
 Let 
 $\mathcal {H} = \bigoplus _{w \geq 0} \mathcal {H}_{w}$
 be the k-vector space with basis
$\mathcal {H} = \bigoplus _{w \geq 0} \mathcal {H}_{w}$
 be the k-vector space with basis 
 $\mathcal {I}$
 graded by weight and let
$\mathcal {I}$
 graded by weight and let 
 $\mathcal {H}_{> 0} := \bigoplus _{w > 0} \mathcal {H}_{w}$
. For each index
$\mathcal {H}_{> 0} := \bigoplus _{w > 0} \mathcal {H}_{w}$
. For each index 
 $\mathfrak {s} = (s_{1}, \ldots , s_{r}) \in \mathcal {I}$
, the corresponding generator in
$\mathfrak {s} = (s_{1}, \ldots , s_{r}) \in \mathcal {I}$
, the corresponding generator in 
 $\mathcal {H}$
 is denoted by
$\mathcal {H}$
 is denoted by 
 $[\mathfrak {s}] = [s_{1}, \ldots , s_{r}]$
 or
$[\mathfrak {s}] = [s_{1}, \ldots , s_{r}]$
 or 
 $\mathfrak {s}$
. For each
$\mathfrak {s}$
. For each 
 $P = \sum _{\mathfrak {s} \in \mathcal {I}} a_{\mathfrak {s}} [\mathfrak {s}] \in \mathcal {H}$
, the support of P is defined by
$P = \sum _{\mathfrak {s} \in \mathcal {I}} a_{\mathfrak {s}} [\mathfrak {s}] \in \mathcal {H}$
, the support of P is defined by 
 $$ \begin{align*} \operatorname{\mathrm{Supp}}(P) := \{ \mathfrak{s} \in \mathcal{I} \ | \ a_{\mathfrak{s}} \neq 0 \}. \end{align*} $$
$$ \begin{align*} \operatorname{\mathrm{Supp}}(P) := \{ \mathfrak{s} \in \mathcal{I} \ | \ a_{\mathfrak{s}} \neq 0 \}. \end{align*} $$
Definition 2.2. Given a positive integer 
 $\ell $
, we define the following k-multilinear map
$\ell $
, we define the following k-multilinear map 
 $$\begin{align*}[-,-, \ldots,-]:\mathcal{H}^{\oplus \ell}\rightarrow \mathcal{H} \end{align*}$$
$$\begin{align*}[-,-, \ldots,-]:\mathcal{H}^{\oplus \ell}\rightarrow \mathcal{H} \end{align*}$$
as follows. For any indices 
 $\mathfrak {s}_{1},\ldots ,\mathfrak {s}_{\ell }\in \mathcal {I}$
, let
$\mathfrak {s}_{1},\ldots ,\mathfrak {s}_{\ell }\in \mathcal {I}$
, let 
 $(\mathfrak {s}_{1},\ldots ,\mathfrak {s}_{\ell })$
 be given in (2.1). We define
$(\mathfrak {s}_{1},\ldots ,\mathfrak {s}_{\ell })$
 be given in (2.1). We define 
 $$\begin{align*}[\mathfrak{s}_{1},\ldots,\mathfrak{s}_{\ell}]:= [(\mathfrak{s}_{1},\ldots,\mathfrak{s}_{\ell})]\in \mathcal{H}. \end{align*}$$
$$\begin{align*}[\mathfrak{s}_{1},\ldots,\mathfrak{s}_{\ell}]:= [(\mathfrak{s}_{1},\ldots,\mathfrak{s}_{\ell})]\in \mathcal{H}. \end{align*}$$
Remark 2.3. As the map above is multilinear, for any 
 $\mathfrak {s}\in \mathcal {I}$
, we particularly have the following identity
$\mathfrak {s}\in \mathcal {I}$
, we particularly have the following identity 
 $$\begin{align*}[\mathfrak{s},0]=0\in \mathcal{H}, \end{align*}$$
$$\begin{align*}[\mathfrak{s},0]=0\in \mathcal{H}, \end{align*}$$
which will be used in the appendix. As 
 $\emptyset $
 is also an index by our definition, we mention that
$\emptyset $
 is also an index by our definition, we mention that 
 $$\begin{align*}[\mathfrak{s},\emptyset] \neq [\mathfrak{s},0]=0\in \mathcal{H}. \end{align*}$$
$$\begin{align*}[\mathfrak{s},\emptyset] \neq [\mathfrak{s},0]=0\in \mathcal{H}. \end{align*}$$
2.2 The maps 
 $\mathscr {L}^{\operatorname {\mathrm {Li}}}$
 and
$\mathscr {L}^{\operatorname {\mathrm {Li}}}$
 and 
 $\mathscr {L}^{\zeta }$
$\mathscr {L}^{\zeta }$
Recall that the Carlitz logarithm is given by
 $$\begin{align*}\log_{C}(z):=\sum_{d\geq 0} \frac{z^{q^{d}}}{L_{d}} \in {k [\![ z ]\!]} ,\end{align*}$$
$$\begin{align*}\log_{C}(z):=\sum_{d\geq 0} \frac{z^{q^{d}}}{L_{d}} \in {k [\![ z ]\!]} ,\end{align*}$$
where 
 $L_{0} := 1$
 and
$L_{0} := 1$
 and 
 $L_{d} := (\theta - \theta ^{q}) \cdots (\theta - \theta ^{q^{d}})$
 for
$L_{d} := (\theta - \theta ^{q}) \cdots (\theta - \theta ^{q^{d}})$
 for 
 $d \geq 1$
 (see [Reference Goss20, Reference Thakur31]), and the nth Carlitz polylogarithm defined by Anderson-Thakur [Reference Anderson and Thakur3] is the following power series:
$d \geq 1$
 (see [Reference Goss20, Reference Thakur31]), and the nth Carlitz polylogarithm defined by Anderson-Thakur [Reference Anderson and Thakur3] is the following power series: 
 $$\begin{align*}\operatorname{\mathrm{Li}}_{n}(z):= \sum_{d \geq 0}\frac{z^{q^{d}}}{L_{d}^{n}}\in {k [\![ z ]\!]}. \end{align*}$$
$$\begin{align*}\operatorname{\mathrm{Li}}_{n}(z):= \sum_{d \geq 0}\frac{z^{q^{d}}}{L_{d}^{n}}\in {k [\![ z ]\!]}. \end{align*}$$
For any index 
 $\mathfrak {s}=(s_{1},\ldots ,s_{r})\in \mathcal {I}_{>0}$
 of positive depth, the
$\mathfrak {s}=(s_{1},\ldots ,s_{r})\in \mathcal {I}_{>0}$
 of positive depth, the 
 $\mathfrak {s}$
th Carlitz multiple polylogarithm (abbreviated as CMPL) is given by the following series (see [Reference Chang9]):
$\mathfrak {s}$
th Carlitz multiple polylogarithm (abbreviated as CMPL) is given by the following series (see [Reference Chang9]): 
 $$ \begin{align} \operatorname{\mathrm{Li}}_{\mathfrak{s}}(z_{1},\ldots,z_{r}):=\sum_{d_{1}> \cdots > d_{r} \geq 0} \dfrac{z_{1}^{q^{d_1}} \cdots z_{r}^{q^{d_r}}}{L_{d_{1}}^{s_{1}} \cdots L_{d_{r}}^{s_{r}}}\in {k [\![ z_{1},\ldots,z_{r} ]\!]}. \end{align} $$
$$ \begin{align} \operatorname{\mathrm{Li}}_{\mathfrak{s}}(z_{1},\ldots,z_{r}):=\sum_{d_{1}> \cdots > d_{r} \geq 0} \dfrac{z_{1}^{q^{d_1}} \cdots z_{r}^{q^{d_r}}}{L_{d_{1}}^{s_{1}} \cdots L_{d_{r}}^{s_{r}}}\in {k [\![ z_{1},\ldots,z_{r} ]\!]}. \end{align} $$
 For each 
 $s \in \mathbb {Z}_{\geq 1}$
 and
$s \in \mathbb {Z}_{\geq 1}$
 and 
 $d \in \mathbb {Z}_{\geq 0}$
, we set
$d \in \mathbb {Z}_{\geq 0}$
, we set 
 $$ \begin{align*} S^{\operatorname{\mathrm{Li}}}_{d}(s) := \dfrac{1}{L_{d}^{s}}\in k \ \ \mathrm{and} \ \ S^{\zeta}_{d}(s) := \sum_{a \in A_{+, d}} \dfrac{1}{a^{d}}\in k, \end{align*} $$
$$ \begin{align*} S^{\operatorname{\mathrm{Li}}}_{d}(s) := \dfrac{1}{L_{d}^{s}}\in k \ \ \mathrm{and} \ \ S^{\zeta}_{d}(s) := \sum_{a \in A_{+, d}} \dfrac{1}{a^{d}}\in k, \end{align*} $$
where 
 $A_{+, d}$
 is the set of monic polynomials in A of degree d. We then define k-linear maps
$A_{+, d}$
 is the set of monic polynomials in A of degree d. We then define k-linear maps 
 $\mathscr {L}^{\bullet }_{d}$
,
$\mathscr {L}^{\bullet }_{d}$
, 
 $\mathscr {L}^{\bullet }_{< d}$
 and
$\mathscr {L}^{\bullet }_{< d}$
 and 
 $\mathscr {L}^{\bullet }$
 on
$\mathscr {L}^{\bullet }$
 on 
 $\mathcal {H}$
.
$\mathcal {H}$
.
Definition 2.4. Let 
 $\bullet \in \{ \operatorname {\mathrm {Li}}, \zeta \}$
 and
$\bullet \in \{ \operatorname {\mathrm {Li}}, \zeta \}$
 and 
 $d \in \mathbb {Z}$
.
$d \in \mathbb {Z}$
. 
- 
(1) The map  $\mathscr {L}^{\bullet }_{d} \colon \mathcal {H} \to k$
 is the k-linear map defined by (2.4) $\mathscr {L}^{\bullet }_{d} \colon \mathcal {H} \to k$
 is the k-linear map defined by (2.4) $$ \begin{align} \mathscr{L}^{\bullet}_{d}(\mathfrak{s}) := \left\{ \begin{array}{cl} {\displaystyle \sum_{d = d_{1}> \cdots > d_{r} \geq 0}} S^{\bullet}_{d_{1}}(s_{1}) \cdots S^{\bullet}_{d_{r}}(s_{r}) & (\mathfrak{s} = (s_{1}, \ldots, s_{r}) \in \mathcal{I}_{> 0} \ \mathrm{and} \ d \geq \operatorname{\mathrm{dep}}(\mathfrak{s}) - 1) \\ 1 & (\mathfrak{s} = \emptyset \ \mathrm{and} \ d = - 1) \\ 0 & (\mathrm{otherwise}) \end{array} \right. \end{align} $$ $$ \begin{align} \mathscr{L}^{\bullet}_{d}(\mathfrak{s}) := \left\{ \begin{array}{cl} {\displaystyle \sum_{d = d_{1}> \cdots > d_{r} \geq 0}} S^{\bullet}_{d_{1}}(s_{1}) \cdots S^{\bullet}_{d_{r}}(s_{r}) & (\mathfrak{s} = (s_{1}, \ldots, s_{r}) \in \mathcal{I}_{> 0} \ \mathrm{and} \ d \geq \operatorname{\mathrm{dep}}(\mathfrak{s}) - 1) \\ 1 & (\mathfrak{s} = \emptyset \ \mathrm{and} \ d = - 1) \\ 0 & (\mathrm{otherwise}) \end{array} \right. \end{align} $$
- 
(2) The map  $\mathscr {L}^{\bullet }_{< d} \colon \mathcal {H} \to k$
 is the k-linear map defined by (2.5) $\mathscr {L}^{\bullet }_{< d} \colon \mathcal {H} \to k$
 is the k-linear map defined by (2.5) $$ \begin{align} \mathscr{L}^{\bullet}_{< d}(\mathfrak{s}) := \left\{ \begin{array}{cl} {\displaystyle \sum_{d> d_{1} > \cdots > d_{r} \geq 0}} S^{\bullet}_{d_{1}}(s_{1}) \cdots S^{\bullet}_{d_{r}}(s_{r}) & (\mathfrak{s} = (s_{1}, \ldots, s_{r}) \in \mathcal{I}_{> 0} \ \mathrm{and} \ d \geq \operatorname{\mathrm{dep}}(\mathfrak{s})) \\ 1 & (\mathfrak{s} = \emptyset \ \mathrm{and} \ d \geq 0) \\ 0 & (\mathrm{otherwise}) \end{array} \right. \end{align} $$ $$ \begin{align} \mathscr{L}^{\bullet}_{< d}(\mathfrak{s}) := \left\{ \begin{array}{cl} {\displaystyle \sum_{d> d_{1} > \cdots > d_{r} \geq 0}} S^{\bullet}_{d_{1}}(s_{1}) \cdots S^{\bullet}_{d_{r}}(s_{r}) & (\mathfrak{s} = (s_{1}, \ldots, s_{r}) \in \mathcal{I}_{> 0} \ \mathrm{and} \ d \geq \operatorname{\mathrm{dep}}(\mathfrak{s})) \\ 1 & (\mathfrak{s} = \emptyset \ \mathrm{and} \ d \geq 0) \\ 0 & (\mathrm{otherwise}) \end{array} \right. \end{align} $$
- 
(3) The map  $\mathscr {L}^{\bullet } \colon \mathcal {H} \to k_{\infty }$
 is the k-linear map defined by (2.6) $\mathscr {L}^{\bullet } \colon \mathcal {H} \to k_{\infty }$
 is the k-linear map defined by (2.6) $$ \begin{align} \mathscr{L}^{\bullet}(\mathfrak{s}) := \left\{ \begin{array}{cl} {\displaystyle \sum_{d_{1}> \cdots > d_{r} \geq 0}} S^{\bullet}_{d_{1}}(s_{1}) \cdots S^{\bullet}_{d_{r}}(s_{r}) & (\mathfrak{s} = (s_{1}, \ldots, s_{r}) \in \mathcal{I}_{> 0}) \\ 1 & (\mathfrak{s} = \emptyset). \end{array} \right. \end{align} $$ $$ \begin{align} \mathscr{L}^{\bullet}(\mathfrak{s}) := \left\{ \begin{array}{cl} {\displaystyle \sum_{d_{1}> \cdots > d_{r} \geq 0}} S^{\bullet}_{d_{1}}(s_{1}) \cdots S^{\bullet}_{d_{r}}(s_{r}) & (\mathfrak{s} = (s_{1}, \ldots, s_{r}) \in \mathcal{I}_{> 0}) \\ 1 & (\mathfrak{s} = \emptyset). \end{array} \right. \end{align} $$
 It follows that for each 
 $P \in \mathcal {H}$
,
$P \in \mathcal {H}$
, 
 $\mathfrak {s} \in \mathcal {I}$
,
$\mathfrak {s} \in \mathcal {I}$
, 
 $s \in \mathbb {Z}_{\geq 1}$
 and
$s \in \mathbb {Z}_{\geq 1}$
 and 
 $d \in \mathbb {Z}$
, we have
$d \in \mathbb {Z}$
, we have 
 $$ \begin{align*} \mathscr{L}^{\bullet}_{d}(P) &= \mathscr{L}^{\bullet}_{< d + 1}(P) - \mathscr{L}^{\bullet}_{< d}(P), \\ \mathscr{L}^{\bullet}_{< d}(P) &= \sum_{d' < d} \mathscr{L}^{\bullet}_{d'}(P), \\ \mathscr{L}^{\bullet}(P) &= \sum_{d \in \mathbb{Z}} \mathscr{L}^{\bullet}_{d}(P) = \lim_{d \to \infty} \mathscr{L}^{\bullet}_{< d}(P) \in k_{\infty}, \\ \mathscr{L}^{\bullet}_{d}(s) \mathscr{L}^{\bullet}_{< d}(P) &= \mathscr{L}^{\bullet}_{d}([s, P]), \\ \mathscr{L}^{\operatorname{\mathrm{Li}}}(\mathfrak{s}) &= \operatorname{\mathrm{Li}}_{\mathfrak{s}}(\mathbf{1}), \\ \mathscr{L}^{\zeta}(\mathfrak{s}) &= \zeta_{A}(\mathfrak{s}), \end{align*} $$
$$ \begin{align*} \mathscr{L}^{\bullet}_{d}(P) &= \mathscr{L}^{\bullet}_{< d + 1}(P) - \mathscr{L}^{\bullet}_{< d}(P), \\ \mathscr{L}^{\bullet}_{< d}(P) &= \sum_{d' < d} \mathscr{L}^{\bullet}_{d'}(P), \\ \mathscr{L}^{\bullet}(P) &= \sum_{d \in \mathbb{Z}} \mathscr{L}^{\bullet}_{d}(P) = \lim_{d \to \infty} \mathscr{L}^{\bullet}_{< d}(P) \in k_{\infty}, \\ \mathscr{L}^{\bullet}_{d}(s) \mathscr{L}^{\bullet}_{< d}(P) &= \mathscr{L}^{\bullet}_{d}([s, P]), \\ \mathscr{L}^{\operatorname{\mathrm{Li}}}(\mathfrak{s}) &= \operatorname{\mathrm{Li}}_{\mathfrak{s}}(\mathbf{1}), \\ \mathscr{L}^{\zeta}(\mathfrak{s}) &= \zeta_{A}(\mathfrak{s}), \end{align*} $$
where 
 $\textbf {1}$
 is simply referred to
$\textbf {1}$
 is simply referred to 
 $(1,\ldots ,1)\in \mathbb {Z}_{>0}^{\operatorname {\mathrm {dep}}(\mathfrak {s})}$
 when it is clear from the context without confusion, and we set
$(1,\ldots ,1)\in \mathbb {Z}_{>0}^{\operatorname {\mathrm {dep}}(\mathfrak {s})}$
 when it is clear from the context without confusion, and we set 
 $\operatorname {\mathrm {Li}}_{\emptyset }(\mathbf {1}) := \zeta _{A}(\emptyset ) := 1$
.
$\operatorname {\mathrm {Li}}_{\emptyset }(\mathbf {1}) := \zeta _{A}(\emptyset ) := 1$
.
Remark 2.5. For 
 $1 \leq s \leq q$
 and
$1 \leq s \leq q$
 and 
 $d \geq 0$
, we have the following equality due to Carlitz (see also [Reference Thakur31, Thm. 5.9.1]):
$d \geq 0$
, we have the following equality due to Carlitz (see also [Reference Thakur31, Thm. 5.9.1]): 
 $$ \begin{align*} \dfrac{1}{L_{d}^{s}} = \sum_{a \in A_{+, d}} \dfrac{1}{a^{s}}. \end{align*} $$
$$ \begin{align*} \dfrac{1}{L_{d}^{s}} = \sum_{a \in A_{+, d}} \dfrac{1}{a^{s}}. \end{align*} $$
Therefore, for each 
 $\mathfrak {s} = (s_{1}, \ldots , s_{r})$
 with
$\mathfrak {s} = (s_{1}, \ldots , s_{r})$
 with 
 $1 \leq s_{i} \leq q$
 and
$1 \leq s_{i} \leq q$
 and 
 $d \in \mathbb {Z}$
, we have
$d \in \mathbb {Z}$
, we have 
 $$ \begin{align*} \mathscr{L}^{\operatorname{\mathrm{Li}}}_{d}(\mathfrak{s}) = \mathscr{L}^{\zeta}_{d}(\mathfrak{s}), \ \ \ \mathscr{L}^{\operatorname{\mathrm{Li}}}_{< d}(\mathfrak{s}) = \mathscr{L}^{\zeta}_{< d}(\mathfrak{s}), \end{align*} $$
$$ \begin{align*} \mathscr{L}^{\operatorname{\mathrm{Li}}}_{d}(\mathfrak{s}) = \mathscr{L}^{\zeta}_{d}(\mathfrak{s}), \ \ \ \mathscr{L}^{\operatorname{\mathrm{Li}}}_{< d}(\mathfrak{s}) = \mathscr{L}^{\zeta}_{< d}(\mathfrak{s}), \end{align*} $$
and
 $$ \begin{align} \operatorname{\mathrm{Li}}_{\mathfrak{s}}(\mathbf{1})=\mathscr{L}^{\operatorname{\mathrm{Li}}}(\mathfrak{s}) = \mathscr{L}^{\zeta}(\mathfrak{s})=\zeta_{A}(\mathfrak{s}). \end{align} $$
$$ \begin{align} \operatorname{\mathrm{Li}}_{\mathfrak{s}}(\mathbf{1})=\mathscr{L}^{\operatorname{\mathrm{Li}}}(\mathfrak{s}) = \mathscr{L}^{\zeta}(\mathfrak{s})=\zeta_{A}(\mathfrak{s}). \end{align} $$
2.3 Product formulae
 The harmonic product on 
 $\mathcal {H}$
 is denoted by
$\mathcal {H}$
 is denoted by 
 $*$
 or
$*$
 or 
 $*^{\operatorname {\mathrm {Li}}}$
. Thus,
$*^{\operatorname {\mathrm {Li}}}$
. Thus, 
 $*$
 is a k-bilinear map
$*$
 is a k-bilinear map 
 $\mathcal {H} \times \mathcal {H} \to \mathcal {H}$
 such that
$\mathcal {H} \times \mathcal {H} \to \mathcal {H}$
 such that 
 $$ \begin{align*} &[\emptyset] * P = P * [\emptyset] = P, \\ &[\mathfrak{s}] * [\mathfrak{n}] = [s_{1}, \mathfrak{s}_{-} * \mathfrak{n}] + [n_{1}, \mathfrak{s} * \mathfrak{n}_{-}] + [s_{1} + n_{1}, \mathfrak{s}_{-} * \mathfrak{n}_{-}] \end{align*} $$
$$ \begin{align*} &[\emptyset] * P = P * [\emptyset] = P, \\ &[\mathfrak{s}] * [\mathfrak{n}] = [s_{1}, \mathfrak{s}_{-} * \mathfrak{n}] + [n_{1}, \mathfrak{s} * \mathfrak{n}_{-}] + [s_{1} + n_{1}, \mathfrak{s}_{-} * \mathfrak{n}_{-}] \end{align*} $$
for each 
 $P \in \mathcal {H}$
,
$P \in \mathcal {H}$
, 
 $\mathfrak {s} = (s_{1}, \mathfrak {s}_{-}), \mathfrak {n} = (n_{1}, \mathfrak {n}_{-}) \in \mathcal{I}_{> 0}$
. For each
$\mathfrak {s} = (s_{1}, \mathfrak {s}_{-}), \mathfrak {n} = (n_{1}, \mathfrak {n}_{-}) \in \mathcal{I}_{> 0}$
. For each 
 $\mathfrak {s}, \mathfrak {n} \in \mathcal{I}_{> 0}$
, we put
$\mathfrak {s}, \mathfrak {n} \in \mathcal{I}_{> 0}$
, we put 
 $$ \begin{align} D^{\operatorname{\mathrm{Li}}}_{\mathfrak{s}, \mathfrak{n}} := 0 \in \mathcal{H}. \end{align} $$
$$ \begin{align} D^{\operatorname{\mathrm{Li}}}_{\mathfrak{s}, \mathfrak{n}} := 0 \in \mathcal{H}. \end{align} $$
 For each 
 $s, n \geq 1$
, H.-J. Chen showed in [Reference Chen15] that
$s, n \geq 1$
, H.-J. Chen showed in [Reference Chen15] that 
 $$ \begin{align} \mathscr{L}^{\zeta}_{d}(s) \mathscr{L}^{\zeta}_{d}(n) = \mathscr{L}^{\zeta}_{d}(s + n) + \sum_{j = 1}^{s + n - 1} \Delta_{s, n}^{[j]} \mathscr{L}^{\zeta}_{d}(s + n - j, j), \end{align} $$
$$ \begin{align} \mathscr{L}^{\zeta}_{d}(s) \mathscr{L}^{\zeta}_{d}(n) = \mathscr{L}^{\zeta}_{d}(s + n) + \sum_{j = 1}^{s + n - 1} \Delta_{s, n}^{[j]} \mathscr{L}^{\zeta}_{d}(s + n - j, j), \end{align} $$
where we set
 $$ \begin{align*} \Delta_{s, n}^{[j]} := \left\{ \begin{array}{ll} {\displaystyle (- 1)^{s - 1} \binom{j - 1}{s - 1} + (- 1)^{n - 1} \binom{j - 1}{n - 1}} & \mathrm{if}\ (q - 1) \mid j\ \mathrm{and}\ 1 \leq j < s + n \\ 0 & \mathrm{otherwise} \end{array} \right.. \end{align*} $$
$$ \begin{align*} \Delta_{s, n}^{[j]} := \left\{ \begin{array}{ll} {\displaystyle (- 1)^{s - 1} \binom{j - 1}{s - 1} + (- 1)^{n - 1} \binom{j - 1}{n - 1}} & \mathrm{if}\ (q - 1) \mid j\ \mathrm{and}\ 1 \leq j < s + n \\ 0 & \mathrm{otherwise} \end{array} \right.. \end{align*} $$
The q-shuffle product on 
 $\mathcal {H}$
 is denoted by
$\mathcal {H}$
 is denoted by 
 $*^{\zeta }$
. Thus,
$*^{\zeta }$
. Thus, 
 $*^{\zeta }$
 is a k-bilinear map
$*^{\zeta }$
 is a k-bilinear map 
 $\mathcal {H} \times \mathcal {H} \to \mathcal {H}$
 such that
$\mathcal {H} \times \mathcal {H} \to \mathcal {H}$
 such that 
 $$ \begin{align*} &[\emptyset] *^{\zeta} P = P *^{\zeta} [\emptyset] = P, \\ &[\mathfrak{s}] *^{\zeta} [\mathfrak{n}] = [s_{1}, \mathfrak{s}_{-} *^{\zeta} \mathfrak{n}] + [n_{1}, \mathfrak{s} *^{\zeta} \mathfrak{n}_{-}] + [s_{1} + n_{1}, \mathfrak{s}_{-} *^{\zeta} \mathfrak{n}_{-}] + D^{\zeta}_{\mathfrak{s}, \mathfrak{n}} \end{align*} $$
$$ \begin{align*} &[\emptyset] *^{\zeta} P = P *^{\zeta} [\emptyset] = P, \\ &[\mathfrak{s}] *^{\zeta} [\mathfrak{n}] = [s_{1}, \mathfrak{s}_{-} *^{\zeta} \mathfrak{n}] + [n_{1}, \mathfrak{s} *^{\zeta} \mathfrak{n}_{-}] + [s_{1} + n_{1}, \mathfrak{s}_{-} *^{\zeta} \mathfrak{n}_{-}] + D^{\zeta}_{\mathfrak{s}, \mathfrak{n}} \end{align*} $$
for each 
 $P \in \mathcal {H}$
,
$P \in \mathcal {H}$
, 
 $ \mathfrak {s} = (s_{1}, \mathfrak {s}_{-}),\mathfrak {n} = (n_{1}, \mathfrak {n}_{-}) \in \mathcal {I}_{> 0}$
, where we set
$ \mathfrak {s} = (s_{1}, \mathfrak {s}_{-}),\mathfrak {n} = (n_{1}, \mathfrak {n}_{-}) \in \mathcal {I}_{> 0}$
, where we set 
 $$ \begin{align} D^{\zeta}_{\mathfrak{s}, \mathfrak{n}} := \sum_{j = 1}^{s_{1} + n_{1} - 1} \Delta_{s_{1}, n_{1}}^{[j]} [s_{1} + n_{1} - j, (j) *^{\zeta} (\mathfrak{s}_{-} *^{\zeta} \mathfrak{n}_{-})] \end{align} $$
$$ \begin{align} D^{\zeta}_{\mathfrak{s}, \mathfrak{n}} := \sum_{j = 1}^{s_{1} + n_{1} - 1} \Delta_{s_{1}, n_{1}}^{[j]} [s_{1} + n_{1} - j, (j) *^{\zeta} (\mathfrak{s}_{-} *^{\zeta} \mathfrak{n}_{-})] \end{align} $$
(see Yamamoto’s definition in [Reference Thakur35, p. 1006]). By the induction on 
 $w + w'$
, we can show that
$w + w'$
, we can show that 
 $P *^{\bullet } Q \in \mathcal {H}_{w + w'}$
 for each
$P *^{\bullet } Q \in \mathcal {H}_{w + w'}$
 for each 
 $w, w' \in \mathbb {Z}_{\geq 0}$
,
$w, w' \in \mathbb {Z}_{\geq 0}$
, 
 $P \in \mathcal {H}_{w}$
,
$P \in \mathcal {H}_{w}$
, 
 $Q \in \mathcal {H}_{w'}$
 and
$Q \in \mathcal {H}_{w'}$
 and 
 $\bullet \in \{ \operatorname {\mathrm {Li}}, \zeta \}$
. In particular, when
$\bullet \in \{ \operatorname {\mathrm {Li}}, \zeta \}$
. In particular, when 
 $w, w' \in \mathbb {Z}_{\geq 1}$
, we have
$w, w' \in \mathbb {Z}_{\geq 1}$
, we have 
 $D^{\zeta }_{\mathfrak {s}, \mathfrak {n}} \in \mathcal {H}_{w + w'}$
 for each
$D^{\zeta }_{\mathfrak {s}, \mathfrak {n}} \in \mathcal {H}_{w + w'}$
 for each 
 $\mathfrak {s} \in \mathcal {I}_{w}$
 and
$\mathfrak {s} \in \mathcal {I}_{w}$
 and 
 $\mathfrak {n} \in \mathcal {I}_{w'}$
.
$\mathfrak {n} \in \mathcal {I}_{w'}$
.
Remark 2.6. When 
 $s + n \leq q$
, we observe that
$s + n \leq q$
, we observe that 
 $\Delta _{s, n}^{[j]} = 0$
 for all j. Thus, for
$\Delta _{s, n}^{[j]} = 0$
 for all j. Thus, for 
 $\mathfrak {s} = (s_{1}, \ldots ), \mathfrak {n} = (n_{1}, \ldots ) \in \mathcal {I}_{> 0}$
, if
$\mathfrak {s} = (s_{1}, \ldots ), \mathfrak {n} = (n_{1}, \ldots ) \in \mathcal {I}_{> 0}$
, if 
 $s_{1} + n_{1} \leq q$
, then we have
$s_{1} + n_{1} \leq q$
, then we have 
 $D^{\zeta }_{\mathfrak {s}, \mathfrak {n}} = 0$
.
$D^{\zeta }_{\mathfrak {s}, \mathfrak {n}} = 0$
.
The following product formulae are crucial when proving Theorem 3.6, whose detailed proof is given in the appendix.
Proposition 2.7. Let 
 $\bullet \in \left \{\operatorname {\mathrm {Li}}, \zeta \right \}$
. Given any
$\bullet \in \left \{\operatorname {\mathrm {Li}}, \zeta \right \}$
. Given any 
 $P,Q\in \mathcal {H}$
 and
$P,Q\in \mathcal {H}$
 and 
 $\mathfrak {s} = (s_{1}, \mathfrak {s}_{-}), \mathfrak {n} = (n_{1}, \mathfrak {n}_{-}) \in \mathcal {I}_{> 0}$
, we have the following identities for each
$\mathfrak {s} = (s_{1}, \mathfrak {s}_{-}), \mathfrak {n} = (n_{1}, \mathfrak {n}_{-}) \in \mathcal {I}_{> 0}$
, we have the following identities for each 
 $d\in \mathbb {Z}$
.
$d\in \mathbb {Z}$
. 
- 
(1)  $\mathscr {L}^{\bullet }(P) \mathscr {L}^{\bullet }(Q) = \mathscr {L}^{\bullet }(P *^{\bullet } Q)$
. $\mathscr {L}^{\bullet }(P) \mathscr {L}^{\bullet }(Q) = \mathscr {L}^{\bullet }(P *^{\bullet } Q)$
.
- 
(2)  $ \mathscr {L}^{\bullet }_{< d}(P) \mathscr {L}^{\bullet }_{< d}(Q) = \mathscr {L}^{\bullet }_{< d}(P *^{\bullet } Q)$
. $ \mathscr {L}^{\bullet }_{< d}(P) \mathscr {L}^{\bullet }_{< d}(Q) = \mathscr {L}^{\bullet }_{< d}(P *^{\bullet } Q)$
.
- 
(3)  $$ \begin{align*} \mathscr{L}^{\bullet}_{d}(\mathfrak{s}) \mathscr{L}^{\bullet}_{d}(\mathfrak{n}) &= \mathscr{L}^{\bullet}_{d}([s_{1} + n_{1}, \mathfrak{s}_{-} *^{\bullet} \mathfrak{n}_{-}]) + \mathscr{L}^{\bullet}_{d}(D^{\bullet}_{\mathfrak{s}, \mathfrak{n}}) \\ &= \mathscr{L}^{\bullet}_{d}(\mathfrak{s} *^{\bullet} \mathfrak{n}) - \mathscr{L}^{\bullet}_{d}([s_{1}, \mathfrak{s}_{-} *^{\bullet} \mathfrak{n}]) - \mathscr{L}^{\bullet}_{d}([n_{1}, \mathfrak{s} *^{\bullet} \mathfrak{n}_{-}]). \end{align*} $$ $$ \begin{align*} \mathscr{L}^{\bullet}_{d}(\mathfrak{s}) \mathscr{L}^{\bullet}_{d}(\mathfrak{n}) &= \mathscr{L}^{\bullet}_{d}([s_{1} + n_{1}, \mathfrak{s}_{-} *^{\bullet} \mathfrak{n}_{-}]) + \mathscr{L}^{\bullet}_{d}(D^{\bullet}_{\mathfrak{s}, \mathfrak{n}}) \\ &= \mathscr{L}^{\bullet}_{d}(\mathfrak{s} *^{\bullet} \mathfrak{n}) - \mathscr{L}^{\bullet}_{d}([s_{1}, \mathfrak{s}_{-} *^{\bullet} \mathfrak{n}]) - \mathscr{L}^{\bullet}_{d}([n_{1}, \mathfrak{s} *^{\bullet} \mathfrak{n}_{-}]). \end{align*} $$
Proof. We first mention that (3) for d follows from the second one for the same d. Indeed, for each 
 $\mathfrak {s} = (s_{1}, \ldots ), \mathfrak {n} = (n_{1}, \ldots ) \in \mathcal {I}_{> 0}$
, we have
$\mathfrak {s} = (s_{1}, \ldots ), \mathfrak {n} = (n_{1}, \ldots ) \in \mathcal {I}_{> 0}$
, we have 
 $$ \begin{align*} \mathscr{L}^{\operatorname{\mathrm{Li}}}_{d}(\mathfrak{s}) \mathscr{L}^{\operatorname{\mathrm{Li}}}_{d}(\mathfrak{n}) &= \mathscr{L}^{\operatorname{\mathrm{Li}}}_{d}(s_{1}) \mathscr{L}^{\operatorname{\mathrm{Li}}}_{d}(n_{1}) \mathscr{L}^{\operatorname{\mathrm{Li}}}_{< d}(\mathfrak{s}_{-}) \mathscr{L}^{\operatorname{\mathrm{Li}}}_{< d}(\mathfrak{n}_{-}) \\ &= \mathscr{L}^{\operatorname{\mathrm{Li}}}_{d}(s_{1} + n_{1}) \mathscr{L}^{\operatorname{\mathrm{Li}}}_{< d}(\mathfrak{s}_{-} *^{\operatorname{\mathrm{Li}}} \mathfrak{n}_{-}) \\ &= \mathscr{L}^{\operatorname{\mathrm{Li}}}_{d}([s_{1} + n_{1}, \mathfrak{s}_{-} *^{\operatorname{\mathrm{Li}}} \mathfrak{n}_{-}]) + \mathscr{L}^{\operatorname{\mathrm{Li}}}_{d}(D^{\operatorname{\mathrm{Li}}}_{\mathfrak{s}, \mathfrak{n}}), \end{align*} $$
$$ \begin{align*} \mathscr{L}^{\operatorname{\mathrm{Li}}}_{d}(\mathfrak{s}) \mathscr{L}^{\operatorname{\mathrm{Li}}}_{d}(\mathfrak{n}) &= \mathscr{L}^{\operatorname{\mathrm{Li}}}_{d}(s_{1}) \mathscr{L}^{\operatorname{\mathrm{Li}}}_{d}(n_{1}) \mathscr{L}^{\operatorname{\mathrm{Li}}}_{< d}(\mathfrak{s}_{-}) \mathscr{L}^{\operatorname{\mathrm{Li}}}_{< d}(\mathfrak{n}_{-}) \\ &= \mathscr{L}^{\operatorname{\mathrm{Li}}}_{d}(s_{1} + n_{1}) \mathscr{L}^{\operatorname{\mathrm{Li}}}_{< d}(\mathfrak{s}_{-} *^{\operatorname{\mathrm{Li}}} \mathfrak{n}_{-}) \\ &= \mathscr{L}^{\operatorname{\mathrm{Li}}}_{d}([s_{1} + n_{1}, \mathfrak{s}_{-} *^{\operatorname{\mathrm{Li}}} \mathfrak{n}_{-}]) + \mathscr{L}^{\operatorname{\mathrm{Li}}}_{d}(D^{\operatorname{\mathrm{Li}}}_{\mathfrak{s}, \mathfrak{n}}), \end{align*} $$
where the second equality comes from (2) and the definition of 
 $\mathscr {L}^{\operatorname {\mathrm {Li}}}_{d}$
, and the third identity comes from (2.8). Similarly, we have
$\mathscr {L}^{\operatorname {\mathrm {Li}}}_{d}$
, and the third identity comes from (2.8). Similarly, we have 
 $$ \begin{align*} \mathscr{L}^{\zeta}_{d}(\mathfrak{s}) \mathscr{L}^{\zeta}_{d}(\mathfrak{n}) &= \mathscr{L}^{\zeta}_{d}(s_{1}) \mathscr{L}^{\zeta}_{d}(n_{1}) \mathscr{L}^{\zeta}_{< d}(\mathfrak{s}_{-}) \mathscr{L}^{\zeta}_{< d}(\mathfrak{n}_{-}) \\ &= \left( \mathscr{L}^{\zeta}_{d}(s_{1} + n_{1}) + \sum_{j} \Delta_{s_{1}, n_{1}}^{j} \mathscr{L}^{\zeta}_{d}(s_{1} + n_{1} - j) \mathscr{L}^{\zeta}_{< d}(j) \right) \mathscr{L}^{\zeta}_{< d}(\mathfrak{s}_{-} *^{\zeta} \mathfrak{n}_{-}) \\ &= \mathscr{L}^{\zeta}_{d}([s_{1} + n_{1}, \mathfrak{s}_{-} *^{\zeta} \mathfrak{n}_{-}]) + \sum_{j} \Delta_{s_{1}, n_{1}}^{[j]} \mathscr{L}^{\zeta}_{d}(s_{1} + n_{1} - j) \mathscr{L}^{\zeta}_{< d}((j) *^{\zeta} (\mathfrak{s}_{-} *^{\zeta} \mathfrak{n}_{-}) ) \\ &= \mathscr{L}^{\zeta}_{d}([s_{1} + n_{1}, \mathfrak{s}_{-} *^{\zeta} \mathfrak{n}_{-}]) + \mathscr{L}^{\zeta}_{d}(D^{\zeta}_{\mathfrak{s}, \mathfrak{n}}), \end{align*} $$
$$ \begin{align*} \mathscr{L}^{\zeta}_{d}(\mathfrak{s}) \mathscr{L}^{\zeta}_{d}(\mathfrak{n}) &= \mathscr{L}^{\zeta}_{d}(s_{1}) \mathscr{L}^{\zeta}_{d}(n_{1}) \mathscr{L}^{\zeta}_{< d}(\mathfrak{s}_{-}) \mathscr{L}^{\zeta}_{< d}(\mathfrak{n}_{-}) \\ &= \left( \mathscr{L}^{\zeta}_{d}(s_{1} + n_{1}) + \sum_{j} \Delta_{s_{1}, n_{1}}^{j} \mathscr{L}^{\zeta}_{d}(s_{1} + n_{1} - j) \mathscr{L}^{\zeta}_{< d}(j) \right) \mathscr{L}^{\zeta}_{< d}(\mathfrak{s}_{-} *^{\zeta} \mathfrak{n}_{-}) \\ &= \mathscr{L}^{\zeta}_{d}([s_{1} + n_{1}, \mathfrak{s}_{-} *^{\zeta} \mathfrak{n}_{-}]) + \sum_{j} \Delta_{s_{1}, n_{1}}^{[j]} \mathscr{L}^{\zeta}_{d}(s_{1} + n_{1} - j) \mathscr{L}^{\zeta}_{< d}((j) *^{\zeta} (\mathfrak{s}_{-} *^{\zeta} \mathfrak{n}_{-}) ) \\ &= \mathscr{L}^{\zeta}_{d}([s_{1} + n_{1}, \mathfrak{s}_{-} *^{\zeta} \mathfrak{n}_{-}]) + \mathscr{L}^{\zeta}_{d}(D^{\zeta}_{\mathfrak{s}, \mathfrak{n}}), \end{align*} $$
where the second equality comes from (2.9) and (2), the third identity comes from (2) and the fourth one comes from (2.10).
 To prove the formula (2), we first mention that when 
 $d < 0$
, the formula holds as both sides of the identity are zero. We then prove the formula (2) by induction on d. Now, let d be any non-negative integer. By bilinearity, we may assume that
$d < 0$
, the formula holds as both sides of the identity are zero. We then prove the formula (2) by induction on d. Now, let d be any non-negative integer. By bilinearity, we may assume that 
 $P = \mathfrak {s}, Q = \mathfrak {n} \in \mathcal {I}_{> 0}$
. Then we have
$P = \mathfrak {s}, Q = \mathfrak {n} \in \mathcal {I}_{> 0}$
. Then we have 
 $$ \begin{align*} &\mathscr{L}^{\bullet}_{< d}(\mathfrak{s}) \mathscr{L}^{\bullet}_{< d}(\mathfrak{n}) \\ &= \sum_{d_{1} < d} \mathscr{L}^{\bullet}_{d_{1}}(s_{1}) \mathscr{L}^{\bullet}_{< d_{1}}(\mathfrak{s}_{-}) \mathscr{L}^{\bullet}_{< d_{1}}(\mathfrak{n}) + \sum_{d_{1} < d} \mathscr{L}^{\bullet}_{d_{1}}(n_{1}) \mathscr{L}^{\bullet}_{< d_{1}}(\mathfrak{s}) \mathscr{L}^{\bullet}_{< d_{1}}(\mathfrak{n}_{-}) + \sum_{d_{1} < d} \mathscr{L}^{\bullet}_{d_{1}}(\mathfrak{s}) \mathscr{L}^{\bullet}_{d_{1}}(\mathfrak{n}) \\ &= \sum_{d_{1} < d} \mathscr{L}^{\bullet}_{d_{1}}(s_{1}) \mathscr{L}^{\bullet}_{< d_{1}}(\mathfrak{s}_{-} *^{\bullet} \mathfrak{n}) + \sum_{d_{1} < d} \mathscr{L}^{\bullet}_{d_{1}}(n_{1}) \mathscr{L}^{\bullet}_{< d_{1}}(\mathfrak{s} *^{\bullet} \mathfrak{n}_{-}) \\ & \ \ \ + \sum_{d_{1} < d} \mathscr{L}^{\bullet}_{d_{1}}([s_{1} + n_{1}, \mathfrak{s}_{-} *^{\bullet} \mathfrak{n}_{-}] + D^{\bullet}_{\mathfrak{s}, \mathfrak{n}}) \\ &= \mathscr{L}^{\bullet}_{< d}(\mathfrak{s} *^{\bullet} \mathfrak{n}), \end{align*} $$
$$ \begin{align*} &\mathscr{L}^{\bullet}_{< d}(\mathfrak{s}) \mathscr{L}^{\bullet}_{< d}(\mathfrak{n}) \\ &= \sum_{d_{1} < d} \mathscr{L}^{\bullet}_{d_{1}}(s_{1}) \mathscr{L}^{\bullet}_{< d_{1}}(\mathfrak{s}_{-}) \mathscr{L}^{\bullet}_{< d_{1}}(\mathfrak{n}) + \sum_{d_{1} < d} \mathscr{L}^{\bullet}_{d_{1}}(n_{1}) \mathscr{L}^{\bullet}_{< d_{1}}(\mathfrak{s}) \mathscr{L}^{\bullet}_{< d_{1}}(\mathfrak{n}_{-}) + \sum_{d_{1} < d} \mathscr{L}^{\bullet}_{d_{1}}(\mathfrak{s}) \mathscr{L}^{\bullet}_{d_{1}}(\mathfrak{n}) \\ &= \sum_{d_{1} < d} \mathscr{L}^{\bullet}_{d_{1}}(s_{1}) \mathscr{L}^{\bullet}_{< d_{1}}(\mathfrak{s}_{-} *^{\bullet} \mathfrak{n}) + \sum_{d_{1} < d} \mathscr{L}^{\bullet}_{d_{1}}(n_{1}) \mathscr{L}^{\bullet}_{< d_{1}}(\mathfrak{s} *^{\bullet} \mathfrak{n}_{-}) \\ & \ \ \ + \sum_{d_{1} < d} \mathscr{L}^{\bullet}_{d_{1}}([s_{1} + n_{1}, \mathfrak{s}_{-} *^{\bullet} \mathfrak{n}_{-}] + D^{\bullet}_{\mathfrak{s}, \mathfrak{n}}) \\ &= \mathscr{L}^{\bullet}_{< d}(\mathfrak{s} *^{\bullet} \mathfrak{n}), \end{align*} $$
where the second equality comes from the induction hypothesis as well as (3) (as (2) holds for 
 $d_1<d$
 by induction hypothesis). Finally, the formula (1) follows from (2) by taking the limit
$d_1<d$
 by induction hypothesis). Finally, the formula (1) follows from (2) by taking the limit 
 $d \to \infty $
.
$d \to \infty $
.
3 Generators
 The purpose of this section is to establish Theorem 3.6, which allows us to obtain the desired generating sets for 
 $\mathcal {Z}_w$
. To achieve it, we need to set up the box-plus operator on
$\mathcal {Z}_w$
. To achieve it, we need to set up the box-plus operator on 
 $\mathcal {H}^{\oplus 2}$
 as well as the k-linear maps
$\mathcal {H}^{\oplus 2}$
 as well as the k-linear maps 
 $\mathscr {U}^{\bullet }$
 on
$\mathscr {U}^{\bullet }$
 on 
 $\mathcal {H}$
.
$\mathcal {H}$
.
3.1 The box-plus operator
Definition 3.1. Let 
 $\boxplus \colon \mathcal {H}^{\oplus 2} \to \mathcal {H}$
 be the k-linear map defined by
$\boxplus \colon \mathcal {H}^{\oplus 2} \to \mathcal {H}$
 be the k-linear map defined by 
 $$ \begin{align*} \emptyset \boxplus P = P \boxplus \emptyset := 0 \ \ \mathrm{and} \ \ \mathfrak{s} \boxplus \mathfrak{n} := (\mathfrak{s}_{+}, s_{r} + n_{1}, \mathfrak{n}_{-}) \end{align*} $$
$$ \begin{align*} \emptyset \boxplus P = P \boxplus \emptyset := 0 \ \ \mathrm{and} \ \ \mathfrak{s} \boxplus \mathfrak{n} := (\mathfrak{s}_{+}, s_{r} + n_{1}, \mathfrak{n}_{-}) \end{align*} $$
for 
 $P \in \mathcal {H}$
 and
$P \in \mathcal {H}$
 and 
 $\mathfrak {s} = (\mathfrak {s}_{+}, s_{r}), \mathfrak {n} = (n_{1}, \mathfrak {n}_{-}) \in \mathcal {I}_{> 0}$
.
$\mathfrak {s} = (\mathfrak {s}_{+}, s_{r}), \mathfrak {n} = (n_{1}, \mathfrak {n}_{-}) \in \mathcal {I}_{> 0}$
.
Remark 3.2. To avoid confusion, we mention that for each 
 $n \geq 1$
 and
$n \geq 1$
 and 
 $P = \sum _{\mathfrak {s} \in \mathcal {I}} a_{\mathfrak {s}} [\mathfrak {s}] \in \mathcal {H}$
,
$P = \sum _{\mathfrak {s} \in \mathcal {I}} a_{\mathfrak {s}} [\mathfrak {s}] \in \mathcal {H}$
, 
 $$ \begin{align*} [n, P] & = \sum_{\mathfrak{s} = (s_{1}, \ldots, s_{r}) \in \mathcal{I}} a_{\mathfrak{s}} [n, s_{1}, \ldots, s_{r}] \in \mathcal{H}_{> 0}, \\ (n) \boxplus P & = \sum_{\mathfrak{s} = (s_{1}, \ldots, s_{r}) \in \mathcal{I}_{> 0}} a_{\mathfrak{s}} [n + s_{1}, s_{2}, \ldots, s_{r}] \in \mathcal{H}_{> 0} \ \ \ (\neq [n] + P). \end{align*} $$
$$ \begin{align*} [n, P] & = \sum_{\mathfrak{s} = (s_{1}, \ldots, s_{r}) \in \mathcal{I}} a_{\mathfrak{s}} [n, s_{1}, \ldots, s_{r}] \in \mathcal{H}_{> 0}, \\ (n) \boxplus P & = \sum_{\mathfrak{s} = (s_{1}, \ldots, s_{r}) \in \mathcal{I}_{> 0}} a_{\mathfrak{s}} [n + s_{1}, s_{2}, \ldots, s_{r}] \in \mathcal{H}_{> 0} \ \ \ (\neq [n] + P). \end{align*} $$
Furthermore, in the depth one case for 
 $\mathfrak {s}=(s)$
 and
$\mathfrak {s}=(s)$
 and 
 $\mathfrak {n}=(n)$
, we have
$\mathfrak {n}=(n)$
, we have 
 $\mathfrak {s}_{+}=\emptyset =\mathfrak {n}_{-}$
, and hence in this case,
$\mathfrak {s}_{+}=\emptyset =\mathfrak {n}_{-}$
, and hence in this case, 
 $$\begin{align*}\mathfrak{s} \boxplus \mathfrak{n}=[s+n].\end{align*}$$
$$\begin{align*}\mathfrak{s} \boxplus \mathfrak{n}=[s+n].\end{align*}$$
3.2 Generating sets
 We define a k-linear endomorphism 
 $\mathscr {U}^{\bullet } \colon \mathcal {H} \to \mathcal {H}$
 as follows. Let
$\mathscr {U}^{\bullet } \colon \mathcal {H} \to \mathcal {H}$
 as follows. Let 
 $\mathfrak {s} \in \mathcal {I}$
. We write
$\mathfrak {s} \in \mathcal {I}$
. We write 
 $$ \begin{align} \mathfrak{s} = (s_{1}, \ldots ) = (\mathfrak{s}^{\mathrm{T}}, q^{\{ m \}}, \mathfrak{s}') \end{align} $$
$$ \begin{align} \mathfrak{s} = (s_{1}, \ldots ) = (\mathfrak{s}^{\mathrm{T}}, q^{\{ m \}}, \mathfrak{s}') \end{align} $$
with 
 $\mathfrak {s}^{\mathrm {T}} \in \mathcal {I}^{\mathrm {T}}$
,
$\mathfrak {s}^{\mathrm {T}} \in \mathcal {I}^{\mathrm {T}}$
, 
 $m \geq 0$
 and
$m \geq 0$
 and 
 $\mathfrak {s}' = (s^\prime _{1}, \ldots )$
 with
$\mathfrak {s}' = (s^\prime _{1}, \ldots )$
 with 
 $s^\prime _{1}> q$
 or
$s^\prime _{1}> q$
 or 
 $\mathfrak {s}' = \emptyset $
. When
$\mathfrak {s}' = \emptyset $
. When 
 $\mathfrak {s}' \neq \emptyset $
, we set
$\mathfrak {s}' \neq \emptyset $
, we set 
 $$ \begin{align} \mathfrak{s}" := (s^\prime_{1} - q, \mathfrak{s}^\prime_{-}). \end{align} $$
$$ \begin{align} \mathfrak{s}" := (s^\prime_{1} - q, \mathfrak{s}^\prime_{-}). \end{align} $$
Example 3.3. Let 
 $\mathfrak {s}=(q-1,q,q,q+1,1)$
. Then
$\mathfrak {s}=(q-1,q,q,q+1,1)$
. Then 
 $\mathfrak {s}^{\mathrm {T}}=(q-1)$
,
$\mathfrak {s}^{\mathrm {T}}=(q-1)$
, 
 $m=2$
 and
$m=2$
 and 
 $\mathfrak {s}'=(q+1,1)$
. Since
$\mathfrak {s}'=(q+1,1)$
. Since 
 $\mathfrak {s}'\neq \emptyset $
, we also have
$\mathfrak {s}'\neq \emptyset $
, we also have 
 $\mathfrak {s}"=(1,1)$
.
$\mathfrak {s}"=(1,1)$
.
We set
 $$ \begin{align} \alpha^{\bullet}_{q}(P) := [1, (q - 1) *^{\bullet} P] \end{align} $$
$$ \begin{align} \alpha^{\bullet}_{q}(P) := [1, (q - 1) *^{\bullet} P] \end{align} $$
for each 
 $P \in \mathcal {H}$
. For
$P \in \mathcal {H}$
. For 
 $m=0$
,
$m=0$
, 
 $\alpha _{q}^{\bullet , 0}$
 is defined to be the identity map on
$\alpha _{q}^{\bullet , 0}$
 is defined to be the identity map on 
 $\mathcal {H}$
, and for
$\mathcal {H}$
, and for 
 $m\in \mathbb {Z}_{>0}$
,
$m\in \mathbb {Z}_{>0}$
, 
 $\alpha ^{\bullet ,m}_{q}$
 is defined to be the mth iteration of
$\alpha ^{\bullet ,m}_{q}$
 is defined to be the mth iteration of 
 $\alpha ^{\bullet }_{q}$
.
$\alpha ^{\bullet }_{q}$
.
Definition 3.4. For 
 $\bullet \in \left \{ \operatorname {\mathrm {Li}}, \zeta \right \}$
, we define the k-linear map
$\bullet \in \left \{ \operatorname {\mathrm {Li}}, \zeta \right \}$
, we define the k-linear map 
 $\mathscr {U}^{\bullet }:\mathcal {H}\rightarrow \mathcal {H}$
 given by
$\mathscr {U}^{\bullet }:\mathcal {H}\rightarrow \mathcal {H}$
 given by 
 $$ \begin{align*} \mathscr{U}^{\bullet}(\mathfrak{s}) := \left\{ \begin{array}{@{}ll} - [\mathfrak{s}^{\mathrm{T}}, q^{\{m + 1\}}, \mathfrak{s}"] + L_{1}^{m + 1} [\mathfrak{s}^{\mathrm{T}}, \alpha_{q}^{\bullet, m + 1}(\mathfrak{s}")] & \\ \hspace{5.0em} + L_{1}^{m + 1} (\mathfrak{s}^{\mathrm{T}} \boxplus \alpha_{q}^{\bullet, m + 1}(\mathfrak{s}")) - [\mathfrak{s}^{\mathrm{T}}, q^{\{m\}}, D^{\bullet}_{q, \mathfrak{s}"}] & (\mathfrak{s}' \neq \emptyset) \\[0.5em] L_{1}^{m} [\mathfrak{s}^{\mathrm{T}}, \alpha_{q}^{\bullet, m}(\emptyset)] + L_{1}^{m} (\mathfrak{s}^{\mathrm{T}} \boxplus \alpha_{q}^{\bullet, m}(\emptyset)) & (\mathfrak{s}' = \emptyset) \end{array} \right. \end{align*} $$
$$ \begin{align*} \mathscr{U}^{\bullet}(\mathfrak{s}) := \left\{ \begin{array}{@{}ll} - [\mathfrak{s}^{\mathrm{T}}, q^{\{m + 1\}}, \mathfrak{s}"] + L_{1}^{m + 1} [\mathfrak{s}^{\mathrm{T}}, \alpha_{q}^{\bullet, m + 1}(\mathfrak{s}")] & \\ \hspace{5.0em} + L_{1}^{m + 1} (\mathfrak{s}^{\mathrm{T}} \boxplus \alpha_{q}^{\bullet, m + 1}(\mathfrak{s}")) - [\mathfrak{s}^{\mathrm{T}}, q^{\{m\}}, D^{\bullet}_{q, \mathfrak{s}"}] & (\mathfrak{s}' \neq \emptyset) \\[0.5em] L_{1}^{m} [\mathfrak{s}^{\mathrm{T}}, \alpha_{q}^{\bullet, m}(\emptyset)] + L_{1}^{m} (\mathfrak{s}^{\mathrm{T}} \boxplus \alpha_{q}^{\bullet, m}(\emptyset)) & (\mathfrak{s}' = \emptyset) \end{array} \right. \end{align*} $$
Remark 3.5. From the definition, one sees that 
 $\mathscr {U}^{\bullet }(\mathcal {H}_{w}) \subset \mathcal {H}_{w}$
. We also mention that when
$\mathscr {U}^{\bullet }(\mathcal {H}_{w}) \subset \mathcal {H}_{w}$
. We also mention that when 
 $\mathfrak {s}\in \mathcal {I}^{\mathrm {T}}$
, then
$\mathfrak {s}\in \mathcal {I}^{\mathrm {T}}$
, then 
 $\mathscr {U}^{\bullet }(\mathfrak {s})=\mathfrak {s}$
 since in this case, we have
$\mathscr {U}^{\bullet }(\mathfrak {s})=\mathfrak {s}$
 since in this case, we have 
 $m=0$
 and
$m=0$
 and 
 $\mathfrak {s}'=\emptyset $
.
$\mathfrak {s}'=\emptyset $
.
Theorem 3.6. Let 
 $\bullet \in \left \{ \operatorname {\mathrm {Li}}, \zeta \right \}$
. For each
$\bullet \in \left \{ \operatorname {\mathrm {Li}}, \zeta \right \}$
. For each 
 $P \in \mathcal {H}$
, the following statements hold.
$P \in \mathcal {H}$
, the following statements hold. 
- 
(1)  $\mathscr {L}^{\bullet }(\mathscr {U}^{\bullet }(P)) = \mathscr {L}^{\bullet }(P)$
. $\mathscr {L}^{\bullet }(\mathscr {U}^{\bullet }(P)) = \mathscr {L}^{\bullet }(P)$
.
- 
(2) There exists an explicit integer  $e \geq 0$
 such that $e \geq 0$
 such that $\operatorname {\mathrm {Supp}}((\mathscr {U}^{\bullet })^{e}(P)) \subset \mathcal {I}^{\mathrm {T}}$
, where $\operatorname {\mathrm {Supp}}((\mathscr {U}^{\bullet })^{e}(P)) \subset \mathcal {I}^{\mathrm {T}}$
, where $(\mathscr {U}^{\bullet })^{0}$
 is defined to be the identity map and for $(\mathscr {U}^{\bullet })^{0}$
 is defined to be the identity map and for $e\in \mathbb {Z}_{>0}$
, $e\in \mathbb {Z}_{>0}$
, $(\mathscr {U}^{\bullet })^{e}$
 is defined to be the eth iteration of $(\mathscr {U}^{\bullet })^{e}$
 is defined to be the eth iteration of $\mathscr {U}^{\bullet }$
. $\mathscr {U}^{\bullet }$
.
 Note that our 
 $\mathscr {U}^{\bullet }$
 is concrete and explicit and simultaneously deals with the two products
$\mathscr {U}^{\bullet }$
 is concrete and explicit and simultaneously deals with the two products 
 $*^{\operatorname {\mathrm {Li}}}$
 and
$*^{\operatorname {\mathrm {Li}}}$
 and 
 $*^{\zeta }$
. Our strategy for proving Theorem 3.6 arises from [Reference Ngo Dac26], and so we leave the detailed proof to the appendix. However, we give an outline of the proof of Theorem 3.6 (1) as follows. Let
$*^{\zeta }$
. Our strategy for proving Theorem 3.6 arises from [Reference Ngo Dac26], and so we leave the detailed proof to the appendix. However, we give an outline of the proof of Theorem 3.6 (1) as follows. Let 
 $\bullet \in \left \{\operatorname {\mathrm {Li}}, \zeta \right \}$
.
$\bullet \in \left \{\operatorname {\mathrm {Li}}, \zeta \right \}$
. 
- 
(I) We first define the space of binary relations  $\mathcal {P}^{\bullet }\subset \mathcal {H}^{\oplus 2}$
 in (A.1) and note that for $\mathcal {P}^{\bullet }\subset \mathcal {H}^{\oplus 2}$
 in (A.1) and note that for $(P,Q)\in \mathcal {P}^{\bullet }$
, we have $(P,Q)\in \mathcal {P}^{\bullet }$
, we have $$\begin{align*}\mathscr{L}^{\bullet}(P, Q) := \mathscr{L}^{\bullet}(P)+\mathscr{L}^{\bullet}(Q)=0 .\end{align*}$$ $$\begin{align*}\mathscr{L}^{\bullet}(P, Q) := \mathscr{L}^{\bullet}(P)+\mathscr{L}^{\bullet}(Q)=0 .\end{align*}$$
- 
(II) For any  $\mathfrak {s}\in \mathcal {I}_{>0}$
 and integer $\mathfrak {s}\in \mathcal {I}_{>0}$
 and integer $m\geq 0$
, we define in Sec. A.3 the following maps and we further show in Proposition A.4 that they preserve $m\geq 0$
, we define in Sec. A.3 the following maps and we further show in Proposition A.4 that they preserve $$\begin{align*}\mathscr{B}_{\mathfrak{s}}^{\bullet},\mathscr{C}_{\mathfrak{s}}^{\bullet},\mathscr{BC}_{q}^{\bullet,m}:\mathcal{H}_{>0}^{\oplus 2}\rightarrow \mathcal{H}_{>0}^{\oplus 2}, \end{align*}$$ $$\begin{align*}\mathscr{B}_{\mathfrak{s}}^{\bullet},\mathscr{C}_{\mathfrak{s}}^{\bullet},\mathscr{BC}_{q}^{\bullet,m}:\mathcal{H}_{>0}^{\oplus 2}\rightarrow \mathcal{H}_{>0}^{\oplus 2}, \end{align*}$$ $\mathcal {P}^{\bullet }$
. $\mathcal {P}^{\bullet }$
.
- 
(III) In order to give a clear outline, we drop the subscripts to avoid heavy notation as all details are given in the proof of Theorem A.5. We start with  $R_{1}\in \mathcal {P}_{q}^{\bullet }$
, and consider $R_{1}\in \mathcal {P}_{q}^{\bullet }$
, and consider $\mathscr {D}^{\bullet }(R_{1})$
 for choosing a suitable $\mathscr {D}^{\bullet }(R_{1})$
 for choosing a suitable $\mathscr {D}^{\bullet }$
 arising from one of $\mathscr {D}^{\bullet }$
 arising from one of $\mathscr {B}^{\bullet }, \mathscr {C}^{\bullet }, \mathscr {BC}^{\bullet }$
 as well as their composites (see (A.4), (A.5), (A.6) and (A.7)). Based on (II), we have $\mathscr {B}^{\bullet }, \mathscr {C}^{\bullet }, \mathscr {BC}^{\bullet }$
 as well as their composites (see (A.4), (A.5), (A.6) and (A.7)). Based on (II), we have $\mathscr {D}^{\bullet }(R_{1})\in \mathcal {P}^{\bullet }$
 and hence $\mathscr {D}^{\bullet }(R_{1})\in \mathcal {P}^{\bullet }$
 and hence $\mathscr {L}^{\bullet }(\mathscr {D}^{\bullet }(R_{1}))=0$
. In this case, the expansion of $\mathscr {L}^{\bullet }(\mathscr {D}^{\bullet }(R_{1}))=0$
. In this case, the expansion of $\mathscr {L}^{\bullet }(\mathscr {D}^{\bullet }(R_{1}))$
 is equal to $\mathscr {L}^{\bullet }(\mathscr {D}^{\bullet }(R_{1}))$
 is equal to $\mathscr {L}^{\bullet }(\mathfrak {s})-\mathscr {L}^{\bullet }(\mathscr {U}^{\bullet }(\mathfrak {s}))$
, and hence $\mathscr {L}^{\bullet }(\mathfrak {s})-\mathscr {L}^{\bullet }(\mathscr {U}^{\bullet }(\mathfrak {s}))$
, and hence $\mathscr {L}^{\bullet }(\mathfrak {s})=\mathscr {L}^{\bullet }(\mathscr {U}^{\bullet }(\mathfrak {s}))$
 as desired. $\mathscr {L}^{\bullet }(\mathfrak {s})=\mathscr {L}^{\bullet }(\mathscr {U}^{\bullet }(\mathfrak {s}))$
 as desired.
As a consequence of Theorem 3.6, we obtain the following important equality.
Corollary 3.7. Let 
 $\bullet \in \left \{\operatorname {\mathrm {Li}}, \zeta \right \}$
. For any
$\bullet \in \left \{\operatorname {\mathrm {Li}}, \zeta \right \}$
. For any 
 $w\geq 0$
, we let
$w\geq 0$
, we let 
 $\mathcal {Z}_{w}^{\bullet } $
 be the k-vector space spanned by the elements
$\mathcal {Z}_{w}^{\bullet } $
 be the k-vector space spanned by the elements 
 $\mathscr {L}^{\bullet }(\mathfrak {s})\in k_{\infty }$
 for
$\mathscr {L}^{\bullet }(\mathfrak {s})\in k_{\infty }$
 for 
 $\mathfrak {s} \in \mathcal {I}_{w}$
. Then
$\mathfrak {s} \in \mathcal {I}_{w}$
. Then 
 $$\begin{align*}\left\{ \mathscr{L}^{\bullet}(\mathfrak{s})| \mathfrak{s}\in \mathcal{I}^{\mathrm{T}}_{w} \right\}\end{align*}$$
$$\begin{align*}\left\{ \mathscr{L}^{\bullet}(\mathfrak{s})| \mathfrak{s}\in \mathcal{I}^{\mathrm{T}}_{w} \right\}\end{align*}$$
is a generating set for 
 $\mathcal {Z}_{w}^{\bullet } $
. In particular, we have
$\mathcal {Z}_{w}^{\bullet } $
. In particular, we have 
 $$\begin{align*}\mathcal{Z}^{\operatorname{\mathrm{Li}}}_{w}=\mathcal{Z}_{w}^{\zeta} \ (=\mathcal{Z}_{w}) .\end{align*}$$
$$\begin{align*}\mathcal{Z}^{\operatorname{\mathrm{Li}}}_{w}=\mathcal{Z}_{w}^{\zeta} \ (=\mathcal{Z}_{w}) .\end{align*}$$
Proof. The first assertion comes from Theorem 3.6. We note that for 
 $\mathfrak {s}\in \mathcal {I}^{\mathrm {T}}_{w}$
, we have
$\mathfrak {s}\in \mathcal {I}^{\mathrm {T}}_{w}$
, we have 
 $$\begin{align*}\mathscr{L}^{\operatorname{\mathrm{Li}}}(\mathfrak{s}):= \operatorname{\mathrm{Li}}_{\mathfrak{s}}(\mathbf{1})=\zeta_{A}(\mathfrak{s}) =:\mathscr{L}^{\zeta}(\mathfrak{s}),\end{align*}$$
$$\begin{align*}\mathscr{L}^{\operatorname{\mathrm{Li}}}(\mathfrak{s}):= \operatorname{\mathrm{Li}}_{\mathfrak{s}}(\mathbf{1})=\zeta_{A}(\mathfrak{s}) =:\mathscr{L}^{\zeta}(\mathfrak{s}),\end{align*}$$
whence obtaining 
 $\mathcal {Z}_{w}^{\operatorname {\mathrm {Li}}}= \mathcal {Z}_{w}^{\zeta }$
.
$\mathcal {Z}_{w}^{\operatorname {\mathrm {Li}}}= \mathcal {Z}_{w}^{\zeta }$
.
Theorem 3.8. The k-vector space 
 $\mathcal {Z}_{w}$
 is spanned by the elements
$\mathcal {Z}_{w}$
 is spanned by the elements 
 $\operatorname {\mathrm {Li}}_{\mathfrak {s}}(\mathbf {1})$
 for
$\operatorname {\mathrm {Li}}_{\mathfrak {s}}(\mathbf {1})$
 for 
 $\mathfrak {s} \in \mathcal {I}^{\mathrm {ND}}_{w}$
.
$\mathfrak {s} \in \mathcal {I}^{\mathrm {ND}}_{w}$
.
Proof. We set 
 $d_{w}' := |\mathcal {I}^{\mathrm {T}}_{w}| = |\mathcal {I}^{\mathrm {ND}}_{w}|$
. By the definition of
$d_{w}' := |\mathcal {I}^{\mathrm {T}}_{w}| = |\mathcal {I}^{\mathrm {ND}}_{w}|$
. By the definition of 
 $\mathscr {U}^{\operatorname {\mathrm {Li}}}$
 and Theorem 3.6 (2), there exists
$\mathscr {U}^{\operatorname {\mathrm {Li}}}$
 and Theorem 3.6 (2), there exists 
 $e \gg 0$
 such that
$e \gg 0$
 such that 
 $(\mathscr {U}^{\operatorname {\mathrm {Li}}})^{e}(\mathcal {H}_{w / \mathbb {F}_{p}[L_{1}]}) \subset \mathcal {H}^{\mathrm {T}}_{w / \mathbb {F}_{p}[L_{1}]}$
, where
$(\mathscr {U}^{\operatorname {\mathrm {Li}}})^{e}(\mathcal {H}_{w / \mathbb {F}_{p}[L_{1}]}) \subset \mathcal {H}^{\mathrm {T}}_{w / \mathbb {F}_{p}[L_{1}]}$
, where 
 $\mathcal {H}_{w / \mathbb {F}_{p}[L_{1}]}$
 (resp.
$\mathcal {H}_{w / \mathbb {F}_{p}[L_{1}]}$
 (resp. 
 $\mathcal {H}^{\mathrm {T}}_{w / \mathbb {F}_{p}[L_{1}]}$
) is the
$\mathcal {H}^{\mathrm {T}}_{w / \mathbb {F}_{p}[L_{1}]}$
) is the 
 $\mathbb {F}_{p}[L_{1}]$
-module spanned by
$\mathbb {F}_{p}[L_{1}]$
-module spanned by 
 $\mathfrak {s} \in \mathcal {I}_{w}$
 (resp.
$\mathfrak {s} \in \mathcal {I}_{w}$
 (resp. 
 $\mathfrak {s} \in \mathcal {I}^{\mathrm {T}}_{w}$
) in
$\mathfrak {s} \in \mathcal {I}^{\mathrm {T}}_{w}$
) in 
 $\mathcal {H}_{w}$
. We note that according to Remark 3.5,
$\mathcal {H}_{w}$
. We note that according to Remark 3.5, 
 $(\mathscr {U}^{\operatorname {\mathrm {Li}}})^{e}$
 is independent of e for
$(\mathscr {U}^{\operatorname {\mathrm {Li}}})^{e}$
 is independent of e for 
 $e\gg 0$
.
$e\gg 0$
.
To show the desired result, it suffices to prove that the determinant of the matrix
 $$\begin{align*}U = (u_{\mathfrak{s}, \mathfrak{n}})_{\mathfrak{s} \in \mathcal{I}^{\mathrm{ND}}_{w}, \mathfrak{n} \in \mathcal{I}^{\mathrm{T}}_{w}} \in \operatorname{\mathrm{Mat}}_{d_{w}}(\mathbb{F}_{p}[L_{1}])\end{align*}$$
$$\begin{align*}U = (u_{\mathfrak{s}, \mathfrak{n}})_{\mathfrak{s} \in \mathcal{I}^{\mathrm{ND}}_{w}, \mathfrak{n} \in \mathcal{I}^{\mathrm{T}}_{w}} \in \operatorname{\mathrm{Mat}}_{d_{w}}(\mathbb{F}_{p}[L_{1}])\end{align*}$$
arising from
 $$ \begin{align*} (\mathscr{U}^{\operatorname{\mathrm{Li}}})^{e}(\mathfrak{s}) = \sum_{\mathfrak{n} \in \mathcal{I}^{\mathrm{T}}_{w}} u_{\mathfrak{s}, \mathfrak{n}} [\mathfrak{n}] \ \ (\mathfrak{s} \in \mathcal{I}^{\mathrm{ND}}_{w}) \end{align*} $$
$$ \begin{align*} (\mathscr{U}^{\operatorname{\mathrm{Li}}})^{e}(\mathfrak{s}) = \sum_{\mathfrak{n} \in \mathcal{I}^{\mathrm{T}}_{w}} u_{\mathfrak{s}, \mathfrak{n}} [\mathfrak{n}] \ \ (\mathfrak{s} \in \mathcal{I}^{\mathrm{ND}}_{w}) \end{align*} $$
is non-zero. We mention that 
 $\mathcal {I}^{\mathrm {ND}}_{w}$
 is equal to
$\mathcal {I}^{\mathrm {ND}}_{w}$
 is equal to 
 $\mathcal {I}^{\mathrm {T}}_{w}$
 when
$\mathcal {I}^{\mathrm {T}}_{w}$
 when 
 $w \leq q$
, and in this case, the result is valid. So in what follows, we assume that
$w \leq q$
, and in this case, the result is valid. So in what follows, we assume that 
 $\mathcal {I}^{\mathrm {ND}}_{w} \neq \mathcal {I}^{\mathrm {T}}_{w}$
.
$\mathcal {I}^{\mathrm {ND}}_{w} \neq \mathcal {I}^{\mathrm {T}}_{w}$
.
 Taking any 
 $\mathfrak {s} = (s_{1}, \ldots , s_{r}) \in \mathcal {I}^{\mathrm {ND}}_{w}$
 but
$\mathfrak {s} = (s_{1}, \ldots , s_{r}) \in \mathcal {I}^{\mathrm {ND}}_{w}$
 but 
 $\mathfrak {s} \notin \mathcal {I}^{\mathrm {T}}_{w}$
, based on (3.1) and the definition of
$\mathfrak {s} \notin \mathcal {I}^{\mathrm {T}}_{w}$
, based on (3.1) and the definition of 
 $\mathcal {I}^{\mathrm {ND}}_{w}$
, we write
$\mathcal {I}^{\mathrm {ND}}_{w}$
, we write 
 $\mathfrak {s} = (\mathfrak {s}^{\mathrm {T}}, q^{\{0\}}, \mathfrak {s}')$
 with
$\mathfrak {s} = (\mathfrak {s}^{\mathrm {T}}, q^{\{0\}}, \mathfrak {s}')$
 with 
 $\mathfrak {s}^{\mathrm {T}} \in \mathcal {I}^{\mathrm {T}}$
 (
$\mathfrak {s}^{\mathrm {T}} \in \mathcal {I}^{\mathrm {T}}$
 (
 $q^{\left \{ 0\right \}}:=\emptyset $
), and
$q^{\left \{ 0\right \}}:=\emptyset $
), and 
 $\mathfrak {s}' \neq \emptyset $
. Note that
$\mathfrak {s}' \neq \emptyset $
. Note that 
 $\mathfrak {s}'$
 is of the form:
$\mathfrak {s}'$
 is of the form: 
 $\mathfrak {s}' = (s^\prime _{1}, \ldots )$
 with
$\mathfrak {s}' = (s^\prime _{1}, \ldots )$
 with 
 $s^\prime _{1}> q$
. By definition (2.8),
$s^\prime _{1}> q$
. By definition (2.8), 
 $D^{\operatorname {\mathrm {Li}}}_{q, \mathfrak {s}"} = 0$
. Thus,
$D^{\operatorname {\mathrm {Li}}}_{q, \mathfrak {s}"} = 0$
. Thus, 
 $$ \begin{align} \mathscr{U}^{\operatorname{\mathrm{Li}}}(\mathfrak{s}) = - [\mathfrak{s}^{\mathrm{T}}, q, \mathfrak{s}"] + L_{1} [\mathfrak{s}^{\mathrm{T}}, \alpha_{q}^{\operatorname{\mathrm{Li}}}(\mathfrak{s}")] + L_{1} (\mathfrak{s}^{\mathrm{T}} \boxplus \alpha_{q}^{\operatorname{\mathrm{Li}}}(\mathfrak{s}")), \end{align} $$
$$ \begin{align} \mathscr{U}^{\operatorname{\mathrm{Li}}}(\mathfrak{s}) = - [\mathfrak{s}^{\mathrm{T}}, q, \mathfrak{s}"] + L_{1} [\mathfrak{s}^{\mathrm{T}}, \alpha_{q}^{\operatorname{\mathrm{Li}}}(\mathfrak{s}")] + L_{1} (\mathfrak{s}^{\mathrm{T}} \boxplus \alpha_{q}^{\operatorname{\mathrm{Li}}}(\mathfrak{s}")), \end{align} $$
where 
 $\mathfrak {s}" := (s^\prime _{1} - q, \mathfrak {s}^\prime _{-})$
. Thus, for each
$\mathfrak {s}" := (s^\prime _{1} - q, \mathfrak {s}^\prime _{-})$
. Thus, for each 
 $\mathfrak {s} = (m_{1} q + n_{1}, \ldots , m_{r} q + n_{r}) \in \mathcal {I}^{\mathrm {ND}}_{w}$
 with
$\mathfrak {s} = (m_{1} q + n_{1}, \ldots , m_{r} q + n_{r}) \in \mathcal {I}^{\mathrm {ND}}_{w}$
 with 
 $m_{i} \geq 0$
 (
$m_{i} \geq 0$
 (
 $m_{i}$
 are not all zero since
$m_{i}$
 are not all zero since 
 $\mathfrak {s}\notin \mathcal {I}^{\mathrm {T}}_{w}$
) and
$\mathfrak {s}\notin \mathcal {I}^{\mathrm {T}}_{w}$
) and 
 $1 \leq n_{i} \leq q - 1$
, we have
$1 \leq n_{i} \leq q - 1$
, we have 
 $$ \begin{align*} (\mathscr{U}^{\operatorname{\mathrm{Li}}})^{e}(\mathfrak{s}) &= (\mathscr{U}^{\operatorname{\mathrm{Li}}})^{e + m_{1} + \cdots + m_{r}}(\mathfrak{s}) \\ & \in (\mathscr{U}^{\operatorname{\mathrm{Li}}})^{e}\left((- 1)^{m_{1} + \cdots + m_{r}} [q^{\{ m_{1} \}}, n_{1}, \ldots, q^{\{ m_{r} \}}, n_{r}] + L_{1} \cdot \mathcal{H}_{w / \mathbb{F}_{p}[L_{1}]}\right) \\ &\subset (- 1)^{m_{1} + \cdots + m_{r}} [q^{\{ m_{1} \}}, n_{1}, \ldots, q^{\{ m_{r} \}}, n_{r}] + L_{1} \cdot \mathcal{H}^{\mathrm{T}}_{w / \mathbb{F}_{p}[L_{1}]}. \end{align*} $$
$$ \begin{align*} (\mathscr{U}^{\operatorname{\mathrm{Li}}})^{e}(\mathfrak{s}) &= (\mathscr{U}^{\operatorname{\mathrm{Li}}})^{e + m_{1} + \cdots + m_{r}}(\mathfrak{s}) \\ & \in (\mathscr{U}^{\operatorname{\mathrm{Li}}})^{e}\left((- 1)^{m_{1} + \cdots + m_{r}} [q^{\{ m_{1} \}}, n_{1}, \ldots, q^{\{ m_{r} \}}, n_{r}] + L_{1} \cdot \mathcal{H}_{w / \mathbb{F}_{p}[L_{1}]}\right) \\ &\subset (- 1)^{m_{1} + \cdots + m_{r}} [q^{\{ m_{1} \}}, n_{1}, \ldots, q^{\{ m_{r} \}}, n_{r}] + L_{1} \cdot \mathcal{H}^{\mathrm{T}}_{w / \mathbb{F}_{p}[L_{1}]}. \end{align*} $$
Note that the first identity above comes from the fact that 
 $(\mathscr {U}^{\operatorname {\mathrm {Li}}})^{e}(\mathfrak {s})\in \mathcal {H}^{\mathrm {T}}_{w / \mathbb {F}_{p}[L_{1}]}$
, which is fixed by
$(\mathscr {U}^{\operatorname {\mathrm {Li}}})^{e}(\mathfrak {s})\in \mathcal {H}^{\mathrm {T}}_{w / \mathbb {F}_{p}[L_{1}]}$
, which is fixed by 
 $(\mathscr {U}^{\operatorname {\mathrm {Li}}})^{m_{1} + \cdots + m_{r}}$
 by Remark 3.5. The second belonging follows from (3.4), whence we have the last inclusion because of
$(\mathscr {U}^{\operatorname {\mathrm {Li}}})^{m_{1} + \cdots + m_{r}}$
 by Remark 3.5. The second belonging follows from (3.4), whence we have the last inclusion because of 
 $(q^{\{ m_{1} \}}, n_{1}, \ldots , q^{\{ m_{r} \}}, n_{r}) \in \mathcal {I}^{\mathrm {T}}_{w}$
 and
$(q^{\{ m_{1} \}}, n_{1}, \ldots , q^{\{ m_{r} \}}, n_{r}) \in \mathcal {I}^{\mathrm {T}}_{w}$
 and 
 $ (\mathscr {U}^{\operatorname {\mathrm {Li}}})^{e} (\mathcal {H}_{w / \mathbb {F}_{p}[L_{1}]}) \subset \mathcal {H}^{\mathrm {T}}_{w / \mathbb {F}_{p}[L_{1}]}$
. Since
$ (\mathscr {U}^{\operatorname {\mathrm {Li}}})^{e} (\mathcal {H}_{w / \mathbb {F}_{p}[L_{1}]}) \subset \mathcal {H}^{\mathrm {T}}_{w / \mathbb {F}_{p}[L_{1}]}$
. Since 
 $$\begin{align*}(m_{1} q + n_{1}, \ldots, m_{r} q + n_{r}) \mapsto (q^{\{ m_{1} \}}, n_{1}, \ldots, q^{\{ m_{r} \}}, n_{r})\end{align*}$$
$$\begin{align*}(m_{1} q + n_{1}, \ldots, m_{r} q + n_{r}) \mapsto (q^{\{ m_{1} \}}, n_{1}, \ldots, q^{\{ m_{r} \}}, n_{r})\end{align*}$$
gives a bijection between 
 $\mathcal {I}^{\mathrm {ND}}_{w}$
 and
$\mathcal {I}^{\mathrm {ND}}_{w}$
 and 
 $\mathcal {I}^{\mathrm {T}}_{w}$
, we have
$\mathcal {I}^{\mathrm {T}}_{w}$
, we have 
 $\det (U \bmod L_{1}) = \pm 1$
 in
$\det (U \bmod L_{1}) = \pm 1$
 in 
 $\mathbb {F}_{p}$
. In particular,
$\mathbb {F}_{p}$
. In particular, 
 $\det (U) \neq 0$
.
$\det (U) \neq 0$
.
4 Frobenius difference equations
In this section, we focus on a specific system (E M ) of Frobenius difference equations arising from our study of MZV’s, and the major result is Theorem 4.8 giving the precise dimension of the solution space of (E M ).
4.1 ABP-criterion
 Let t be a new variable and 
 ${\mathbb {C}_{\infty } (\!( t )\!)}$
 be the field of Laurent series in t over
${\mathbb {C}_{\infty } (\!( t )\!)}$
 be the field of Laurent series in t over 
 $\mathbb {C}_{\infty }$
. For any integer n, we define the following n-fold Frobenious twisting:
$\mathbb {C}_{\infty }$
. For any integer n, we define the following n-fold Frobenious twisting: 
 $$\begin{align*}\tau^{n}:= \left(f\mapsto f^{(n)} \right): {\mathbb{C}_{\infty} (\!( t )\!)} \rightarrow {\mathbb{C}_{\infty} (\!( t )\!)}, \end{align*}$$
$$\begin{align*}\tau^{n}:= \left(f\mapsto f^{(n)} \right): {\mathbb{C}_{\infty} (\!( t )\!)} \rightarrow {\mathbb{C}_{\infty} (\!( t )\!)}, \end{align*}$$
where 
 $f^{(n)}:=\sum a_{i}^{q^{n}}t^{i}$
 for
$f^{(n)}:=\sum a_{i}^{q^{n}}t^{i}$
 for 
 $f=\sum a_{i}t^{i}\in {\mathbb {C}_{\infty } (\!( t )\!)}$
. We further extend
$f=\sum a_{i}t^{i}\in {\mathbb {C}_{\infty } (\!( t )\!)}$
. We further extend 
 $\tau ^{n}$
 to the action on
$\tau ^{n}$
 to the action on 
 $\operatorname {\mathrm {Mat}}_{r\times s}({\mathbb {C}_{\infty } (\!( t )\!)})$
 by entrywise action.
$\operatorname {\mathrm {Mat}}_{r\times s}({\mathbb {C}_{\infty } (\!( t )\!)})$
 by entrywise action.
 Note that as an automorphism of the field 
 ${\mathbb {C}_{\infty } (\!( t )\!)}$
,
${\mathbb {C}_{\infty } (\!( t )\!)}$
, 
 $\tau ^{n}$
 stabilizes several subrings such as the power series ring
$\tau ^{n}$
 stabilizes several subrings such as the power series ring 
 ${\mathbb {C}_{\infty } [\![ t ]\!]}$
, the Tate algebra
${\mathbb {C}_{\infty } [\![ t ]\!]}$
, the Tate algebra 
 $$\begin{align*}\mathbb{T}:=\left\{f\in {\mathbb{C}_{\infty} [\![ t ]\!]}| f\text{ converges on }|t|_{\infty}\leq 1 \right\}\end{align*}$$
$$\begin{align*}\mathbb{T}:=\left\{f\in {\mathbb{C}_{\infty} [\![ t ]\!]}| f\text{ converges on }|t|_{\infty}\leq 1 \right\}\end{align*}$$
and the polynomial rings 
 $\mathbb {C}_{\infty }[t], \overline {k}[t]$
 as well as the subfields
$\mathbb {C}_{\infty }[t], \overline {k}[t]$
 as well as the subfields 
 $\mathbb {C}_{\infty }(t)$
 and
$\mathbb {C}_{\infty }(t)$
 and 
 $\overline {k}(t)$
. When
$\overline {k}(t)$
. When 
 $n=-1$
, we denote by
$n=-1$
, we denote by 
 $\sigma := \tau ^{-1}$
. For
$\sigma := \tau ^{-1}$
. For 
 $n\in \left \{1,-1 \right \}$
, the following fixed elements are particularly used in this paper:
$n\in \left \{1,-1 \right \}$
, the following fixed elements are particularly used in this paper: 
 $$\begin{align*}\mathbb{T}^{\tau}=\overline{k}[t]^{\tau}=\mathbb{F}_{q}[t]=\mathbb{T}^{\sigma}=\overline{k}[t]^{\sigma} \text{ and }\overline{k}(t)^{\tau}=\mathbb{F}_{q}(t)=\overline{k}(t)^{\sigma}. \end{align*}$$
$$\begin{align*}\mathbb{T}^{\tau}=\overline{k}[t]^{\tau}=\mathbb{F}_{q}[t]=\mathbb{T}^{\sigma}=\overline{k}[t]^{\sigma} \text{ and }\overline{k}(t)^{\tau}=\mathbb{F}_{q}(t)=\overline{k}(t)^{\sigma}. \end{align*}$$
 Following [Reference Anderson, Brownawell and Papanikolas2], we denote by 
 $\mathcal {E}\subset {\mathbb {C}_{\infty } [\![ t ]\!]}$
 the subring consisting of power series
$\mathcal {E}\subset {\mathbb {C}_{\infty } [\![ t ]\!]}$
 the subring consisting of power series 
 $f=\sum _{i=0}^{\infty }a_{i}t^{i}$
 with algebraic coefficients (
$f=\sum _{i=0}^{\infty }a_{i}t^{i}$
 with algebraic coefficients (
 $a_{i}\in \overline {k}$
,
$a_{i}\in \overline {k}$
, 
 $\forall i\in \mathbb {Z}_{\geq 0}$
) for which
$\forall i\in \mathbb {Z}_{\geq 0}$
) for which 
 $$\begin{align*}\lim_{i\rightarrow \infty} \sqrt[i]{|a_{i}|_{\infty}}=0\text{ and }[k_{\infty}\left(a_{0},a_{1},\ldots \right):k_{\infty} ]<\infty .\end{align*}$$
$$\begin{align*}\lim_{i\rightarrow \infty} \sqrt[i]{|a_{i}|_{\infty}}=0\text{ and }[k_{\infty}\left(a_{0},a_{1},\ldots \right):k_{\infty} ]<\infty .\end{align*}$$
It follows that such any power series in 
 $\mathcal {E}$
 converges on whole
$\mathcal {E}$
 converges on whole 
 $\mathbb {C}_{\infty }$
, and we have
$\mathbb {C}_{\infty }$
, and we have 
 $$\begin{align*}\mathcal{E}^{\tau}=\mathbb{F}_{q}[t]=\mathcal{E}^{\sigma}.\end{align*}$$
$$\begin{align*}\mathcal{E}^{\tau}=\mathbb{F}_{q}[t]=\mathcal{E}^{\sigma}.\end{align*}$$
The primary tool that we use in this paper to show linear independence results is the following ABP-criterion
Theorem 4.1 [Reference Anderson, Brownawell and Papanikolas2, Theorem 3.1.1].
 Let 
 $\Phi \in \operatorname {\mathrm {Mat}}_{\ell }(\overline {k}[t])$
 be a matrix satisfying that as a polynomial in
$\Phi \in \operatorname {\mathrm {Mat}}_{\ell }(\overline {k}[t])$
 be a matrix satisfying that as a polynomial in 
 $\overline {k}[t]$
,
$\overline {k}[t]$
, 
 $\det \Phi $
 vanishes only (if at all) at
$\det \Phi $
 vanishes only (if at all) at 
 $t=\theta $
. Suppose that a column vector
$t=\theta $
. Suppose that a column vector 
 $\psi =\psi (t)\in \operatorname {\mathrm {Mat}}_{\ell \times 1}(\mathcal {E})$
 satisfies the following difference equation
$\psi =\psi (t)\in \operatorname {\mathrm {Mat}}_{\ell \times 1}(\mathcal {E})$
 satisfies the following difference equation 
 $$\begin{align*}\psi^{(-1)}=\Phi \psi .\end{align*}$$
$$\begin{align*}\psi^{(-1)}=\Phi \psi .\end{align*}$$
We denote by 
 $\psi (\theta )\in \operatorname {\mathrm {Mat}}_{\ell \times 1}(\mathbb {C}_{\infty })$
 the evaluation of
$\psi (\theta )\in \operatorname {\mathrm {Mat}}_{\ell \times 1}(\mathbb {C}_{\infty })$
 the evaluation of 
 $\psi $
 at
$\psi $
 at 
 $t=\theta $
. Then for any row vector
$t=\theta $
. Then for any row vector 
 $\rho \in \operatorname {\mathrm {Mat}}_{1\times \ell }(\overline {k})$
 for which
$\rho \in \operatorname {\mathrm {Mat}}_{1\times \ell }(\overline {k})$
 for which 
 $$\begin{align*}\rho \psi(\theta)=0,\end{align*}$$
$$\begin{align*}\rho \psi(\theta)=0,\end{align*}$$
there exists a row vector
 
such that

 The spirit of ABP-criterion asserts any 
 $\overline {k}$
-linear relation among the entries of
$\overline {k}$
-linear relation among the entries of 
 $\psi (\theta )$
 can be lifted to a
$\psi (\theta )$
 can be lifted to a 
 $\overline {k}[t]$
-linear relation among the entries of
$\overline {k}[t]$
-linear relation among the entries of 
 $\psi $
. We mention that the condition on
$\psi $
. We mention that the condition on 
 $\Phi $
 in the theorem above arises from dual t-motives and refer the reader to [Reference Anderson, Brownawell and Papanikolas2, Reference Papanikolas27] and [Reference Anderson1] also.
$\Phi $
 in the theorem above arises from dual t-motives and refer the reader to [Reference Anderson, Brownawell and Papanikolas2, Reference Papanikolas27] and [Reference Anderson1] also.
4.2 Some lemmas
 For each 
 $\mathfrak {s} = (s_{1}, \ldots , s_{r}) \in \mathcal {I}$
 and
$\mathfrak {s} = (s_{1}, \ldots , s_{r}) \in \mathcal {I}$
 and 
 $M \subset \mathcal {I}$
, we set
$M \subset \mathcal {I}$
, we set 
 $$ \begin{align*} \mathscr{I}(\mathfrak{s}) := \{ \emptyset, (s_{1}), (s_{1}, s_{2}), \ldots, (s_{1}, \ldots, s_{r}) \} \ \ \mathrm{and} \ \ \mathscr{I}(M) := \bigcup_{\mathfrak{s} \in M} \mathscr{I}(\mathfrak{s}). \end{align*} $$
$$ \begin{align*} \mathscr{I}(\mathfrak{s}) := \{ \emptyset, (s_{1}), (s_{1}, s_{2}), \ldots, (s_{1}, \ldots, s_{r}) \} \ \ \mathrm{and} \ \ \mathscr{I}(M) := \bigcup_{\mathfrak{s} \in M} \mathscr{I}(\mathfrak{s}). \end{align*} $$
Throughout this paper, we denote by
 
 the following 
 $\mathbb {F}_{q}(t)$
-algebra:
$\mathbb {F}_{q}(t)$
-algebra: 

For any finite nonempty set J, it is understood that
 
 refers to the 
 $\mathbb {F}_{q}(t)$
-vector space
$\mathbb {F}_{q}(t)$
-vector space 
 
 and any element of 
 ${R}^{J}$
 is written in the form
${R}^{J}$
 is written in the form 
 $(r_x)_{x\in J}$
 with
$(r_x)_{x\in J}$
 with 
 
.
 Given any nonempty subset 
 $M \subset \mathcal {I}_{w}$
 for some
$M \subset \mathcal {I}_{w}$
 for some 
 $w \geq 0$
, we consider the system of Frobenius equations
$w \geq 0$
, we consider the system of Frobenius equations 
 $$\begin{align} \varepsilon_{\mathfrak{s}}^{(1)} = \varepsilon_{\mathfrak{s}} (t - \theta)^{w - \operatorname{\mathrm{wt}}(\mathfrak{s})} + \sum_{\substack{s'> 0 \\ (\mathfrak{s}, s') \in \mathscr{I}(M)}} \varepsilon_{(\mathfrak{s}, s')} (t - \theta)^{w - \operatorname{\mathrm{wt}}(\mathfrak{s})} \ \ (\mathfrak{s} \in \mathscr{I}(M)) \end{align}$$
$$\begin{align} \varepsilon_{\mathfrak{s}}^{(1)} = \varepsilon_{\mathfrak{s}} (t - \theta)^{w - \operatorname{\mathrm{wt}}(\mathfrak{s})} + \sum_{\substack{s'> 0 \\ (\mathfrak{s}, s') \in \mathscr{I}(M)}} \varepsilon_{(\mathfrak{s}, s')} (t - \theta)^{w - \operatorname{\mathrm{wt}}(\mathfrak{s})} \ \ (\mathfrak{s} \in \mathscr{I}(M)) \end{align}$$
with 
 . We mention that (E
M
) is basically the case of
. We mention that (E
M
) is basically the case of 
 $Q_i=1$
 from [Reference Chang, Papanikolas and Yu14, (3.1.3)], which is derived from the study of establishing a criterion for the zeta-like MZV’s. Note that our
$Q_i=1$
 from [Reference Chang, Papanikolas and Yu14, (3.1.3)], which is derived from the study of establishing a criterion for the zeta-like MZV’s. Note that our 
 $\varepsilon _{\mathfrak {s}}$
 is essentially referring to
$\varepsilon _{\mathfrak {s}}$
 is essentially referring to 
 $\delta _i^{(-1)}$
 used in [Reference Chang, Papanikolas and Yu14, (3.1.3)] (with
$\delta _i^{(-1)}$
 used in [Reference Chang, Papanikolas and Yu14, (3.1.3)] (with 
 $Q_{i}=1$
 in [Reference Chang, Papanikolas and Yu14]), but we follow [Reference Ngo Dac26] to express (E
M
) with subscripts parameterized by indices. See also [Reference Ngo Dac26, (6.3), (6.4)] in the depth two case.
$Q_{i}=1$
 in [Reference Chang, Papanikolas and Yu14]), but we follow [Reference Ngo Dac26] to express (E
M
) with subscripts parameterized by indices. See also [Reference Ngo Dac26, (6.3), (6.4)] in the depth two case.
Remark 4.2. Note that if 
 $w=0$
, we have
$w=0$
, we have 
 $M=\mathcal {I}_{0}=\left \{\emptyset \right \}$
 and so
$M=\mathcal {I}_{0}=\left \{\emptyset \right \}$
 and so 
 $\mathscr {I}(M)=\left \{ \emptyset \right \}$
. In this special case, the equation (E
M
) becomes
$\mathscr {I}(M)=\left \{ \emptyset \right \}$
. In this special case, the equation (E
M
) becomes 
 $\varepsilon _{\emptyset }^{(1)}=\varepsilon _{\emptyset }$
.
$\varepsilon _{\emptyset }^{(1)}=\varepsilon _{\emptyset }$
.
Lemma 4.3. Let 
 $F = \sum _{i = 0}^{n} f_{i} t^{i}, G \in A[t]$
 be polynomials over A such that
$F = \sum _{i = 0}^{n} f_{i} t^{i}, G \in A[t]$
 be polynomials over A such that 
 $n = \deg _{t} F \geq 1$
 and
$n = \deg _{t} F \geq 1$
 and 
 $f_{n} \in \mathbb {F}_{q}^{\times }$
. If
$f_{n} \in \mathbb {F}_{q}^{\times }$
. If 
 satisfies
 satisfies 
 $\varepsilon ^{(1)} = \varepsilon F + G$
, then we have
$\varepsilon ^{(1)} = \varepsilon F + G$
, then we have 
 $\varepsilon \in \mathbb {F}_{q}(t)[\theta ]$
.
$\varepsilon \in \mathbb {F}_{q}(t)[\theta ]$
.
Proof. Our method is inspired by H.-J. Chen’s formulation in the proof of [Reference Kuan and Lin24, Thm. 2 (a)] (see Step I of the proof of [Reference Chang10, Thm. 6.1.1] also). By multiplying the denominator of 
 $\varepsilon $
 on the equation, without loss of generality we assume that
$\varepsilon $
 on the equation, without loss of generality we assume that 
 $\varepsilon \in \overline {k}[t] \setminus \{ 0 \}$
. We put
$\varepsilon \in \overline {k}[t] \setminus \{ 0 \}$
. We put 
 $m := \deg _{t} \varepsilon \geq 0$
. Since
$m := \deg _{t} \varepsilon \geq 0$
. Since 
 $\deg _{t} \varepsilon ^{(1)} = \deg _{t} \varepsilon < \deg _{t} (\varepsilon F)$
, we have
$\deg _{t} \varepsilon ^{(1)} = \deg _{t} \varepsilon < \deg _{t} (\varepsilon F)$
, we have 
 $\deg _{t} G = m + n$
. We set
$\deg _{t} G = m + n$
. We set 
 $$ \begin{align*} \varepsilon = \sum_{i = 0}^{m} a_{i} t^{i} \ (a_{i} \in \overline{k}) \ \ \mathrm{and} \ \ G = \sum_{i = 0}^{m + n} g_{i} t^{i} \ (g_{i} \in A). \end{align*} $$
$$ \begin{align*} \varepsilon = \sum_{i = 0}^{m} a_{i} t^{i} \ (a_{i} \in \overline{k}) \ \ \mathrm{and} \ \ G = \sum_{i = 0}^{m + n} g_{i} t^{i} \ (g_{i} \in A). \end{align*} $$
Moreover, we set 
 $a_{i} := 0$
 (resp.
$a_{i} := 0$
 (resp. 
 $f_{i} := 0$
) when i does not satisfy
$f_{i} := 0$
) when i does not satisfy 
 $0 \leq i \leq m$
 (resp.
$0 \leq i \leq m$
 (resp. 
 $0 \leq i \leq n$
). Then we have
$0 \leq i \leq n$
). Then we have 
 $$ \begin{align*} \sum_{i = 0}^{m} a_{i}^{q} t^{i} = \sum_{j = 0}^{m} a_{j} t^{j} \sum_{\ell = 0}^{n} f_{\ell} t^{\ell} + \sum_{i = 0}^{m + n} g_{i} t^{i} = \sum_{i = 0}^{m + n} \sum_{j + \ell = i} a_{j} f_{\ell} t^{i} + \sum_{i = 0}^{m + n} g_{i} t^{i}. \end{align*} $$
$$ \begin{align*} \sum_{i = 0}^{m} a_{i}^{q} t^{i} = \sum_{j = 0}^{m} a_{j} t^{j} \sum_{\ell = 0}^{n} f_{\ell} t^{\ell} + \sum_{i = 0}^{m + n} g_{i} t^{i} = \sum_{i = 0}^{m + n} \sum_{j + \ell = i} a_{j} f_{\ell} t^{i} + \sum_{i = 0}^{m + n} g_{i} t^{i}. \end{align*} $$
By comparing the coefficients of 
 $t^{i}$
 for
$t^{i}$
 for 
 $m + 1 \leq i \leq m + n$
, we have
$m + 1 \leq i \leq m + n$
, we have 
 $$ \begin{align*} a_{i - n} f_{n} = - g_{i} - \sum_{j> i - n} a_{j} f_{i - j}. \end{align*} $$
$$ \begin{align*} a_{i - n} f_{n} = - g_{i} - \sum_{j> i - n} a_{j} f_{i - j}. \end{align*} $$
Then we can show that 
 $a_{m}, a_{m - 1}, \ldots , a_{m + 1 - n} \in A$
 inductively.
$a_{m}, a_{m - 1}, \ldots , a_{m + 1 - n} \in A$
 inductively.
 Suppose that 
 $m + 1 - n \geq 1 (\Leftrightarrow m \geq n)$
. Then by comparing the coefficients of
$m + 1 - n \geq 1 (\Leftrightarrow m \geq n)$
. Then by comparing the coefficients of 
 $t^{i}$
 for
$t^{i}$
 for 
 $n \leq i \leq m$
, we have
$n \leq i \leq m$
, we have 
 $$ \begin{align*} a_{i - n} f_{n} = a_{i}^{q} - g_{i} - \sum_{j> i - n} a_{j} f_{i - j}. \end{align*} $$
$$ \begin{align*} a_{i - n} f_{n} = a_{i}^{q} - g_{i} - \sum_{j> i - n} a_{j} f_{i - j}. \end{align*} $$
Then we can show that 
 $a_{m - n}, a_{m - n - 1}, \ldots , a_{0} \in A$
 inductively. Therefore, in any case, we have
$a_{m - n}, a_{m - n - 1}, \ldots , a_{0} \in A$
 inductively. Therefore, in any case, we have 
 $\varepsilon \in A[t]$
.
$\varepsilon \in A[t]$
.
 The next lemma can be viewed as an improvement of Step II of [Reference Chang10, Thm. 6.1.1] and [Reference Kuan and Lin24, Thm. 2 (b)] which gives a better upper bound for the degree of solutions 
 satisfying (E
M
).
 satisfying (E
M
).
Lemma 4.4. Let 
 $w \geq 0$
 and
$w \geq 0$
 and 
 $\emptyset \neq M \subset \mathcal {I}_{w}$
. If
$\emptyset \neq M \subset \mathcal {I}_{w}$
. If 
 satisfies (E
M
)
 satisfies (E
M
) 
 $$ \begin{align*} \varepsilon_{\mathfrak{s}}^{(1)} = \varepsilon_{\mathfrak{s}} (t - \theta)^{w - \operatorname{\mathrm{wt}}(\mathfrak{s})} + \sum_{\substack{s'> 0 \\ (\mathfrak{s}, s') \in \mathscr{I}(M)}} \varepsilon_{(\mathfrak{s}, s')} (t - \theta)^{w - \operatorname{\mathrm{wt}}(\mathfrak{s})} \ \ (\mathfrak{s} \in \mathscr{I}(M)), \end{align*} $$
$$ \begin{align*} \varepsilon_{\mathfrak{s}}^{(1)} = \varepsilon_{\mathfrak{s}} (t - \theta)^{w - \operatorname{\mathrm{wt}}(\mathfrak{s})} + \sum_{\substack{s'> 0 \\ (\mathfrak{s}, s') \in \mathscr{I}(M)}} \varepsilon_{(\mathfrak{s}, s')} (t - \theta)^{w - \operatorname{\mathrm{wt}}(\mathfrak{s})} \ \ (\mathfrak{s} \in \mathscr{I}(M)), \end{align*} $$
then we have 
 $\varepsilon _{\mathfrak {s}} \in \mathbb {F}_{q}(t)[\theta ]$
 and
$\varepsilon _{\mathfrak {s}} \in \mathbb {F}_{q}(t)[\theta ]$
 and 
 $\deg _{\theta } \varepsilon _{\mathfrak {s}} \leq \dfrac {w - \operatorname {\mathrm {wt}}(\mathfrak {s})}{q - 1}$
 for each
$\deg _{\theta } \varepsilon _{\mathfrak {s}} \leq \dfrac {w - \operatorname {\mathrm {wt}}(\mathfrak {s})}{q - 1}$
 for each 
 $\mathfrak {s} \in \mathscr {I}(M)$
.
$\mathfrak {s} \in \mathscr {I}(M)$
.
Proof. When 
 $\mathfrak {s} \in M$
, then we have
$\mathfrak {s} \in M$
, then we have 
 $\varepsilon _{\mathfrak {s}} \in \mathbb {F}_{q}(t)$
 since in this case,
$\varepsilon _{\mathfrak {s}} \in \mathbb {F}_{q}(t)$
 since in this case, 
 $\varepsilon _{\mathfrak {s}}^{(1)}=\varepsilon _{\mathfrak {s}}$
. Thus, the statements are clearly valid. By Lemma 4.3 and the induction on
$\varepsilon _{\mathfrak {s}}^{(1)}=\varepsilon _{\mathfrak {s}}$
. Thus, the statements are clearly valid. By Lemma 4.3 and the induction on 
 $w - \operatorname {\mathrm {wt}}(\mathfrak {s})$
, we have
$w - \operatorname {\mathrm {wt}}(\mathfrak {s})$
, we have 
 $\varepsilon _{\mathfrak {s}} \in \mathbb {F}_{q}(t)[\theta ]$
 for all
$\varepsilon _{\mathfrak {s}} \in \mathbb {F}_{q}(t)[\theta ]$
 for all 
 $\mathfrak {s} \in \mathscr {I}(M)$
. We now consider
$\mathfrak {s} \in \mathscr {I}(M)$
. We now consider 
 $\mathfrak {s} \in \mathscr {I}(M) \setminus M$
 and suppose that
$\mathfrak {s} \in \mathscr {I}(M) \setminus M$
 and suppose that 
 $\deg _{\theta } \varepsilon _{(\mathfrak {s}, s')} \leq \dfrac {w - \operatorname {\mathrm {wt}}(\mathfrak {s}, s)}{q - 1}$
 for all
$\deg _{\theta } \varepsilon _{(\mathfrak {s}, s')} \leq \dfrac {w - \operatorname {\mathrm {wt}}(\mathfrak {s}, s)}{q - 1}$
 for all 
 $s'> 0$
 with
$s'> 0$
 with 
 $(\mathfrak {s}, s') \in \mathscr {I}(M)$
.
$(\mathfrak {s}, s') \in \mathscr {I}(M)$
.
 Suppose on the contrary that 
 $\deg _{\theta } \varepsilon _{\mathfrak {s}}> \dfrac {w - \operatorname {\mathrm {wt}}(\mathfrak {s})}{q - 1}$
. Then we have
$\deg _{\theta } \varepsilon _{\mathfrak {s}}> \dfrac {w - \operatorname {\mathrm {wt}}(\mathfrak {s})}{q - 1}$
. Then we have 
 $\deg _{\theta } \varepsilon _{\mathfrak {s}}^{(1)}> \dfrac {q (w - \operatorname {\mathrm {wt}}(\mathfrak {s}))}{q - 1}$
. However, the induction hypothesis implies
$\deg _{\theta } \varepsilon _{\mathfrak {s}}^{(1)}> \dfrac {q (w - \operatorname {\mathrm {wt}}(\mathfrak {s}))}{q - 1}$
. However, the induction hypothesis implies 
 $$ \begin{align*} \deg_{\theta} (\varepsilon_{(\mathfrak{s}, s')} (t - \theta)^{w - \operatorname{\mathrm{wt}}(\mathfrak{s})}) \leq \dfrac{w - \operatorname{\mathrm{wt}}(\mathfrak{s}, s')}{q - 1} + w - \operatorname{\mathrm{wt}}(\mathfrak{s}) < \dfrac{q (w - \operatorname{\mathrm{wt}}(\mathfrak{s}))}{q - 1}. \end{align*} $$
$$ \begin{align*} \deg_{\theta} (\varepsilon_{(\mathfrak{s}, s')} (t - \theta)^{w - \operatorname{\mathrm{wt}}(\mathfrak{s})}) \leq \dfrac{w - \operatorname{\mathrm{wt}}(\mathfrak{s}, s')}{q - 1} + w - \operatorname{\mathrm{wt}}(\mathfrak{s}) < \dfrac{q (w - \operatorname{\mathrm{wt}}(\mathfrak{s}))}{q - 1}. \end{align*} $$
It follows that 
 $\deg _{\theta } \varepsilon _{\mathfrak {s}}^{(1)} = \deg _{\theta } (\varepsilon _{\mathfrak {s}} (t - \theta )^{w - \operatorname {\mathrm {wt}}(\mathfrak {s})})$
, and hence
$\deg _{\theta } \varepsilon _{\mathfrak {s}}^{(1)} = \deg _{\theta } (\varepsilon _{\mathfrak {s}} (t - \theta )^{w - \operatorname {\mathrm {wt}}(\mathfrak {s})})$
, and hence 
 $\deg _{\theta } \varepsilon _{\mathfrak {s}} = \dfrac {w - \operatorname {\mathrm {wt}}(\mathfrak {s})}{q - 1}$
, which is a contradiction.
$\deg _{\theta } \varepsilon _{\mathfrak {s}} = \dfrac {w - \operatorname {\mathrm {wt}}(\mathfrak {s})}{q - 1}$
, which is a contradiction.
4.3 Dimension of 
 $\mathscr {X}_{w}$
$\mathscr {X}_{w}$
 For 
 $w\in \mathbb {Z}_{w\geq 0}$
, we define
$w\in \mathbb {Z}_{w\geq 0}$
, we define 
 $\mathcal {I}^{\mathrm {ND}_{0}}_{w} \subset \mathcal {I}^{\mathrm {ND}}_{w}$
 as follows:
$\mathcal {I}^{\mathrm {ND}_{0}}_{w} \subset \mathcal {I}^{\mathrm {ND}}_{w}$
 as follows: 
 $$ \begin{align} \mathcal{I}^{\mathrm{ND}_{0}}_{w} = \left\{ \begin{array}{@{}ll} \left\{\emptyset\right\} & \mathrm{if} \ w=0 \\ \left\{ (s_{1},\ldots,s_{r})\in \mathcal{I}^{\mathrm{ND}}_{w}|s_{2},\ldots,s_{r} \text{ are divisible by }q-1 \right\} & \mathrm{if} \ w>0 \end{array} \right. \end{align} $$
$$ \begin{align} \mathcal{I}^{\mathrm{ND}_{0}}_{w} = \left\{ \begin{array}{@{}ll} \left\{\emptyset\right\} & \mathrm{if} \ w=0 \\ \left\{ (s_{1},\ldots,s_{r})\in \mathcal{I}^{\mathrm{ND}}_{w}|s_{2},\ldots,s_{r} \text{ are divisible by }q-1 \right\} & \mathrm{if} \ w>0 \end{array} \right. \end{align} $$
Note that the description of indices in 
 $\mathcal {I}^{\mathrm {ND}_{0}}_{w}$
 comes from the simultaneously Eulerian phenomenon in [Reference Chang, Papanikolas and Yu14, Cor. 4.2.3]. For each
$\mathcal {I}^{\mathrm {ND}_{0}}_{w}$
 comes from the simultaneously Eulerian phenomenon in [Reference Chang, Papanikolas and Yu14, Cor. 4.2.3]. For each 
 $w \geq 0$
, we consider the system of Frobenius equations (E
M
) for
$w \geq 0$
, we consider the system of Frobenius equations (E
M
) for 
 $M = \mathcal {I}^{\mathrm {ND}_{0}}_{w}$
:
$M = \mathcal {I}^{\mathrm {ND}_{0}}_{w}$
: 
 $$\begin{align} \varepsilon_{\mathfrak{s}}^{(1)} = \varepsilon_{\mathfrak{s}} (t - \theta)^{w - \operatorname{\mathrm{wt}}(\mathfrak{s})} + \sum_{\substack{s'> 0 \\ (\mathfrak{s}, s') \in \mathscr{I}(\mathcal{I}^{\mathrm{ND}_{0}}_{w})}} \varepsilon_{(\mathfrak{s}, s')} (t - \theta)^{w - \operatorname{\mathrm{wt}}(\mathfrak{s})} \ \ (\mathfrak{s} \in \mathscr{I}(\mathcal{I}^{\mathrm{ND}_{0}}_{w})) \end{align} $$
$$\begin{align} \varepsilon_{\mathfrak{s}}^{(1)} = \varepsilon_{\mathfrak{s}} (t - \theta)^{w - \operatorname{\mathrm{wt}}(\mathfrak{s})} + \sum_{\substack{s'> 0 \\ (\mathfrak{s}, s') \in \mathscr{I}(\mathcal{I}^{\mathrm{ND}_{0}}_{w})}} \varepsilon_{(\mathfrak{s}, s')} (t - \theta)^{w - \operatorname{\mathrm{wt}}(\mathfrak{s})} \ \ (\mathfrak{s} \in \mathscr{I}(\mathcal{I}^{\mathrm{ND}_{0}}_{w})) \end{align} $$
with 
 . We emphasize that
. We emphasize that 
 $(E_{w}) = (E_{\mathcal {I}^{\mathrm {ND}_{0}}_{w}})$
 but
$(E_{w}) = (E_{\mathcal {I}^{\mathrm {ND}_{0}}_{w}})$
 but 
 $(E_{w}) \neq (E_{\{w\}})$
.
$(E_{w}) \neq (E_{\{w\}})$
.
Example 4.5. We give some explicit examples for the system of Frobenius equations (E
w
). The simplest example is the case 
 $w=0$
. We note that
$w=0$
. We note that 
 $\mathcal {I}^{\mathrm {ND}_{0}}_0=\mathscr {I}(\mathcal {I}^{\mathrm {ND}_{0}}_0)=\{\emptyset \}$
. Thus, (E
w
) consists of a single equation
$\mathcal {I}^{\mathrm {ND}_{0}}_0=\mathscr {I}(\mathcal {I}^{\mathrm {ND}_{0}}_0)=\{\emptyset \}$
. Thus, (E
w
) consists of a single equation 
 $$\begin{align*}\varepsilon_{\emptyset}^{(1)} = \varepsilon_{\emptyset}. \end{align*}$$
$$\begin{align*}\varepsilon_{\emptyset}^{(1)} = \varepsilon_{\emptyset}. \end{align*}$$
 The second example is the case 
 $w=q$
. In this case,
$w=q$
. In this case, 
 $\mathcal {I}^{\mathrm {ND}_{0}}_{q}=\{(1,q-1)\}$
 and
$\mathcal {I}^{\mathrm {ND}_{0}}_{q}=\{(1,q-1)\}$
 and 
 $$ \begin{align*} \mathscr{I}(\mathcal{I}^{\mathrm{ND}_{0}}_{q})=\{\emptyset,(1),(1,q-1)\}. \end{align*} $$
$$ \begin{align*} \mathscr{I}(\mathcal{I}^{\mathrm{ND}_{0}}_{q})=\{\emptyset,(1),(1,q-1)\}. \end{align*} $$
Thus, (E w ) consists of three equations
 $$ \begin{align*} \left\{ \begin{array}{@{}ll} \varepsilon_{(1,q-1)}^{(1)} &= \varepsilon_{(1,q-1)}\\ \varepsilon_{(1)}^{(1)} &= \varepsilon_{(1)} (t - \theta)^{q-1}+\varepsilon_{(1,q-1)}(t-\theta)^{q-1}\\ \varepsilon_{\emptyset}^{(1)} &= \varepsilon_{\emptyset} (t - \theta)^{q}+\varepsilon_{(1)}(t-\theta)^{q}. \end{array} \right. \end{align*} $$
$$ \begin{align*} \left\{ \begin{array}{@{}ll} \varepsilon_{(1,q-1)}^{(1)} &= \varepsilon_{(1,q-1)}\\ \varepsilon_{(1)}^{(1)} &= \varepsilon_{(1)} (t - \theta)^{q-1}+\varepsilon_{(1,q-1)}(t-\theta)^{q-1}\\ \varepsilon_{\emptyset}^{(1)} &= \varepsilon_{\emptyset} (t - \theta)^{q}+\varepsilon_{(1)}(t-\theta)^{q}. \end{array} \right. \end{align*} $$
 The third example is the case 
 $w=2q-2$
 with
$w=2q-2$
 with 
 $q \geq 3$
. Since
$q \geq 3$
. Since 
 $\mathcal {I}^{\mathrm {ND}_{0}}_{2q-2}=\{(q-1,q-1),(2q-2)\}$
, we have
$\mathcal {I}^{\mathrm {ND}_{0}}_{2q-2}=\{(q-1,q-1),(2q-2)\}$
, we have 
 $$\begin{align*}\mathscr{I}(\mathcal{I}^{\mathrm{ND}_{0}}_{2q-2})=\{\emptyset,(q-1),(q-1,q-1),(2q-2)\}. \end{align*}$$
$$\begin{align*}\mathscr{I}(\mathcal{I}^{\mathrm{ND}_{0}}_{2q-2})=\{\emptyset,(q-1),(q-1,q-1),(2q-2)\}. \end{align*}$$
Then (E w ) consists of four equations
 $$ \begin{align*} \left\{ \begin{array}{@{}ll} \varepsilon_{(2q-2)}^{(1)} &= \varepsilon_{(2q-2)}\\ \varepsilon_{(q-1,q-1)}^{(1)} &= \varepsilon_{(q-1,q-1)}\\ \varepsilon_{(q-1)}^{(1)} &= \varepsilon_{(q-1)} (t - \theta)^{q-1}+\varepsilon_{(q-1,q-1)}(t-\theta)^{q-1}\\ \varepsilon_{\emptyset}^{(1)} &= \varepsilon_{\emptyset} (t - \theta)^{2q-2}+\varepsilon_{(q-1)}(t-\theta)^{2q-2}+\varepsilon_{(2q-2)}(t-\theta)^{2q-2}. \end{array} \right. \end{align*} $$
$$ \begin{align*} \left\{ \begin{array}{@{}ll} \varepsilon_{(2q-2)}^{(1)} &= \varepsilon_{(2q-2)}\\ \varepsilon_{(q-1,q-1)}^{(1)} &= \varepsilon_{(q-1,q-1)}\\ \varepsilon_{(q-1)}^{(1)} &= \varepsilon_{(q-1)} (t - \theta)^{q-1}+\varepsilon_{(q-1,q-1)}(t-\theta)^{q-1}\\ \varepsilon_{\emptyset}^{(1)} &= \varepsilon_{\emptyset} (t - \theta)^{2q-2}+\varepsilon_{(q-1)}(t-\theta)^{2q-2}+\varepsilon_{(2q-2)}(t-\theta)^{2q-2}. \end{array} \right. \end{align*} $$
Definition 4.6. For each 
 $w\in \mathbb {Z}_{\geq 0}$
, we let
$w\in \mathbb {Z}_{\geq 0}$
, we let 
 $\mathscr {X}_{w}$
 be the set of
$\mathscr {X}_{w}$
 be the set of 
 -valued solutions of (E
w
).
-valued solutions of (E
w
).
Remark 4.7. Since 
 $f^{(1)}=f$
 for any
$f^{(1)}=f$
 for any 
 , we see that
, we see that 
 $\mathscr {X}_{w}$
 forms an
$\mathscr {X}_{w}$
 forms an 
 $\mathbb {F}_{q}(t)$
-vector subspace of
$\mathbb {F}_{q}(t)$
-vector subspace of 
 .
.
 The main result of this section is the following dimension formula for 
 $\mathscr {X}_{w}$
.
$\mathscr {X}_{w}$
.
Theorem 4.8. For any 
 $w\in \mathbb {Z}_{\geq 0}$
, we have
$w\in \mathbb {Z}_{\geq 0}$
, we have 
 $$\begin{align*}\dim_{\mathbb{F}_{q}(t)} \mathscr{X}_{w} = \left\{ \begin{array}{@{}ll} 1 & \textit{if} \ (q - 1) \mid w \\ 0 & \textit{if} \ (q - 1) \nmid w \end{array}. \right.\end{align*}$$
$$\begin{align*}\dim_{\mathbb{F}_{q}(t)} \mathscr{X}_{w} = \left\{ \begin{array}{@{}ll} 1 & \textit{if} \ (q - 1) \mid w \\ 0 & \textit{if} \ (q - 1) \nmid w \end{array}. \right.\end{align*}$$
When 
 $w = \ell (q - 1)$
 for some
$w = \ell (q - 1)$
 for some 
 $\ell \in \mathbb {Z}_{\geq 0}$
, we can choose a generator
$\ell \in \mathbb {Z}_{\geq 0}$
, we can choose a generator 
 $(\eta _{\ell; \mathfrak {s}})_{\mathfrak {s} \in \mathscr {I}(\mathcal {I}^{\mathrm {ND}_{0}}_{w})} \in \mathscr {X}_{w}$
 such that
$(\eta _{\ell; \mathfrak {s}})_{\mathfrak {s} \in \mathscr {I}(\mathcal {I}^{\mathrm {ND}_{0}}_{w})} \in \mathscr {X}_{w}$
 such that 
 $$ \begin{align*} \eta_{\ell; \emptyset} = \sum_{i = 0}^{\ell} b_{\ell i} (t - \theta)^{i}, \ \ b_{\ell i} \in T \mathbb{F}_{p}[T]_{(T)} \ (0 \leq i < \ell) \ \ {and} \ \ b_{\ell \ell} = 1, \end{align*} $$
$$ \begin{align*} \eta_{\ell; \emptyset} = \sum_{i = 0}^{\ell} b_{\ell i} (t - \theta)^{i}, \ \ b_{\ell i} \in T \mathbb{F}_{p}[T]_{(T)} \ (0 \leq i < \ell) \ \ {and} \ \ b_{\ell \ell} = 1, \end{align*} $$
where 
 $T := t - t^{q}$
 and
$T := t - t^{q}$
 and 
 $\mathbb {F}_{p}[T]_{(T)} \subset \mathbb {F}_{p}(t)$
 is the localization of
$\mathbb {F}_{p}[T]_{(T)} \subset \mathbb {F}_{p}(t)$
 is the localization of 
 $\mathbb {F}_{p}[T]$
 at the prime ideal
$\mathbb {F}_{p}[T]$
 at the prime ideal 
 $(T)$
.
$(T)$
.
Proof. Note that by Lemma 4.4, we have 
 $\mathscr {X}_{w} \subset \mathbb {F}_{q}(t)[\theta ]^{\mathscr {I}(\mathcal {I}^{\mathrm {ND}_{0}}_{w})}$
. We write
$\mathscr {X}_{w} \subset \mathbb {F}_{q}(t)[\theta ]^{\mathscr {I}(\mathcal {I}^{\mathrm {ND}_{0}}_{w})}$
. We write 
 $$ \begin{align*} w &= \ell (q - 1) + s \ \ (\ell \geq 0, \ \ 0 \leq s < q - 1), \\ \ell &= m q + n \ \ (m \geq 0, \ \ 0 \leq n < q). \end{align*} $$
$$ \begin{align*} w &= \ell (q - 1) + s \ \ (\ell \geq 0, \ \ 0 \leq s < q - 1), \\ \ell &= m q + n \ \ (m \geq 0, \ \ 0 \leq n < q). \end{align*} $$
 First, we assume that 
 $s = 0$
 and hence
$s = 0$
 and hence 
 $w = \ell (q - 1)$
 with
$w = \ell (q - 1)$
 with 
 $\ell \geq 0$
. When
$\ell \geq 0$
. When 
 $\ell = 0$
, we have
$\ell = 0$
, we have 
 $\mathscr {I}(\mathcal {I}^{\mathrm {ND}_{0}}_{0}) = \{ \emptyset \}$
 and the equation is
$\mathscr {I}(\mathcal {I}^{\mathrm {ND}_{0}}_{0}) = \{ \emptyset \}$
 and the equation is 
 $\varepsilon _{\emptyset }^{(1)} = \varepsilon _{\emptyset }$
. Thus,
$\varepsilon _{\emptyset }^{(1)} = \varepsilon _{\emptyset }$
. Thus, 
 $\mathscr {X}_0=\mathbb {F}_{q}(t)$
, and we have a generator
$\mathscr {X}_0=\mathbb {F}_{q}(t)$
, and we have a generator 
 $\eta _{0; \emptyset } = 1$
. Let
$\eta _{0; \emptyset } = 1$
. Let 
 $\ell \geq 1$
 and suppose that the desired properties hold for weight
$\ell \geq 1$
 and suppose that the desired properties hold for weight 
 $\ell ' (q - 1)$
 with
$\ell ' (q - 1)$
 with 
 $\ell ' < \ell $
. The system of Frobenius equations (E
$\ell ' < \ell $
. The system of Frobenius equations (E
 $_{\ell (q - 1)}$
) becomes
$_{\ell (q - 1)}$
) becomes 
 $$ \begin{align} \varepsilon_{\emptyset}^{(1)} = \varepsilon_{\emptyset} (t - \theta)^{\ell (q - 1)} + \sum_{\substack{0 \leq j < \ell \\ j \not\equiv \ell \bmod q}} \varepsilon_{((\ell - j) (q - 1))}(t - \theta)^{\ell (q - 1)} \end{align} $$
$$ \begin{align} \varepsilon_{\emptyset}^{(1)} = \varepsilon_{\emptyset} (t - \theta)^{\ell (q - 1)} + \sum_{\substack{0 \leq j < \ell \\ j \not\equiv \ell \bmod q}} \varepsilon_{((\ell - j) (q - 1))}(t - \theta)^{\ell (q - 1)} \end{align} $$
and
 $$ \begin{align*} \varepsilon_{((\ell - j) (q - 1), \mathfrak{s})}^{(1)} &= \varepsilon_{((\ell - j) (q - 1), \mathfrak{s})} (t - \theta)^{j (q - 1) - \operatorname{\mathrm{wt}}(\mathfrak{s})} \\ & \ \ \ + \sum_{\substack{s'> 0 \\ (\mathfrak{s}, s') \in \mathscr{I}(\mathcal{I}^{\mathrm{ND}_{0}}_{j (q - 1)})}} \varepsilon_{((\ell - j) (q - 1), \mathfrak{s}, s')} (t - \theta)^{j (q - 1) - \operatorname{\mathrm{wt}}(\mathfrak{s})} \end{align*} $$
$$ \begin{align*} \varepsilon_{((\ell - j) (q - 1), \mathfrak{s})}^{(1)} &= \varepsilon_{((\ell - j) (q - 1), \mathfrak{s})} (t - \theta)^{j (q - 1) - \operatorname{\mathrm{wt}}(\mathfrak{s})} \\ & \ \ \ + \sum_{\substack{s'> 0 \\ (\mathfrak{s}, s') \in \mathscr{I}(\mathcal{I}^{\mathrm{ND}_{0}}_{j (q - 1)})}} \varepsilon_{((\ell - j) (q - 1), \mathfrak{s}, s')} (t - \theta)^{j (q - 1) - \operatorname{\mathrm{wt}}(\mathfrak{s})} \end{align*} $$
for 
 $0 \leq j < \ell $
 with
$0 \leq j < \ell $
 with 
 $j \not \equiv \ell \bmod q$
 and
$j \not \equiv \ell \bmod q$
 and 
 $\mathfrak {s} \in \mathscr {I}(\mathcal {I}^{\mathrm {ND}_{0}}_{j (q - 1)})$
. Since
$\mathfrak {s} \in \mathscr {I}(\mathcal {I}^{\mathrm {ND}_{0}}_{j (q - 1)})$
. Since 
 $(\varepsilon _{((\ell - j) (q - 1), \mathfrak {s})})_{\mathfrak {s} \in \mathscr {I}(\mathcal {I}^{\mathrm {ND}_{0}}_{j (q - 1)})} \in \mathscr {X}_{j (q - 1)}$
 for each j, the induction hypothesis implies that we have
$(\varepsilon _{((\ell - j) (q - 1), \mathfrak {s})})_{\mathfrak {s} \in \mathscr {I}(\mathcal {I}^{\mathrm {ND}_{0}}_{j (q - 1)})} \in \mathscr {X}_{j (q - 1)}$
 for each j, the induction hypothesis implies that we have 
 $$ \begin{align*} \varepsilon_{((\ell - j) (q - 1))} = f_{j} \sum_{i = 0}^{j} b_{j i} (t - \theta)^{i}, \ \ f_{j} \in \mathbb{F}_{q}(t), \ \ b_{j i} \in T \mathbb{F}_{p}[T]_{(T)} \ \ \mathrm{and} \ \ b_{j j} = 1. \end{align*} $$
$$ \begin{align*} \varepsilon_{((\ell - j) (q - 1))} = f_{j} \sum_{i = 0}^{j} b_{j i} (t - \theta)^{i}, \ \ f_{j} \in \mathbb{F}_{q}(t), \ \ b_{j i} \in T \mathbb{F}_{p}[T]_{(T)} \ \ \mathrm{and} \ \ b_{j j} = 1. \end{align*} $$
By Lemma 4.4, we have 
 $\deg _{\theta } \varepsilon _{\emptyset } \leq \ell $
. We write
$\deg _{\theta } \varepsilon _{\emptyset } \leq \ell $
. We write 
 $\varepsilon _{\emptyset } = \sum _{i = 0}^{\ell } a_{i} (t - \theta )^{i}$
 with
$\varepsilon _{\emptyset } = \sum _{i = 0}^{\ell } a_{i} (t - \theta )^{i}$
 with 
 $a_{i} \in \mathbb {F}_{q}(t)$
 and plug it into (4.2). Then we obtain
$a_{i} \in \mathbb {F}_{q}(t)$
 and plug it into (4.2). Then we obtain 
 $$ \begin{align*} \sum_{j = 0}^{\ell} a_{j} (t - \theta^{q})^{j} = \sum_{i = 0}^{\ell} a_{i} (t - \theta)^{\ell (q - 1) + i} + \sum_{\substack{0 \leq j < \ell \\ j \not\equiv \ell \bmod q}} f_{j} \sum_{i = 0}^{j} b_{j i} (t - \theta)^{\ell (q - 1) + i}. \end{align*} $$
$$ \begin{align*} \sum_{j = 0}^{\ell} a_{j} (t - \theta^{q})^{j} = \sum_{i = 0}^{\ell} a_{i} (t - \theta)^{\ell (q - 1) + i} + \sum_{\substack{0 \leq j < \ell \\ j \not\equiv \ell \bmod q}} f_{j} \sum_{i = 0}^{j} b_{j i} (t - \theta)^{\ell (q - 1) + i}. \end{align*} $$
Note that the equation above can be expressed as
 $$ \begin{align*} \sum_{i = 0}^{\ell - 1} \sum_{j = i}^{\ell - 1} \binom{j}{i} T^{j - i} a_{j} (t - \theta)^{i q} &- \sum_{i = 0}^{\ell - 1} a_{i} (t - \theta)^{\ell (q - 1) + i} - \sum_{i = 0}^{\ell - 1} \sum_{\substack{i \leq j < \ell \\ j \not\equiv \ell \bmod q}} b_{j i} f_{j} (t - \theta)^{\ell (q - 1) + i} \\[-4pt] &= - a_{\ell} \sum_{i = 0}^{\ell - 1} \binom{\ell}{i} T^{\ell - i} (t - \theta)^{i q}. \end{align*} $$
$$ \begin{align*} \sum_{i = 0}^{\ell - 1} \sum_{j = i}^{\ell - 1} \binom{j}{i} T^{j - i} a_{j} (t - \theta)^{i q} &- \sum_{i = 0}^{\ell - 1} a_{i} (t - \theta)^{\ell (q - 1) + i} - \sum_{i = 0}^{\ell - 1} \sum_{\substack{i \leq j < \ell \\ j \not\equiv \ell \bmod q}} b_{j i} f_{j} (t - \theta)^{\ell (q - 1) + i} \\[-4pt] &= - a_{\ell} \sum_{i = 0}^{\ell - 1} \binom{\ell}{i} T^{\ell - i} (t - \theta)^{i q}. \end{align*} $$
Note further that
 $$ \begin{align*} i q < w = (\ell - m) q - n \ \Longleftrightarrow \ i < \ell - m - \dfrac{n}{q}. \end{align*} $$
$$ \begin{align*} i q < w = (\ell - m) q - n \ \Longleftrightarrow \ i < \ell - m - \dfrac{n}{q}. \end{align*} $$
By comparing the coefficients of 
 $(t - \theta )^{\nu }$
 for
$(t - \theta )^{\nu }$
 for 
 $\nu = i q\ (0 \leq i < \ell - m)$
 or
$\nu = i q\ (0 \leq i < \ell - m)$
 or 
 $\ell (q - 1) \leq \nu < \ell q$
, this gives a system of linear equations with
$\ell (q - 1) \leq \nu < \ell q$
, this gives a system of linear equations with 
 $(2 \ell - m)$
-equations and
$(2 \ell - m)$
-equations and 
 $(2 \ell - m + 1)$
-variables. We write
$(2 \ell - m + 1)$
-variables. We write 
 $\mathbf {a} := (a_{0}, \ldots , a_{\ell - 1})^{\mathrm {tr}}$
 and
$\mathbf {a} := (a_{0}, \ldots , a_{\ell - 1})^{\mathrm {tr}}$
 and 
 $\mathbf {f} := (f_{0}, \ldots , f_{\ell - 1})^{\mathrm {tr}}$
 (excluding
$\mathbf {f} := (f_{0}, \ldots , f_{\ell - 1})^{\mathrm {tr}}$
 (excluding 
 $f_{n}, f_{q + n}, \ldots , f_{(m - 1) q + n}$
). Then the system mentioned above can be expressed as
$f_{n}, f_{q + n}, \ldots , f_{(m - 1) q + n}$
). Then the system mentioned above can be expressed as 
 $$ \begin{align} U \left( \begin{array}{@{}c@{}} \mathbf{a} \\ \mathbf{f} \end{array} \right) = a_{\ell} \mathbf{b}, \ \ U \in \operatorname{\mathrm{Mat}}_{2 \ell - m}(\mathbb{F}_{p}[T]_{(T)}) \ \ \mathrm{and} \ \ \mathbf{b} \in (T \mathbb{F}_{p}[T]_{(T)})^{2 \ell - m}. \end{align} $$
$$ \begin{align} U \left( \begin{array}{@{}c@{}} \mathbf{a} \\ \mathbf{f} \end{array} \right) = a_{\ell} \mathbf{b}, \ \ U \in \operatorname{\mathrm{Mat}}_{2 \ell - m}(\mathbb{F}_{p}[T]_{(T)}) \ \ \mathrm{and} \ \ \mathbf{b} \in (T \mathbb{F}_{p}[T]_{(T)})^{2 \ell - m}. \end{align} $$
 As our goal of this case 
 $w=\ell (q-1)$
 is to show
$w=\ell (q-1)$
 is to show 
 $\dim _{\mathbb {F}_{q}(t)}\mathscr {X}_{w}=1$
, it is to show that the existence of
$\dim _{\mathbb {F}_{q}(t)}\mathscr {X}_{w}=1$
, it is to show that the existence of 
 $\begin {pmatrix} \mathbf {a}\\ \mathbf {f} \end {pmatrix}$
 is unique up to
$\begin {pmatrix} \mathbf {a}\\ \mathbf {f} \end {pmatrix}$
 is unique up to 
 $\mathbb {F}_{q}(t)$
-scalar multiple. Therefore, from (4.3), it suffices to show that
$\mathbb {F}_{q}(t)$
-scalar multiple. Therefore, from (4.3), it suffices to show that 
 $\det (U \bmod T) \neq 0$
 in
$\det (U \bmod T) \neq 0$
 in 
 $\mathbb {F}_{p}$
. Indeed, we have
$\mathbb {F}_{p}$
. Indeed, we have 

 The matrix 
 $\left (U \bmod T\right )+ \left ( \begin {array}{@{}cc@{}} O & O \\ \operatorname {\mathrm {Id}}_{\ell } & O \end {array} \right )$
 can be described as follows:
$\left (U \bmod T\right )+ \left ( \begin {array}{@{}cc@{}} O & O \\ \operatorname {\mathrm {Id}}_{\ell } & O \end {array} \right )$
 can be described as follows: 
- 
(i) We first set up the lower right submatrix by beginning with a matrix of diagonal blocks, the first one being  $-\operatorname {\mathrm {Id}}_n$
 and the remaining m of them being equal to $-\operatorname {\mathrm {Id}}_n$
 and the remaining m of them being equal to $-\operatorname {\mathrm {Id}}_{q-1}$
. Then we insert zero rows between the blocks to obtain our submatrix of size $-\operatorname {\mathrm {Id}}_{q-1}$
. Then we insert zero rows between the blocks to obtain our submatrix of size $\ell \times (\ell -m)$
. $\ell \times (\ell -m)$
.
- 
(ii) We then put the identity matrix  $\operatorname {\mathrm {Id}}_{\ell -m}$
 on the upper left corner. $\operatorname {\mathrm {Id}}_{\ell -m}$
 on the upper left corner.
- 
(iii) Finally, we define the  $\left ((\ell -m)+1\right )$
st column to the $\left ((\ell -m)+1\right )$
st column to the $\ell $
th column, each of length $\ell $
th column, each of length $2\ell -m$
. In the $2\ell -m$
. In the $\left ((\ell -m)+i\right )$
th column, all entries are zero except for the entry $\left ((\ell -m)+i\right )$
th column, all entries are zero except for the entry $1$
 occurring in the same row as the ith row of zeroes inserted into the matrix constructed in step (i) (i.e., the row of zeroes lying above the ith diagonal block equal to $1$
 occurring in the same row as the ith row of zeroes inserted into the matrix constructed in step (i) (i.e., the row of zeroes lying above the ith diagonal block equal to $-\operatorname {\mathrm {Id}}_{q-1}$
 in step (i)). Thus, we have our $-\operatorname {\mathrm {Id}}_{q-1}$
 in step (i)). Thus, we have our $2(\ell -m)\times 2(\ell -m)$
 matrix $2(\ell -m)\times 2(\ell -m)$
 matrix $\left (U \bmod T\right )+ \left ( \begin {array}{@{}cc@{}} O & O \\ \operatorname {\mathrm {Id}}_{\ell } & O \end {array} \right )$
. $\left (U \bmod T\right )+ \left ( \begin {array}{@{}cc@{}} O & O \\ \operatorname {\mathrm {Id}}_{\ell } & O \end {array} \right )$
.
For example, let 
 $q = 3$
,
$q = 3$
, 
 $w = 14 = 7 (3 - 1)$
 (
$w = 14 = 7 (3 - 1)$
 (
 $\ell = 7 = 2 \cdot 3 + 1$
,
$\ell = 7 = 2 \cdot 3 + 1$
, 
 $m = 2$
,
$m = 2$
, 
 $n = 1$
). Then we have
$n = 1$
). Then we have 
 $$ \begin{align*} U \bmod T =\left( \begin{array}{@{}ccccccc|ccccc@{}}1 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 \\0 & 1 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 \\0 & 0 & 1 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 \\0 & 0 & 0 & 1 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 \\0 & 0 & 0 & 0 & 1 & 0 & 0 & 0 & 0 & 0 & 0 & 0 \\\hline-1 & 0 & 0 & 0 & 0 & 0 & 0 & -1 & 0 & 0 & 0 & 0 \\0 & -1 & 0 & 0 & 0 & 1 & 0 & 0 & 0 & 0 & 0 & 0 \\0 & 0 & -1 & 0 & 0 & 0 & 0 & 0 & -1 & 0 & 0 & 0 \\0 & 0 & 0 & -1 & 0 & 0 & 0 & 0 & 0 & -1 & 0 & 0 \\0 & 0 & 0 & 0 & -1 & 0 & 1 & 0 & 0 & 0 & 0 & 0 \\0 & 0 & 0 & 0 & 0 & -1 & 0 & 0 & 0 & 0 & -1 & 0 \\0 & 0 & 0 & 0 & 0 & 0 & -1 & 0 & 0 & 0 & 0 & -1 \\\end{array} \right) \end{align*} $$
$$ \begin{align*} U \bmod T =\left( \begin{array}{@{}ccccccc|ccccc@{}}1 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 \\0 & 1 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 \\0 & 0 & 1 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 \\0 & 0 & 0 & 1 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 \\0 & 0 & 0 & 0 & 1 & 0 & 0 & 0 & 0 & 0 & 0 & 0 \\\hline-1 & 0 & 0 & 0 & 0 & 0 & 0 & -1 & 0 & 0 & 0 & 0 \\0 & -1 & 0 & 0 & 0 & 1 & 0 & 0 & 0 & 0 & 0 & 0 \\0 & 0 & -1 & 0 & 0 & 0 & 0 & 0 & -1 & 0 & 0 & 0 \\0 & 0 & 0 & -1 & 0 & 0 & 0 & 0 & 0 & -1 & 0 & 0 \\0 & 0 & 0 & 0 & -1 & 0 & 1 & 0 & 0 & 0 & 0 & 0 \\0 & 0 & 0 & 0 & 0 & -1 & 0 & 0 & 0 & 0 & -1 & 0 \\0 & 0 & 0 & 0 & 0 & 0 & -1 & 0 & 0 & 0 & 0 & -1 \\\end{array} \right) \end{align*} $$
 To evaluate 
 $\det \left (U \bmod T\right )$
, we appeal to elementary row operations which do not change the value of the determinant. Adding each of the top
$\det \left (U \bmod T\right )$
, we appeal to elementary row operations which do not change the value of the determinant. Adding each of the top 
 $\ell -m$
 rows to the corresponding rows in the lower left matrix kills all entries there coming from
$\ell -m$
 rows to the corresponding rows in the lower left matrix kills all entries there coming from 
 $-\operatorname {\mathrm {Id}}_{\ell }$
 except the m bottom ones, which lie in the
$-\operatorname {\mathrm {Id}}_{\ell }$
 except the m bottom ones, which lie in the 
 $((\ell -m)+1)$
st one to the
$((\ell -m)+1)$
st one to the 
 $\ell $
th column. But each
$\ell $
th column. But each 
 $-1$
 in these last m rows can be killed by adding the appropriate row from step (iii) which has all zero entries except
$-1$
 in these last m rows can be killed by adding the appropriate row from step (iii) which has all zero entries except 
 $1$
 in a unique column between
$1$
 in a unique column between 
 $\ell -m +1$
 and
$\ell -m +1$
 and 
 $ \ell $
. Doing this leaves only the non-zero entries in those m columns the ones inserted in step (iii). We end up with a matrix which has a unique
$ \ell $
. Doing this leaves only the non-zero entries in those m columns the ones inserted in step (iii). We end up with a matrix which has a unique 
 $\pm 1$
 in each row and column. So the elementary product expansion evaluates the determinant as
$\pm 1$
 in each row and column. So the elementary product expansion evaluates the determinant as 
 $\pm 1$
. Note that one can also use elementary column operations to show the desired identity.
$\pm 1$
. Note that one can also use elementary column operations to show the desired identity.
 Next, we assume that 
 $1 \leq s < q - 1$
 and put
$1 \leq s < q - 1$
 and put 
 $w := \ell (q - 1) + s$
. The system of Frobenius equations (E
w
) is
$w := \ell (q - 1) + s$
. The system of Frobenius equations (E
w
) is 
 $$ \begin{align} \varepsilon_{\emptyset}^{(1)} = \varepsilon_{\emptyset} (t - \theta)^{w} + \sum_{\substack{0 \leq j \leq \ell \\ j \not\equiv \ell - s \bmod q}} \varepsilon_{((\ell - j) (q - 1) + s)}(t - \theta)^{w} \end{align} $$
$$ \begin{align} \varepsilon_{\emptyset}^{(1)} = \varepsilon_{\emptyset} (t - \theta)^{w} + \sum_{\substack{0 \leq j \leq \ell \\ j \not\equiv \ell - s \bmod q}} \varepsilon_{((\ell - j) (q - 1) + s)}(t - \theta)^{w} \end{align} $$
and
 $$ \begin{align*} \varepsilon_{((\ell - j) (q - 1) + s, \mathfrak{s})}^{(1)} &= \varepsilon_{((\ell - j) (q - 1) + s, \mathfrak{s})} (t - \theta)^{j (q - 1) - \operatorname{\mathrm{wt}}(\mathfrak{s})} \\ & \ \ \ + \sum_{\substack{s'> 0 \\ (\mathfrak{s}, s') \in \mathscr{I}(\mathcal{I}^{\mathrm{ND}_{0}}_{j (q - 1)})}} \varepsilon_{((\ell - j) (q - 1) + s, \mathfrak{s}, s')} (t - \theta)^{j (q - 1) - \operatorname{\mathrm{wt}}(\mathfrak{s})} \end{align*} $$
$$ \begin{align*} \varepsilon_{((\ell - j) (q - 1) + s, \mathfrak{s})}^{(1)} &= \varepsilon_{((\ell - j) (q - 1) + s, \mathfrak{s})} (t - \theta)^{j (q - 1) - \operatorname{\mathrm{wt}}(\mathfrak{s})} \\ & \ \ \ + \sum_{\substack{s'> 0 \\ (\mathfrak{s}, s') \in \mathscr{I}(\mathcal{I}^{\mathrm{ND}_{0}}_{j (q - 1)})}} \varepsilon_{((\ell - j) (q - 1) + s, \mathfrak{s}, s')} (t - \theta)^{j (q - 1) - \operatorname{\mathrm{wt}}(\mathfrak{s})} \end{align*} $$
for 
 $0 \leq j \leq \ell $
 with
$0 \leq j \leq \ell $
 with 
 $j \not \equiv \ell - s \bmod q$
 and
$j \not \equiv \ell - s \bmod q$
 and 
 $\mathfrak {s} \in \mathscr {I}(\mathcal {I}^{\mathrm {ND}_{0}}_{j (q - 1)})$
. Since
$\mathfrak {s} \in \mathscr {I}(\mathcal {I}^{\mathrm {ND}_{0}}_{j (q - 1)})$
. Since 
 $(\varepsilon _{((\ell - j) (q - 1) + s, \mathfrak {s})})_{\mathfrak {s} \in \mathscr {I}(\mathcal {I}^{\mathrm {ND}_{0}}_{j (q - 1)})} \in \mathscr {X}_{j (q - 1)}$
 for each j, we have
$(\varepsilon _{((\ell - j) (q - 1) + s, \mathfrak {s})})_{\mathfrak {s} \in \mathscr {I}(\mathcal {I}^{\mathrm {ND}_{0}}_{j (q - 1)})} \in \mathscr {X}_{j (q - 1)}$
 for each j, we have 
 $$ \begin{align*} \varepsilon_{((\ell - j) (q - 1) + s)} = f_{j} \sum_{i = 0}^{j} b_{j i} (t - \theta)^{i}, \ \ f_{j} \in \mathbb{F}_{q}(t), \ \ b_{j i} \in T \mathbb{F}_{p}[T]_{(T)} \ \ \mathrm{and} \ \ b_{j j} = 1. \end{align*} $$
$$ \begin{align*} \varepsilon_{((\ell - j) (q - 1) + s)} = f_{j} \sum_{i = 0}^{j} b_{j i} (t - \theta)^{i}, \ \ f_{j} \in \mathbb{F}_{q}(t), \ \ b_{j i} \in T \mathbb{F}_{p}[T]_{(T)} \ \ \mathrm{and} \ \ b_{j j} = 1. \end{align*} $$
By Lemma 4.4, we have 
 $\deg _{\theta } \varepsilon _{\emptyset } \leq \ell $
. We write
$\deg _{\theta } \varepsilon _{\emptyset } \leq \ell $
. We write 
 $\varepsilon _{\emptyset } = \sum _{i = 0}^{\ell } a_{i} (t - \theta )^{i}$
 with
$\varepsilon _{\emptyset } = \sum _{i = 0}^{\ell } a_{i} (t - \theta )^{i}$
 with 
 $a_{i} \in \mathbb {F}_{q}(t)$
. Then (4.4) becomes
$a_{i} \in \mathbb {F}_{q}(t)$
. Then (4.4) becomes 
 $$ \begin{align*} \sum_{j = 0}^{\ell} a_{j} (t - \theta^{q})^{j} = \sum_{i = 0}^{\ell} a_{i} (t - \theta)^{w + i} + \sum_{\substack{0 \leq j \leq \ell \\ j \not\equiv \ell - s \bmod q}} f_{j} \sum_{i = 0}^{j} b_{j i} (t - \theta)^{w + i}. \end{align*} $$
$$ \begin{align*} \sum_{j = 0}^{\ell} a_{j} (t - \theta^{q})^{j} = \sum_{i = 0}^{\ell} a_{i} (t - \theta)^{w + i} + \sum_{\substack{0 \leq j \leq \ell \\ j \not\equiv \ell - s \bmod q}} f_{j} \sum_{i = 0}^{j} b_{j i} (t - \theta)^{w + i}. \end{align*} $$
This identity can be written as
 $$ \begin{align*} \sum_{i = 0}^{\ell} \sum_{j = i}^{\ell} \binom{j}{i} T^{j - i} a_{j} (t - \theta)^{i q} &- \sum_{i = 0}^{\ell} a_{i} (t - \theta)^{w + i} - \sum_{i = 0}^{\ell} \sum_{\substack{i \leq j \leq \ell \\ j \not\equiv \ell - s \bmod q}} b_{j i} f_{j} (t - \theta)^{w + i} = 0. \end{align*} $$
$$ \begin{align*} \sum_{i = 0}^{\ell} \sum_{j = i}^{\ell} \binom{j}{i} T^{j - i} a_{j} (t - \theta)^{i q} &- \sum_{i = 0}^{\ell} a_{i} (t - \theta)^{w + i} - \sum_{i = 0}^{\ell} \sum_{\substack{i \leq j \leq \ell \\ j \not\equiv \ell - s \bmod q}} b_{j i} f_{j} (t - \theta)^{w + i} = 0. \end{align*} $$
We note that
 $$ \begin{align*} i q < w = (\ell - m) q + (s - n) \ \Longleftrightarrow \ i < \ell - m + \dfrac{s - n}{q}. \end{align*} $$
$$ \begin{align*} i q < w = (\ell - m) q + (s - n) \ \Longleftrightarrow \ i < \ell - m + \dfrac{s - n}{q}. \end{align*} $$
 When 
 $s \leq n$
, by comparing the coefficients of
$s \leq n$
, by comparing the coefficients of 
 $(t - \theta )^{\nu }$
 for
$(t - \theta )^{\nu }$
 for 
 $\nu = i q\ (0 \leq i < \ell - m)$
 or
$\nu = i q\ (0 \leq i < \ell - m)$
 or 
 $w \leq \nu \leq w + \ell $
, this gives a system of linear equations with
$w \leq \nu \leq w + \ell $
, this gives a system of linear equations with 
 $(2 \ell - m + 1)$
-equations and
$(2 \ell - m + 1)$
-equations and 
 $(2 \ell - m + 1)$
-variables. We write
$(2 \ell - m + 1)$
-variables. We write 
 $\mathbf {a} := (a_{0}, \ldots , a_{\ell })^{\mathrm {tr}}$
 and
$\mathbf {a} := (a_{0}, \ldots , a_{\ell })^{\mathrm {tr}}$
 and 
 $\mathbf {f} := (f_{0}, \ldots , f_{\ell })^{\mathrm {tr}}$
 (excluding
$\mathbf {f} := (f_{0}, \ldots , f_{\ell })^{\mathrm {tr}}$
 (excluding 
 $f_{n - s}, f_{q + n - s}, \ldots , f_{\ell - s}$
). Then the system can be written as
$f_{n - s}, f_{q + n - s}, \ldots , f_{\ell - s}$
). Then the system can be written as 
 $$ \begin{align*} U \left( \begin{array}{@{}c@{}} \mathbf{a} \\ \mathbf{f} \end{array} \right) = \mathbf{0} \ \ \mathrm{and} \ \ U \in \operatorname{\mathrm{Mat}}_{2 \ell - m + 1}(\mathbb{F}_{p}[T]_{(T)}). \end{align*} $$
$$ \begin{align*} U \left( \begin{array}{@{}c@{}} \mathbf{a} \\ \mathbf{f} \end{array} \right) = \mathbf{0} \ \ \mathrm{and} \ \ U \in \operatorname{\mathrm{Mat}}_{2 \ell - m + 1}(\mathbb{F}_{p}[T]_{(T)}). \end{align*} $$
Since we aim to show that the solution space 
 $\mathscr {X}_{w}$
 is trivial in this case, it suffices to show that
$\mathscr {X}_{w}$
 is trivial in this case, it suffices to show that 
 $\det (U \bmod T) \neq 0$
 in
$\det (U \bmod T) \neq 0$
 in 
 $\mathbb {F}_{p}$
. Indeed, we have
$\mathbb {F}_{p}$
. Indeed, we have 

and hence 
 $\det (U \bmod T) = \pm 1$
.
$\det (U \bmod T) = \pm 1$
.
 When 
 $s> n$
, by comparing the coefficients of
$s> n$
, by comparing the coefficients of 
 $(t - \theta )^{\nu }$
 for
$(t - \theta )^{\nu }$
 for 
 $\nu = i q\ (0 \leq i \leq \ell - m)$
 or
$\nu = i q\ (0 \leq i \leq \ell - m)$
 or 
 $w \leq \nu \leq w + \ell $
, this gives a system of linear equations with
$w \leq \nu \leq w + \ell $
, this gives a system of linear equations with 
 $(2 \ell - m + 2)$
-equations and
$(2 \ell - m + 2)$
-equations and 
 $(2 \ell - m + 2)$
-variables. We write
$(2 \ell - m + 2)$
-variables. We write 
 $\mathbf {a} := (a_{0}, \ldots , a_{\ell })^{\mathrm {tr}}$
 and
$\mathbf {a} := (a_{0}, \ldots , a_{\ell })^{\mathrm {tr}}$
 and 
 $\mathbf {f} := (f_{0}, \ldots , f_{\ell })^{\mathrm {tr}}$
 (excluding
$\mathbf {f} := (f_{0}, \ldots , f_{\ell })^{\mathrm {tr}}$
 (excluding 
 $f_{q + n - s}, f_{2 q + n - s}, \ldots , f_{\ell - s}$
). Then the system can be written as
$f_{q + n - s}, f_{2 q + n - s}, \ldots , f_{\ell - s}$
). Then the system can be written as 
 $$ \begin{align*} U \left( \begin{array}{@{}c@{}} \mathbf{a} \\ \mathbf{f} \end{array} \right) = \mathbf{0} \ \ \mathrm{and} \ \ U \in \operatorname{\mathrm{Mat}}_{2 \ell - m + 2}(\mathbb{F}_{p}[T]_{(T)}). \end{align*} $$
$$ \begin{align*} U \left( \begin{array}{@{}c@{}} \mathbf{a} \\ \mathbf{f} \end{array} \right) = \mathbf{0} \ \ \mathrm{and} \ \ U \in \operatorname{\mathrm{Mat}}_{2 \ell - m + 2}(\mathbb{F}_{p}[T]_{(T)}). \end{align*} $$
It is enough to show that 
 $\det (U \bmod T) \neq 0$
 in
$\det (U \bmod T) \neq 0$
 in 
 $\mathbb {F}_{p}$
. Indeed, we have
$\mathbb {F}_{p}$
. Indeed, we have 

and hence 
 $\det (U \bmod T) = \pm 1$
.
$\det (U \bmod T) = \pm 1$
.
5 Linear independence
 In this section, we aim to show that 
 $\{\operatorname {\mathrm {Li}}_{\mathfrak {s}}(\mathbf {1})\in k_{\infty }\mid \mathfrak {s}\in \mathcal {I}^{\mathrm {ND}}_{w}\}$
 is a k-linearly independent set. To begin with, we adopt the following setting. Let
$\{\operatorname {\mathrm {Li}}_{\mathfrak {s}}(\mathbf {1})\in k_{\infty }\mid \mathfrak {s}\in \mathcal {I}^{\mathrm {ND}}_{w}\}$
 is a k-linearly independent set. To begin with, we adopt the following setting. Let 
 $(-\theta )^{\frac {1}{q-1}}\in \overline {k}^\times $
 be a fixed
$(-\theta )^{\frac {1}{q-1}}\in \overline {k}^\times $
 be a fixed 
 $(q-1)$
st root of
$(q-1)$
st root of 
 $-\theta $
. Following [Reference Anderson, Brownawell and Papanikolas2], we consider the following power series:
$-\theta $
. Following [Reference Anderson, Brownawell and Papanikolas2], we consider the following power series: 
 $$ \begin{align*} \Omega(t):=(-\theta)^{\frac{-q}{q-1}}\prod_{i=1}^\infty\left(1-\frac{t}{\theta^{q^i}}\right)\in{\overline{k_\infty} [\![ t ]\!]}. \end{align*} $$
$$ \begin{align*} \Omega(t):=(-\theta)^{\frac{-q}{q-1}}\prod_{i=1}^\infty\left(1-\frac{t}{\theta^{q^i}}\right)\in{\overline{k_\infty} [\![ t ]\!]}. \end{align*} $$
Note that it satisfies the Frobenius difference equation
 $$ \begin{align*} \Omega^{(-1)}(t)=(t-\theta)\Omega(t). \end{align*} $$
$$ \begin{align*} \Omega^{(-1)}(t)=(t-\theta)\Omega(t). \end{align*} $$
In addition, we have 
 $\Omega (t)\in \mathcal {E}$
 and
$\Omega (t)\in \mathcal {E}$
 and 
 $\widetilde {\pi }:=1/\Omega (\theta )$
 is the fundamental period of the Carlitz module (see [Reference Anderson, Brownawell and Papanikolas2, Sec. 3.1.2]). We also set
$\widetilde {\pi }:=1/\Omega (\theta )$
 is the fundamental period of the Carlitz module (see [Reference Anderson, Brownawell and Papanikolas2, Sec. 3.1.2]). We also set 
 $\mathbb {L}_{0} := 1$
 and
$\mathbb {L}_{0} := 1$
 and 
 $\mathbb {L}_{d} := (t - \theta ^{q}) \cdots (t - \theta ^{q^{d}})$
 for
$\mathbb {L}_{d} := (t - \theta ^{q}) \cdots (t - \theta ^{q^{d}})$
 for 
 $d \geq 1$
. Put
$d \geq 1$
. Put 
 $\mathcal {L}(\emptyset ) := 1$
 and for each index
$\mathcal {L}(\emptyset ) := 1$
 and for each index 
 $\mathfrak {s} = (s_{1}, \ldots , s_{r}) \in \mathcal {I}_{>0}$
, we define the following deformation series:
$\mathfrak {s} = (s_{1}, \ldots , s_{r}) \in \mathcal {I}_{>0}$
, we define the following deformation series: 
 $$ \begin{align*} \mathcal{L}(\mathfrak{s}) := \Omega^{\operatorname{\mathrm{wt}}(\mathfrak{s})} \sum_{d_{1}> \cdots > d_{r} \geq 0} \dfrac{1}{\mathbb{L}_{d_{1}}^{s_{1}} \cdots \mathbb{L}_{d_{r}}^{s_{r}}} \in \mathbb{T}, \end{align*} $$
$$ \begin{align*} \mathcal{L}(\mathfrak{s}) := \Omega^{\operatorname{\mathrm{wt}}(\mathfrak{s})} \sum_{d_{1}> \cdots > d_{r} \geq 0} \dfrac{1}{\mathbb{L}_{d_{1}}^{s_{1}} \cdots \mathbb{L}_{d_{r}}^{s_{r}}} \in \mathbb{T}, \end{align*} $$
which was first introduced by Papanikolas [Reference Papanikolas27] for 
 $\operatorname {\mathrm {dep}}(\mathfrak {s})=1$
. It is shown in [Reference Chang9, Lemma 5.3.1] that
$\operatorname {\mathrm {dep}}(\mathfrak {s})=1$
. It is shown in [Reference Chang9, Lemma 5.3.1] that 
 $\mathcal {L}(\mathfrak {s})\in \mathcal {E}$
. Moreover, by [Reference Chang, Papanikolas and Yu14, Proposition 2.3.3], we have
$\mathcal {L}(\mathfrak {s})\in \mathcal {E}$
. Moreover, by [Reference Chang, Papanikolas and Yu14, Proposition 2.3.3], we have 
 $$ \begin{align*} \mathcal{L}(\mathfrak{s})|_{t = \theta^{q^{j}}} = (\mathcal{L}(\mathfrak{s})|_{t = \theta})^{q^{j}} = (\operatorname{\mathrm{Li}}_{\mathfrak{s}}(\mathbf{1}) / \widetilde{\pi}^{\operatorname{\mathrm{wt}}(\mathfrak{s})})^{q^{j}} \end{align*} $$
$$ \begin{align*} \mathcal{L}(\mathfrak{s})|_{t = \theta^{q^{j}}} = (\mathcal{L}(\mathfrak{s})|_{t = \theta})^{q^{j}} = (\operatorname{\mathrm{Li}}_{\mathfrak{s}}(\mathbf{1}) / \widetilde{\pi}^{\operatorname{\mathrm{wt}}(\mathfrak{s})})^{q^{j}} \end{align*} $$
for all 
 $j \geq 0$
 (see also [Reference Chang9, Lemma 5.3.5]). Let
$j \geq 0$
 (see also [Reference Chang9, Lemma 5.3.5]). Let 
 $P = \sum _{\mathfrak {s} \in \mathcal {I}} a_{\mathfrak {s}} [\mathfrak {s}] \in \mathcal {H} (a_{\mathfrak {s}} \in k)$
. For the convenience of later use, we set
$P = \sum _{\mathfrak {s} \in \mathcal {I}} a_{\mathfrak {s}} [\mathfrak {s}] \in \mathcal {H} (a_{\mathfrak {s}} \in k)$
. For the convenience of later use, we set 
 $$ \begin{align*} \operatorname{\mathrm{Li}}_P(\mathbf{1}):=\sum_{\mathfrak{s}} a_{\mathfrak{s}} \operatorname{\mathrm{Li}}_{\mathfrak{s}}(\mathbf{1}). \end{align*} $$
$$ \begin{align*} \operatorname{\mathrm{Li}}_P(\mathbf{1}):=\sum_{\mathfrak{s}} a_{\mathfrak{s}} \operatorname{\mathrm{Li}}_{\mathfrak{s}}(\mathbf{1}). \end{align*} $$
5.1 The key lemma
 The fundamental system of Frobenius difference equations that 
 $\left \{ \mathcal {L}(\mathbf {n})\right \}_{\mathbf {n}\in \mathscr {I}(\mathfrak {s})}$
 satisfy is given in [Reference Chang9, (5.3.3),(5.3.4)] as well as [Reference Chang, Papanikolas and Yu14, (2.3.4), (2.3.7)] with all
$\left \{ \mathcal {L}(\mathbf {n})\right \}_{\mathbf {n}\in \mathscr {I}(\mathfrak {s})}$
 satisfy is given in [Reference Chang9, (5.3.3),(5.3.4)] as well as [Reference Chang, Papanikolas and Yu14, (2.3.4), (2.3.7)] with all 
 $Q_{i}=1$
 there, and it plays a crucial role in the proof of the following Lemma when applying ABP-criterion. We further mention that the first formulation of the following Lemma arises from the ideas in the proof of [Reference Chang, Papanikolas and Yu14, Thm. 2.5.2], and the second one is an extension of part of Step 3 in the proof of [Reference Ngo Dac26, Thm. 6], which dealt with
$Q_{i}=1$
 there, and it plays a crucial role in the proof of the following Lemma when applying ABP-criterion. We further mention that the first formulation of the following Lemma arises from the ideas in the proof of [Reference Chang, Papanikolas and Yu14, Thm. 2.5.2], and the second one is an extension of part of Step 3 in the proof of [Reference Ngo Dac26, Thm. 6], which dealt with 
 $w\leq 2q-2$
.
$w\leq 2q-2$
.
Lemma 5.1. Let 
 $w \geq 0$
 and
$w \geq 0$
 and 
 $\emptyset \neq M \subset \mathcal {I}_{w}$
. Let
$\emptyset \neq M \subset \mathcal {I}_{w}$
. Let 
 $P = \sum _{\mathfrak {s} \in \mathcal {I}} a_{\mathfrak {s}} [\mathfrak {s}] \in \mathcal {H} (a_{\mathfrak {s}} \in k)$
 and suppose that
$P = \sum _{\mathfrak {s} \in \mathcal {I}} a_{\mathfrak {s}} [\mathfrak {s}] \in \mathcal {H} (a_{\mathfrak {s}} \in k)$
 and suppose that 
- 
•  $\operatorname {\mathrm {Supp}}(P) \subset M$
, $\operatorname {\mathrm {Supp}}(P) \subset M$
,
- 
•  $\operatorname {\mathrm {Li}}_{P}(\mathbf {1})$
 is Eulerian; that is, $\operatorname {\mathrm {Li}}_{P}(\mathbf {1})$
 is Eulerian; that is, $\operatorname {\mathrm {Li}}_{P}(\mathbf {1}) = \sum _{\mathfrak {s}} a_{\mathfrak {s}} \operatorname {\mathrm {Li}}_{\mathfrak {s}}(\mathbf {1}) \in k \cdot \widetilde {\pi }^{w}$
, $\operatorname {\mathrm {Li}}_{P}(\mathbf {1}) = \sum _{\mathfrak {s}} a_{\mathfrak {s}} \operatorname {\mathrm {Li}}_{\mathfrak {s}}(\mathbf {1}) \in k \cdot \widetilde {\pi }^{w}$
,
- 
•  $\operatorname {\mathrm {Li}}_{\mathfrak {s}}(\mathbf {1}) (\mathfrak {s} \in \mathscr {I}(M) \cap \mathcal {I}_{\ell })$
 are linearly independent over k for each $\operatorname {\mathrm {Li}}_{\mathfrak {s}}(\mathbf {1}) (\mathfrak {s} \in \mathscr {I}(M) \cap \mathcal {I}_{\ell })$
 are linearly independent over k for each $0 \leq \ell < w$
. $0 \leq \ell < w$
.
Then the following hold:
- 
(1) We have for each $$ \begin{align*} \sum_{\mathfrak{s}' \in \mathcal{I}_{w - \operatorname{\mathrm{wt}}(\mathfrak{s})}} a_{(\mathfrak{s}, \mathfrak{s}')} \operatorname{\mathrm{Li}}_{\mathfrak{s}'}(\mathbf{1}) = 0 \ \ \mathrm{or} \ \ (q - 1) \mid (w - \operatorname{\mathrm{wt}}(\mathfrak{s})) \end{align*} $$ $$ \begin{align*} \sum_{\mathfrak{s}' \in \mathcal{I}_{w - \operatorname{\mathrm{wt}}(\mathfrak{s})}} a_{(\mathfrak{s}, \mathfrak{s}')} \operatorname{\mathrm{Li}}_{\mathfrak{s}'}(\mathbf{1}) = 0 \ \ \mathrm{or} \ \ (q - 1) \mid (w - \operatorname{\mathrm{wt}}(\mathfrak{s})) \end{align*} $$ $\mathfrak {s} \in \mathscr {I}(M)$
. In particular, if $\mathfrak {s} \in \mathscr {I}(M)$
. In particular, if $\operatorname {\mathrm {Li}}_{\mathfrak {s}'}(\mathbf {1}) (\mathfrak {s}' \in \mathcal {I}_{w - \operatorname {\mathrm {wt}}(\mathfrak {s})}, (\mathfrak {s}, \mathfrak {s}') \in \operatorname {\mathrm {Supp}}(P))$
 are linearly independent over k for each $\operatorname {\mathrm {Li}}_{\mathfrak {s}'}(\mathbf {1}) (\mathfrak {s}' \in \mathcal {I}_{w - \operatorname {\mathrm {wt}}(\mathfrak {s})}, (\mathfrak {s}, \mathfrak {s}') \in \operatorname {\mathrm {Supp}}(P))$
 are linearly independent over k for each $\mathfrak {s} \in \mathscr {I}(\operatorname {\mathrm {Supp}}(P)) \setminus \{ \emptyset \}$
, then $\mathfrak {s} \in \mathscr {I}(\operatorname {\mathrm {Supp}}(P)) \setminus \{ \emptyset \}$
, then $$ \begin{align*} \operatorname{\mathrm{Supp}}(P) \subset \{ (s_{1}, \ldots, s_{r}) \in \mathcal{I}_{w} \ | \ (q - 1) \mid s_{2}, \ldots, s_{r} \}. \end{align*} $$ $$ \begin{align*} \operatorname{\mathrm{Supp}}(P) \subset \{ (s_{1}, \ldots, s_{r}) \in \mathcal{I}_{w} \ | \ (q - 1) \mid s_{2}, \ldots, s_{r} \}. \end{align*} $$
- 
(2) The system of Frobenius equations (E M ) has a solution  $(\varepsilon _{\mathfrak {s}})_{\mathfrak {s} \in \mathscr {I}(M)} \in \mathbb {F}_{q}(t)[\theta ]^{\mathscr {I}(M)}$
 such that $(\varepsilon _{\mathfrak {s}})_{\mathfrak {s} \in \mathscr {I}(M)} \in \mathbb {F}_{q}(t)[\theta ]^{\mathscr {I}(M)}$
 such that $\varepsilon _{\mathfrak {s}} = a_{\mathfrak {s}}|_{\theta = t}$
 for each $\varepsilon _{\mathfrak {s}} = a_{\mathfrak {s}}|_{\theta = t}$
 for each $\mathfrak {s} \in M$
. $\mathfrak {s} \in M$
.
Proof. In what follows, our essential arguments are rooted in the ideas of the proof of [Reference Chang, Papanikolas and Yu14]. Let 
 $\alpha _{\mathfrak {s}} = \alpha _{\mathfrak {s}}(t) := a_{\mathfrak {s}}|_{\theta = t} \in \mathbb {F}_{q}(t)$
,
$\alpha _{\mathfrak {s}} = \alpha _{\mathfrak {s}}(t) := a_{\mathfrak {s}}|_{\theta = t} \in \mathbb {F}_{q}(t)$
, 
 $c := \operatorname {\mathrm {Li}}_{P}(\mathbf {1}) / \widetilde {\pi }^{w} \in k$
 and
$c := \operatorname {\mathrm {Li}}_{P}(\mathbf {1}) / \widetilde {\pi }^{w} \in k$
 and 
 $\mathscr {I}(M)' := \mathscr {I}(M) \setminus M$
. We may assume that
$\mathscr {I}(M)' := \mathscr {I}(M) \setminus M$
. We may assume that 
 $w> 0$
,
$w> 0$
, 
 $P \neq 0$
 and
$P \neq 0$
 and 
 $\alpha _{\mathfrak {s}} \in \mathbb {F}_{q}[t] (\mathfrak {s} \in \mathcal {I})$
. In particular,
$\alpha _{\mathfrak {s}} \in \mathbb {F}_{q}[t] (\mathfrak {s} \in \mathcal {I})$
. In particular, 
 $\mathscr {I}(M)' \neq \emptyset $
. We define matrices
$\mathscr {I}(M)' \neq \emptyset $
. We define matrices 
 $\Phi ' = (\Phi ^\prime _{\mathfrak {n}, \mathfrak {s}})_{\mathfrak {n}, \mathfrak {s} \in \mathscr {I}(M)'} \in \operatorname {\mathrm {Mat}}_{|\mathscr {I}(M)'|}(\overline {k}[t])$
 and
$\Phi ' = (\Phi ^\prime _{\mathfrak {n}, \mathfrak {s}})_{\mathfrak {n}, \mathfrak {s} \in \mathscr {I}(M)'} \in \operatorname {\mathrm {Mat}}_{|\mathscr {I}(M)'|}(\overline {k}[t])$
 and 
 $\Psi ' = (\Psi ^\prime _{\mathfrak {n}, \mathfrak {s}})_{\mathfrak {n}, \mathfrak {s} \in \mathscr {I}(M)'} \in \operatorname {\mathrm {GL}}_{|\mathscr {I}(M)'|}(\mathbb {T})$
 indexed by the set
$\Psi ' = (\Psi ^\prime _{\mathfrak {n}, \mathfrak {s}})_{\mathfrak {n}, \mathfrak {s} \in \mathscr {I}(M)'} \in \operatorname {\mathrm {GL}}_{|\mathscr {I}(M)'|}(\mathbb {T})$
 indexed by the set 
 $\mathscr {I}(M)'$
. They are defined by
$\mathscr {I}(M)'$
. They are defined by 
 $$ \begin{align*} \Phi^\prime_{\mathfrak{n}, \mathfrak{s}} := \left\{ \begin{array}{ll} (t - \theta)^{w - \operatorname{\mathrm{wt}}(\mathfrak{s})} & (\mathfrak{s} = \mathfrak{n} \ \mathrm{or} \ \mathfrak{s} = \mathfrak{n}_{+}) \\ 0 & (\mathrm{otherwise}) \end{array} \right. \mathrm{and} \ \Psi^\prime_{\mathfrak{n}, \mathfrak{s}} := \left\{ \begin{array}{ll} \mathcal{L}(\mathfrak{s}') \Omega^{w - \operatorname{\mathrm{wt}}(\mathfrak{n})} & (\mathfrak{n} = (\mathfrak{s}, \mathfrak{s}')) \\ 0 & (\mathrm{otherwise}) \end{array} \right.. \end{align*} $$
$$ \begin{align*} \Phi^\prime_{\mathfrak{n}, \mathfrak{s}} := \left\{ \begin{array}{ll} (t - \theta)^{w - \operatorname{\mathrm{wt}}(\mathfrak{s})} & (\mathfrak{s} = \mathfrak{n} \ \mathrm{or} \ \mathfrak{s} = \mathfrak{n}_{+}) \\ 0 & (\mathrm{otherwise}) \end{array} \right. \mathrm{and} \ \Psi^\prime_{\mathfrak{n}, \mathfrak{s}} := \left\{ \begin{array}{ll} \mathcal{L}(\mathfrak{s}') \Omega^{w - \operatorname{\mathrm{wt}}(\mathfrak{n})} & (\mathfrak{n} = (\mathfrak{s}, \mathfrak{s}')) \\ 0 & (\mathrm{otherwise}) \end{array} \right.. \end{align*} $$
In particular, we have 
 $\Psi ^\prime _{\mathfrak {n}, \emptyset } = \mathcal {L}(\mathfrak {n}) \Omega ^{w - \operatorname {\mathrm {wt}}(\mathfrak {n})}$
. We also define row vectors
$\Psi ^\prime _{\mathfrak {n}, \emptyset } = \mathcal {L}(\mathfrak {n}) \Omega ^{w - \operatorname {\mathrm {wt}}(\mathfrak {n})}$
. We also define row vectors 
 $\mathbf {v} = (v_{\mathfrak {s}})_{\mathfrak {s} \in \mathscr {I}(M)'} \in \operatorname {\mathrm {Mat}}_{1 \times |\mathscr {I}(M)'|}(\overline {k}[t])$
 and
$\mathbf {v} = (v_{\mathfrak {s}})_{\mathfrak {s} \in \mathscr {I}(M)'} \in \operatorname {\mathrm {Mat}}_{1 \times |\mathscr {I}(M)'|}(\overline {k}[t])$
 and 
 $\mathbf {f} = (f_{\mathfrak {s}})_{\mathfrak {s} \in \mathscr {I}(M)'} \in \operatorname {\mathrm {Mat}}_{1 \times |\mathscr {I}(M)'|}(\mathbb {T})$
 by
$\mathbf {f} = (f_{\mathfrak {s}})_{\mathfrak {s} \in \mathscr {I}(M)'} \in \operatorname {\mathrm {Mat}}_{1 \times |\mathscr {I}(M)'|}(\mathbb {T})$
 by 
 $$ \begin{align*} v_{\mathfrak{s}} := \left\{ \begin{array}{ll} \alpha_{(\mathfrak{s}, w - \operatorname{\mathrm{wt}}(\mathfrak{s}))} (t - \theta)^{w - \operatorname{\mathrm{wt}}(\mathfrak{s})} & ((\mathfrak{s}, w - \operatorname{\mathrm{wt}}(\mathfrak{s})) \in M) \\ 0 & (\mathrm{otherwise}) \end{array} \right. \mathrm{and} \ f_{\mathfrak{s}} := \sum_{\mathfrak{s}' \in \mathcal{I}_{w - \operatorname{\mathrm{wt}}(\mathfrak{s})}} \alpha_{(\mathfrak{s}, \mathfrak{s}')} \mathcal{L}(\mathfrak{s}'). \end{align*} $$
$$ \begin{align*} v_{\mathfrak{s}} := \left\{ \begin{array}{ll} \alpha_{(\mathfrak{s}, w - \operatorname{\mathrm{wt}}(\mathfrak{s}))} (t - \theta)^{w - \operatorname{\mathrm{wt}}(\mathfrak{s})} & ((\mathfrak{s}, w - \operatorname{\mathrm{wt}}(\mathfrak{s})) \in M) \\ 0 & (\mathrm{otherwise}) \end{array} \right. \mathrm{and} \ f_{\mathfrak{s}} := \sum_{\mathfrak{s}' \in \mathcal{I}_{w - \operatorname{\mathrm{wt}}(\mathfrak{s})}} \alpha_{(\mathfrak{s}, \mathfrak{s}')} \mathcal{L}(\mathfrak{s}'). \end{align*} $$
In particular, we have 
 $f_{\emptyset } := \sum _{\mathfrak {s}' \in \mathcal {I}_{w}} \alpha _{\mathfrak {s}'} \mathcal {L}(\mathfrak {s}') = \mathcal {L}(P)$
. Then we set
$f_{\emptyset } := \sum _{\mathfrak {s}' \in \mathcal {I}_{w}} \alpha _{\mathfrak {s}'} \mathcal {L}(\mathfrak {s}') = \mathcal {L}(P)$
. Then we set 
 $$ \begin{align*} \Phi := \left( \begin{array}{cc} \Phi' & 0 \\ \mathbf{v} & 1 \end{array} \right) \in \operatorname{\mathrm{Mat}}_{|\mathscr{I}(M)'| + 1}(\overline{k}[t]) \ \ \mathrm{and} \ \ \Psi := \left( \begin{array}{cc} \Psi' & 0 \\ \mathbf{f} & 1 \end{array} \right) \in \operatorname{\mathrm{GL}}_{|\mathscr{I}(M)'| + 1}(\mathbb{T}). \end{align*} $$
$$ \begin{align*} \Phi := \left( \begin{array}{cc} \Phi' & 0 \\ \mathbf{v} & 1 \end{array} \right) \in \operatorname{\mathrm{Mat}}_{|\mathscr{I}(M)'| + 1}(\overline{k}[t]) \ \ \mathrm{and} \ \ \Psi := \left( \begin{array}{cc} \Psi' & 0 \\ \mathbf{f} & 1 \end{array} \right) \in \operatorname{\mathrm{GL}}_{|\mathscr{I}(M)'| + 1}(\mathbb{T}). \end{align*} $$
We further set
 $$ \begin{align*} \widetilde{\Phi} := \left( \begin{array}{cc} 1 & 0 \\ 0 & \Phi \end{array} \right) \in \operatorname{\mathrm{Mat}}_{|\mathscr{I}(M)'| + 2}(\overline{k}[t]) \ \ \mathrm{and} \ \ \widetilde{\psi} := \left( \begin{array}{c} 1 \\ (\Psi^\prime_{\mathfrak{n}, \emptyset})_{\mathfrak{n} \in \mathscr{I}(M)'} \\ f_{\emptyset} \end{array} \right) \in \operatorname{\mathrm{Mat}}_{(|\mathscr{I}(M)'| + 2) \times 1}(\mathbb{T}). \end{align*} $$
$$ \begin{align*} \widetilde{\Phi} := \left( \begin{array}{cc} 1 & 0 \\ 0 & \Phi \end{array} \right) \in \operatorname{\mathrm{Mat}}_{|\mathscr{I}(M)'| + 2}(\overline{k}[t]) \ \ \mathrm{and} \ \ \widetilde{\psi} := \left( \begin{array}{c} 1 \\ (\Psi^\prime_{\mathfrak{n}, \emptyset})_{\mathfrak{n} \in \mathscr{I}(M)'} \\ f_{\emptyset} \end{array} \right) \in \operatorname{\mathrm{Mat}}_{(|\mathscr{I}(M)'| + 2) \times 1}(\mathbb{T}). \end{align*} $$
Then using [Reference Chang, Papanikolas and Yu14, (2.3.4), (2.3.7)], one checks that
 $$ \begin{align*} \Psi^{(- 1)} = \Phi \Psi \ \ \mathrm{and} \ \ \widetilde{\psi}^{(- 1)} = \widetilde{\Phi} \widetilde{\psi}. \end{align*} $$
$$ \begin{align*} \Psi^{(- 1)} = \Phi \Psi \ \ \mathrm{and} \ \ \widetilde{\psi}^{(- 1)} = \widetilde{\Phi} \widetilde{\psi}. \end{align*} $$
We mention that we follow [Reference Ngo Dac26] to use double indices to indicate the entries of 
 $\Phi $
 here, and putting such
$\Phi $
 here, and putting such 
 $f_{\phi }$
 into a system of Frobenius difference equations was first used by the first named author in [Reference Chang10], and later used in [Reference Chen and Harada12, Reference Ngo Dac26]. Such
$f_{\phi }$
 into a system of Frobenius difference equations was first used by the first named author in [Reference Chang10], and later used in [Reference Chen and Harada12, Reference Ngo Dac26]. Such 
 $f_{\phi }$
 naturally appears in the period matrix of the fiber coproduct of rigid analytically trivial dual t-motives in [Reference Chang and Mishiba13].
$f_{\phi }$
 naturally appears in the period matrix of the fiber coproduct of rigid analytically trivial dual t-motives in [Reference Chang and Mishiba13].
 By [Reference Anderson, Brownawell and Papanikolas2, Theorem 3.1.1], there exist 
 $g \in \overline {k}(t)$
 and
$g \in \overline {k}(t)$
 and 
 $\mathbf {g} = (g_{\mathfrak {s}})_{\mathfrak {s} \in \mathscr {I}(M)'} \in \operatorname {\mathrm {Mat}}_{1 \times |\mathscr {I}(M)'|}(\overline {k}(t))$
 such that
$\mathbf {g} = (g_{\mathfrak {s}})_{\mathfrak {s} \in \mathscr {I}(M)'} \in \operatorname {\mathrm {Mat}}_{1 \times |\mathscr {I}(M)'|}(\overline {k}(t))$
 such that 
 $$ \begin{align*} \widetilde{\mathbf{g}} \widetilde{\psi} = 0, \ \ g\ \mathrm{and\ \mathbf{g}\ are\ regular\ at}\ t = \theta \ \ \mathrm{and} \ \ \widetilde{\mathbf{g}}|_{t = \theta} = (- c, 0, \ldots, 0, 1), \end{align*} $$
$$ \begin{align*} \widetilde{\mathbf{g}} \widetilde{\psi} = 0, \ \ g\ \mathrm{and\ \mathbf{g}\ are\ regular\ at}\ t = \theta \ \ \mathrm{and} \ \ \widetilde{\mathbf{g}}|_{t = \theta} = (- c, 0, \ldots, 0, 1), \end{align*} $$
where 
 $\widetilde {\mathbf {g}} := (g, \mathbf {g}, 1)$
.
$\widetilde {\mathbf {g}} := (g, \mathbf {g}, 1)$
.
 We set 
 $B = B(t)$
 and
$B = B(t)$
 and 
 $B_{\mathfrak {s}} = B_{\mathfrak {s}}(t)$
 in
$B_{\mathfrak {s}} = B_{\mathfrak {s}}(t)$
 in 
 $\overline {k}(t)$
 by
$\overline {k}(t)$
 by 
 $$ \begin{align*} (B, (B_{\mathfrak{s}})_{\mathfrak{s} \in \mathscr{I}(M)'}, 0) := \widetilde{\mathbf{g}} - \widetilde{\mathbf{g}}^{(- 1)} \widetilde{\Phi} \in \operatorname{\mathrm{Mat}}_{1 \times (|\mathscr{I}(M)'| + 2)}(\overline{k}(t)). \end{align*} $$
$$ \begin{align*} (B, (B_{\mathfrak{s}})_{\mathfrak{s} \in \mathscr{I}(M)'}, 0) := \widetilde{\mathbf{g}} - \widetilde{\mathbf{g}}^{(- 1)} \widetilde{\Phi} \in \operatorname{\mathrm{Mat}}_{1 \times (|\mathscr{I}(M)'| + 2)}(\overline{k}(t)). \end{align*} $$
We claim that 
 $\widetilde {\mathbf {g}}^{(- 1)} \widetilde {\Phi } = \widetilde {\mathbf {g}}$
; that is,
$\widetilde {\mathbf {g}}^{(- 1)} \widetilde {\Phi } = \widetilde {\mathbf {g}}$
; that is, 
 $B = B_{\mathfrak {s}} = 0$
 for all
$B = B_{\mathfrak {s}} = 0$
 for all 
 $\mathfrak {s} \in \mathscr {I}(M)'$
. Indeed,
$\mathfrak {s} \in \mathscr {I}(M)'$
. Indeed, 
 $$ \begin{align*} B + \sum_{\mathfrak{s} \in \mathscr{I}(M)'} B_{\mathfrak{s}} \mathcal{L}(\mathfrak{s}) \Omega^{w - \operatorname{\mathrm{wt}}(\mathfrak{s})} = (B, (B_{\mathfrak{s}})_{\mathfrak{s} \in \mathscr{I}(M)'}, 0) \widetilde{\psi} = (\widetilde{\mathbf{g}} - \widetilde{\mathbf{g}}^{(- 1)} \widetilde{\Phi}) \widetilde{\psi} = \widetilde{\mathbf{g}} \widetilde{\psi} - (\widetilde{\mathbf{g}} \widetilde{\psi})^{(- 1)} = 0 \end{align*} $$
$$ \begin{align*} B + \sum_{\mathfrak{s} \in \mathscr{I}(M)'} B_{\mathfrak{s}} \mathcal{L}(\mathfrak{s}) \Omega^{w - \operatorname{\mathrm{wt}}(\mathfrak{s})} = (B, (B_{\mathfrak{s}})_{\mathfrak{s} \in \mathscr{I}(M)'}, 0) \widetilde{\psi} = (\widetilde{\mathbf{g}} - \widetilde{\mathbf{g}}^{(- 1)} \widetilde{\Phi}) \widetilde{\psi} = \widetilde{\mathbf{g}} \widetilde{\psi} - (\widetilde{\mathbf{g}} \widetilde{\psi})^{(- 1)} = 0 \end{align*} $$
and 
 $\mathscr {I}(M)' = \bigsqcup _{\ell = 0}^{w - 1} \mathscr {I}(M) \cap \mathcal {I}_{\ell }$
 imply the equality
$\mathscr {I}(M)' = \bigsqcup _{\ell = 0}^{w - 1} \mathscr {I}(M) \cap \mathcal {I}_{\ell }$
 imply the equality 
 $$ \begin{align} B + \sum_{\mathfrak{s} \in \mathscr{I}(M) \cap \mathcal{I}_{w - 1}} B_{\mathfrak{s}} \mathcal{L}(\mathfrak{s}) \Omega + \sum_{\mathfrak{s} \in \mathscr{I}(M) \cap \mathcal{I}_{w - 2}} B_{\mathfrak{s}} \mathcal{L}(\mathfrak{s}) \Omega^{2} + \cdots + \sum_{\mathfrak{s} \in \mathscr{I}(M) \cap \mathcal{I}_{0}} B_{\mathfrak{s}} \mathcal{L}(\mathfrak{s}) \Omega^{w} = 0. \end{align} $$
$$ \begin{align} B + \sum_{\mathfrak{s} \in \mathscr{I}(M) \cap \mathcal{I}_{w - 1}} B_{\mathfrak{s}} \mathcal{L}(\mathfrak{s}) \Omega + \sum_{\mathfrak{s} \in \mathscr{I}(M) \cap \mathcal{I}_{w - 2}} B_{\mathfrak{s}} \mathcal{L}(\mathfrak{s}) \Omega^{2} + \cdots + \sum_{\mathfrak{s} \in \mathscr{I}(M) \cap \mathcal{I}_{0}} B_{\mathfrak{s}} \mathcal{L}(\mathfrak{s}) \Omega^{w} = 0. \end{align} $$
We note that
- 
• B and  $B_{\mathfrak {s}} (\mathfrak {s} \in \mathscr {I}(M)')$
 are regular at $B_{\mathfrak {s}} (\mathfrak {s} \in \mathscr {I}(M)')$
 are regular at $t = \theta ^{q^{i}}$
 for $t = \theta ^{q^{i}}$
 for $j \gg 0$
, $j \gg 0$
,
- 
•  $\Omega $
 and $\Omega $
 and $\mathcal {L}(\mathfrak {s}) (\mathfrak {s} \in \mathcal {I})$
 are entire, $\mathcal {L}(\mathfrak {s}) (\mathfrak {s} \in \mathcal {I})$
 are entire,
- 
•  $\Omega (\theta ^{q^{j}}) = 0$
 for $\Omega (\theta ^{q^{j}}) = 0$
 for $j \geq 1$
, $j \geq 1$
,
- 
•  $\mathcal {L}(\mathfrak {s})|_{t = \theta ^{q^{j}}} = (\operatorname {\mathrm {Li}}_{\mathfrak {s}}(\mathbf {1}) / \widetilde {\pi }^{\operatorname {\mathrm {wt}}(\mathfrak {s})})^{q^{j}}$
 for $\mathcal {L}(\mathfrak {s})|_{t = \theta ^{q^{j}}} = (\operatorname {\mathrm {Li}}_{\mathfrak {s}}(\mathbf {1}) / \widetilde {\pi }^{\operatorname {\mathrm {wt}}(\mathfrak {s})})^{q^{j}}$
 for $\mathfrak {s} \in \mathcal {I}$
 and $\mathfrak {s} \in \mathcal {I}$
 and $j \geq 0$
. $j \geq 0$
.
Thus, evaluating at 
 $t = \theta ^{q^{j}}$
 for
$t = \theta ^{q^{j}}$
 for 
 $j \gg 0$
 in (5.1) implies
$j \gg 0$
 in (5.1) implies 
 $B(\theta ^{q^{j}}) = 0$
. Since B is rational, we have
$B(\theta ^{q^{j}}) = 0$
. Since B is rational, we have 
 $B = 0$
. Then dividing (5.1) by
$B = 0$
. Then dividing (5.1) by 
 $\Omega $
 and evaluating at
$\Omega $
 and evaluating at 
 $t = \theta ^{q^{j}}$
 for
$t = \theta ^{q^{j}}$
 for 
 $j \gg 0$
 imply
$j \gg 0$
 imply 
 $$ \begin{align*} \sum_{\mathfrak{s} \in \mathscr{I}(M) \cap \mathcal{I}_{w - 1}} B_{\mathfrak{s}}(\theta^{q^{j}}) (\operatorname{\mathrm{Li}}_{\mathfrak{s}}(\mathbf{1}) / \widetilde{\pi}^{w - 1})^{q^{j}} = 0. \end{align*} $$
$$ \begin{align*} \sum_{\mathfrak{s} \in \mathscr{I}(M) \cap \mathcal{I}_{w - 1}} B_{\mathfrak{s}}(\theta^{q^{j}}) (\operatorname{\mathrm{Li}}_{\mathfrak{s}}(\mathbf{1}) / \widetilde{\pi}^{w - 1})^{q^{j}} = 0. \end{align*} $$
This is equivalent to
 $$ \begin{align*} \sum_{\mathfrak{s} \in \mathscr{I}(M) \cap \mathcal{I}_{w - 1}} B_{\mathfrak{s}}(\theta^{q^{j}})^{q^{- j}} \operatorname{\mathrm{Li}}_{\mathfrak{s}}(\mathbf{1}) = 0. \end{align*} $$
$$ \begin{align*} \sum_{\mathfrak{s} \in \mathscr{I}(M) \cap \mathcal{I}_{w - 1}} B_{\mathfrak{s}}(\theta^{q^{j}})^{q^{- j}} \operatorname{\mathrm{Li}}_{\mathfrak{s}}(\mathbf{1}) = 0. \end{align*} $$
By the assumption of linear independence and [Reference Chang9, Theorem 2.2.1], we have 
 $B_{\mathfrak {s}}(\theta ^{q^{j}}) = 0$
. Thus, we have
$B_{\mathfrak {s}}(\theta ^{q^{j}}) = 0$
. Thus, we have 
 $B_{\mathfrak {s}} = 0$
 for all
$B_{\mathfrak {s}} = 0$
 for all 
 $\mathfrak {s} \in \mathscr {I}(M) \cap \mathcal {I}_{w - 1}$
. Repeating this process, we have
$\mathfrak {s} \in \mathscr {I}(M) \cap \mathcal {I}_{w - 1}$
. Repeating this process, we have 
 $B_{\mathfrak {s}} = 0$
 for all
$B_{\mathfrak {s}} = 0$
 for all 
 $\mathfrak {s} \in \mathscr {I}(M)'$
. We note that the claim implies
$\mathfrak {s} \in \mathscr {I}(M)'$
. We note that the claim implies 
 $$ \begin{align} \left( \begin{array}{cc} \operatorname{\mathrm{Id}} & 0 \\ \mathbf{g} & 1 \end{array} \right)^{(- 1)} \left( \begin{array}{cc} \Phi' & 0 \\ \mathbf{v} & 1 \end{array} \right) = \left( \begin{array}{cc} \Phi' & 0 \\ 0 & 1 \end{array} \right) \left( \begin{array}{cc} \operatorname{\mathrm{Id}} & 0 \\ \mathbf{g} & 1 \end{array} \right). \end{align} $$
$$ \begin{align} \left( \begin{array}{cc} \operatorname{\mathrm{Id}} & 0 \\ \mathbf{g} & 1 \end{array} \right)^{(- 1)} \left( \begin{array}{cc} \Phi' & 0 \\ \mathbf{v} & 1 \end{array} \right) = \left( \begin{array}{cc} \Phi' & 0 \\ 0 & 1 \end{array} \right) \left( \begin{array}{cc} \operatorname{\mathrm{Id}} & 0 \\ \mathbf{g} & 1 \end{array} \right). \end{align} $$
(1) We set
 $$ \begin{align*} X := \left( \begin{array}{cc} \operatorname{\mathrm{Id}} & 0 \\ \mathbf{g} & 1 \end{array} \right) \Psi = \left( \begin{array}{cc} \Psi' & 0 \\ \mathbf{g} \Psi' + \mathbf{f} & 1 \end{array} \right) \in \operatorname{\mathrm{GL}}_{|\mathscr{I}(M)'| + 1}(\operatorname{\mathrm{Frac}}(\mathbb{T})). \end{align*} $$
$$ \begin{align*} X := \left( \begin{array}{cc} \operatorname{\mathrm{Id}} & 0 \\ \mathbf{g} & 1 \end{array} \right) \Psi = \left( \begin{array}{cc} \Psi' & 0 \\ \mathbf{g} \Psi' + \mathbf{f} & 1 \end{array} \right) \in \operatorname{\mathrm{GL}}_{|\mathscr{I}(M)'| + 1}(\operatorname{\mathrm{Frac}}(\mathbb{T})). \end{align*} $$
By using (5.2), we can verify that 
 $X^{(- 1)} = \left ( \begin {array}{cc} \Phi ' & 0 \\ 0 & 1 \end {array} \right ) X$
. Thus, by [Reference Papanikolas27, §4.1.6],
$X^{(- 1)} = \left ( \begin {array}{cc} \Phi ' & 0 \\ 0 & 1 \end {array} \right ) X$
. Thus, by [Reference Papanikolas27, §4.1.6], 
 $$ \begin{align*} \operatorname{\mathrm{GL}}_{|\mathscr{I}(M)'| + 1}(\mathbb{F}_{q}(t)) \ni \left( \begin{array}{cc} \Psi' & 0 \\ 0 & 1 \end{array} \right)^{- 1} X = \left( \begin{array}{cc} \operatorname{\mathrm{Id}} & 0 \\ \mathbf{g} \Psi' + \mathbf{f} & 1 \end{array} \right) =: \left( \begin{array}{cc} \operatorname{\mathrm{Id}} & 0 \\ (h_{\mathfrak{s}})_{\mathfrak{s} \in \mathscr{I}(M)'} & 1 \end{array} \right). \end{align*} $$
$$ \begin{align*} \operatorname{\mathrm{GL}}_{|\mathscr{I}(M)'| + 1}(\mathbb{F}_{q}(t)) \ni \left( \begin{array}{cc} \Psi' & 0 \\ 0 & 1 \end{array} \right)^{- 1} X = \left( \begin{array}{cc} \operatorname{\mathrm{Id}} & 0 \\ \mathbf{g} \Psi' + \mathbf{f} & 1 \end{array} \right) =: \left( \begin{array}{cc} \operatorname{\mathrm{Id}} & 0 \\ (h_{\mathfrak{s}})_{\mathfrak{s} \in \mathscr{I}(M)'} & 1 \end{array} \right). \end{align*} $$
Then evaluating at 
 $t = \theta ^{q^{j}}$
 for
$t = \theta ^{q^{j}}$
 for 
 $j \gg 0$
 in
$j \gg 0$
 in 
 $\mathbf {g} \Psi ' + \mathbf {f} = (h_{\mathfrak {s}})_{\mathfrak {s} \in \mathscr {I}(M)'}$
, we have
$\mathbf {g} \Psi ' + \mathbf {f} = (h_{\mathfrak {s}})_{\mathfrak {s} \in \mathscr {I}(M)'}$
, we have 
 $f_{\mathfrak {s}}(\theta ^{q^{j}}) = h_{\mathfrak {s}}(\theta ^{q^{j}}) = h_{\mathfrak {s}}(\theta )^{q^{j}}$
. Since
$f_{\mathfrak {s}}(\theta ^{q^{j}}) = h_{\mathfrak {s}}(\theta ^{q^{j}}) = h_{\mathfrak {s}}(\theta )^{q^{j}}$
. Since 
 $$ \begin{align*} f_{\mathfrak{s}}(\theta^{q^{j}}) = \sum_{\mathfrak{s}' \in \mathcal{I}_{w - \operatorname{\mathrm{wt}}(\mathfrak{s})}} \alpha_{(\mathfrak{s}, \mathfrak{s}')}(\theta^{q^{j}}) \mathcal{L}(\mathfrak{s}')|_{t = \theta^{q^{j}}} = \sum_{\mathfrak{s}' \in \mathcal{I}_{w - \operatorname{\mathrm{wt}}(\mathfrak{s})}} \alpha_{(\mathfrak{s}, \mathfrak{s}')}(\theta)^{q^{j}} (\operatorname{\mathrm{Li}}_{\mathfrak{s}'}(\mathbf{1}) / \widetilde{\pi}^{w - \operatorname{\mathrm{wt}}(\mathfrak{s})})^{q^{j}} = f_{\mathfrak{s}}(\theta)^{q^{j}}, \end{align*} $$
$$ \begin{align*} f_{\mathfrak{s}}(\theta^{q^{j}}) = \sum_{\mathfrak{s}' \in \mathcal{I}_{w - \operatorname{\mathrm{wt}}(\mathfrak{s})}} \alpha_{(\mathfrak{s}, \mathfrak{s}')}(\theta^{q^{j}}) \mathcal{L}(\mathfrak{s}')|_{t = \theta^{q^{j}}} = \sum_{\mathfrak{s}' \in \mathcal{I}_{w - \operatorname{\mathrm{wt}}(\mathfrak{s})}} \alpha_{(\mathfrak{s}, \mathfrak{s}')}(\theta)^{q^{j}} (\operatorname{\mathrm{Li}}_{\mathfrak{s}'}(\mathbf{1}) / \widetilde{\pi}^{w - \operatorname{\mathrm{wt}}(\mathfrak{s})})^{q^{j}} = f_{\mathfrak{s}}(\theta)^{q^{j}}, \end{align*} $$
we have 
 $f_{\mathfrak {s}}(\theta ) = h_{\mathfrak {s}}(\theta ) \in k$
 for each
$f_{\mathfrak {s}}(\theta ) = h_{\mathfrak {s}}(\theta ) \in k$
 for each 
 $\mathfrak {s} \in \mathscr {I}(M)'$
. Thus, we have
$\mathfrak {s} \in \mathscr {I}(M)'$
. Thus, we have 
 $$ \begin{align*} \sum_{\mathfrak{s}' \in \mathcal{I}_{w - \operatorname{\mathrm{wt}}(\mathfrak{s})}} a_{(\mathfrak{s}, \mathfrak{s}')} \operatorname{\mathrm{Li}}_{\mathfrak{s}'}(\mathbf{1}) \in k \cdot \widetilde{\pi}^{w - \operatorname{\mathrm{wt}}(\mathfrak{s})} \end{align*} $$
$$ \begin{align*} \sum_{\mathfrak{s}' \in \mathcal{I}_{w - \operatorname{\mathrm{wt}}(\mathfrak{s})}} a_{(\mathfrak{s}, \mathfrak{s}')} \operatorname{\mathrm{Li}}_{\mathfrak{s}'}(\mathbf{1}) \in k \cdot \widetilde{\pi}^{w - \operatorname{\mathrm{wt}}(\mathfrak{s})} \end{align*} $$
for each 
 $\mathfrak {s} \in \mathscr {I}(M)'$
. We note that this holds whenever
$\mathfrak {s} \in \mathscr {I}(M)'$
. We note that this holds whenever 
 $\mathfrak {s} \in M$
. Then the first statement of (1) follows from this relation because
$\mathfrak {s} \in M$
. Then the first statement of (1) follows from this relation because 
 $\widetilde {\pi } \in (- \theta )^{\frac {1}{q - 1}} \cdot k_{\infty }^{\times }$
.
$\widetilde {\pi } \in (- \theta )^{\frac {1}{q - 1}} \cdot k_{\infty }^{\times }$
.
 Next we prove the second statement of (1). Let 
 $(\mathfrak {s}, \mathfrak {s}") \in \operatorname {\mathrm {Supp}}(P)$
 with
$(\mathfrak {s}, \mathfrak {s}") \in \operatorname {\mathrm {Supp}}(P)$
 with 
 $\mathfrak {s} \neq \emptyset $
. Then by the first statement of (1) and the assumption on the linear independence of the second statement of (1), we have
$\mathfrak {s} \neq \emptyset $
. Then by the first statement of (1) and the assumption on the linear independence of the second statement of (1), we have 
 $(q - 1) \mid (w - \operatorname {\mathrm {wt}}(\mathfrak {s})) = \operatorname {\mathrm {wt}}(\mathfrak {s}")$
.
$(q - 1) \mid (w - \operatorname {\mathrm {wt}}(\mathfrak {s})) = \operatorname {\mathrm {wt}}(\mathfrak {s}")$
.
 (2) By (5.2) and [Reference Chang, Papanikolas and Yu14, Proposition 2.2.1], there exists 
 $\alpha \in \mathbb {F}_{q}[t] \setminus \{ 0 \}$
 such that
$\alpha \in \mathbb {F}_{q}[t] \setminus \{ 0 \}$
 such that 
 $\alpha \mathbf {g} \in \operatorname {\mathrm {Mat}}_{1 \times |\mathscr {I}(M)'|}(\overline {k}[t])$
. If we set
$\alpha \mathbf {g} \in \operatorname {\mathrm {Mat}}_{1 \times |\mathscr {I}(M)'|}(\overline {k}[t])$
. If we set 
 $\varepsilon _{\mathfrak {s}} := g_{\mathfrak {s}}^{(- 1)} (\mathfrak {s} \in \mathscr {I}(M)')$
 and
$\varepsilon _{\mathfrak {s}} := g_{\mathfrak {s}}^{(- 1)} (\mathfrak {s} \in \mathscr {I}(M)')$
 and 
 $\varepsilon _{\mathfrak {s}} := \alpha _{\mathfrak {s}} \in \mathbb {F}_{q}(t) (\mathfrak {s} \in M)$
, then
$\varepsilon _{\mathfrak {s}} := \alpha _{\mathfrak {s}} \in \mathbb {F}_{q}(t) (\mathfrak {s} \in M)$
, then 
 $$ \begin{align*} ((\varepsilon_{\mathfrak{s}})_{\mathfrak{s} \in \mathscr{I}(M)'}, 1) \left( \begin{array}{c} \Phi' \\ \mathbf{v} \end{array} \right) = (\varepsilon_{\mathfrak{s}}^{(1)})_{\mathfrak{s} \in \mathscr{I}(M)'} \ \ \mathrm{and} \ \ \varepsilon_{\mathfrak{s}}^{(1)} = \varepsilon_{\mathfrak{s}} \ (\mathfrak{s} \in M) \end{align*} $$
$$ \begin{align*} ((\varepsilon_{\mathfrak{s}})_{\mathfrak{s} \in \mathscr{I}(M)'}, 1) \left( \begin{array}{c} \Phi' \\ \mathbf{v} \end{array} \right) = (\varepsilon_{\mathfrak{s}}^{(1)})_{\mathfrak{s} \in \mathscr{I}(M)'} \ \ \mathrm{and} \ \ \varepsilon_{\mathfrak{s}}^{(1)} = \varepsilon_{\mathfrak{s}} \ (\mathfrak{s} \in M) \end{align*} $$
give the desired equations.
5.2 Linear independence
With the crucial properties of Lemma 5.1 established, we are able to show the following linear independence result.
Theorem 5.2. For each 
 $w \geq 0$
, the elements
$w \geq 0$
, the elements 
 $$ \begin{align*} \operatorname{\mathrm{Li}}_{\mathfrak{s}}(\mathbf{1}) \ \ \mathrm{with} \ \ \mathfrak{s} \in \mathcal{I}^{\mathrm{ND}}_{w} \end{align*} $$
$$ \begin{align*} \operatorname{\mathrm{Li}}_{\mathfrak{s}}(\mathbf{1}) \ \ \mathrm{with} \ \ \mathfrak{s} \in \mathcal{I}^{\mathrm{ND}}_{w} \end{align*} $$
form a basis of 
 $\mathcal {Z}_{w}$
.
$\mathcal {Z}_{w}$
.
Proof. (cf. [Reference Ngo Dac26, p. 388] for the special case of k-linear independence of 
 $\zeta _{A}(w)$
 and
$\zeta _{A}(w)$
 and 
 $\zeta _{A}(w - (q - 1), q - 1)$
 with
$\zeta _{A}(w - (q - 1), q - 1)$
 with 
 $w \leq 2 q - 2$
.) By Theorem 3.8,
$w \leq 2 q - 2$
.) By Theorem 3.8, 
 $\left \{ \operatorname {\mathrm {Li}}_{\mathfrak {s}}(\mathbf {1})| \mathfrak {s}\in \mathcal {I}^{\mathrm {ND}}_{w} \right \}$
 is a generating set for
$\left \{ \operatorname {\mathrm {Li}}_{\mathfrak {s}}(\mathbf {1})| \mathfrak {s}\in \mathcal {I}^{\mathrm {ND}}_{w} \right \}$
 is a generating set for 
 $\mathcal {Z}_{w}$
. Thus, it is enough to show that the given elements are linearly independent over k. This is proved by induction on w. When
$\mathcal {Z}_{w}$
. Thus, it is enough to show that the given elements are linearly independent over k. This is proved by induction on w. When 
 $w = 0$
, we have
$w = 0$
, we have 
 $\mathcal {I}^{\mathrm {ND}}_{0} = \{ \emptyset \}$
, and
$\mathcal {I}^{\mathrm {ND}}_{0} = \{ \emptyset \}$
, and 
 $\operatorname {\mathrm {Li}}_{\emptyset }(\mathbf {1}) = 1$
 is linearly independent over k.
$\operatorname {\mathrm {Li}}_{\emptyset }(\mathbf {1}) = 1$
 is linearly independent over k.
 Let 
 $w \geq 1$
 and assume that the elements
$w \geq 1$
 and assume that the elements 
 $\operatorname {\mathrm {Li}}_{\mathfrak {s}}(\mathbf {1})$
 with
$\operatorname {\mathrm {Li}}_{\mathfrak {s}}(\mathbf {1})$
 with 
 $\mathfrak {s} \in \mathcal {I}^{\mathrm {ND}}_{w'}$
 are linearly independent over k for
$\mathfrak {s} \in \mathcal {I}^{\mathrm {ND}}_{w'}$
 are linearly independent over k for 
 $w' < w$
. Let
$w' < w$
. Let 
 $P = \sum _{\mathfrak {s} \in \mathcal {I}} \alpha _{\mathfrak {s}}(\theta ) [\mathfrak {s}] \in \mathcal {H} (\alpha _{\mathfrak {s}} = \alpha _{\mathfrak {s}}(t) \in \mathbb {F}_{q}(t))$
 be a linear relation among
$P = \sum _{\mathfrak {s} \in \mathcal {I}} \alpha _{\mathfrak {s}}(\theta ) [\mathfrak {s}] \in \mathcal {H} (\alpha _{\mathfrak {s}} = \alpha _{\mathfrak {s}}(t) \in \mathbb {F}_{q}(t))$
 be a linear relation among 
 $\operatorname {\mathrm {Li}}_{\mathfrak {s}}(\mathbf {1})$
’s over k such that
$\operatorname {\mathrm {Li}}_{\mathfrak {s}}(\mathbf {1})$
’s over k such that 
 $\operatorname {\mathrm {Supp}}(P) \subset \mathcal {I}^{\mathrm {ND}}_{w}$
. By Lemma 5.1 (1) for
$\operatorname {\mathrm {Supp}}(P) \subset \mathcal {I}^{\mathrm {ND}}_{w}$
. By Lemma 5.1 (1) for 
 $M = \operatorname {\mathrm {Supp}}(P)$
 and the induction hypothesis, we have
$M = \operatorname {\mathrm {Supp}}(P)$
 and the induction hypothesis, we have 
 $\operatorname {\mathrm {Supp}}(P) \subset \mathcal {I}^{\mathrm {ND}_{0}}_{w}$
. By Lemma 5.1 (2) for
$\operatorname {\mathrm {Supp}}(P) \subset \mathcal {I}^{\mathrm {ND}_{0}}_{w}$
. By Lemma 5.1 (2) for 
 $M = \mathcal {I}^{\mathrm {ND}_{0}}_{w}$
, there exists a solution
$M = \mathcal {I}^{\mathrm {ND}_{0}}_{w}$
, there exists a solution 
 $(\varepsilon _{\mathfrak {s}}) \in \mathscr {X}_{w}$
 such that
$(\varepsilon _{\mathfrak {s}}) \in \mathscr {X}_{w}$
 such that 
 $\varepsilon _{\mathfrak {s}} = \alpha _{\mathfrak {s}}$
 for all
$\varepsilon _{\mathfrak {s}} = \alpha _{\mathfrak {s}}$
 for all 
 $\mathfrak {s} \in \mathcal {I}^{\mathrm {ND}_{0}}_{w}$
.
$\mathfrak {s} \in \mathcal {I}^{\mathrm {ND}_{0}}_{w}$
.
 When 
 $(q - 1) \nmid w$
, Theorem 4.8 implies that
$(q - 1) \nmid w$
, Theorem 4.8 implies that 
 $\alpha _{\mathfrak {s}} = 0$
 for all
$\alpha _{\mathfrak {s}} = 0$
 for all 
 $\mathfrak {s} \in \mathcal {I}^{\mathrm {ND}_{0}}_{w}$
. When
$\mathfrak {s} \in \mathcal {I}^{\mathrm {ND}_{0}}_{w}$
. When 
 $(q - 1) \mid w$
, we have
$(q - 1) \mid w$
, we have 
 ${\widetilde {\pi }}^{w}\in \mathcal {Z}_w$
 and hence Theorem 3.8 implies that there exists
${\widetilde {\pi }}^{w}\in \mathcal {Z}_w$
 and hence Theorem 3.8 implies that there exists 
 $P_{w} = \sum _{\mathfrak {s} \in \mathcal {I}} \beta _{\mathfrak {s}}(\theta ) [\mathfrak {s}] \in \mathcal {H}_{w} (\beta _{\mathfrak {s}}(t) \in \mathbb {F}_{q}(t))$
 such that
$P_{w} = \sum _{\mathfrak {s} \in \mathcal {I}} \beta _{\mathfrak {s}}(\theta ) [\mathfrak {s}] \in \mathcal {H}_{w} (\beta _{\mathfrak {s}}(t) \in \mathbb {F}_{q}(t))$
 such that 
 $\operatorname {\mathrm {Supp}}(P_{w}) \subset \mathcal {I}^{\mathrm {ND}}_{w}$
 and
$\operatorname {\mathrm {Supp}}(P_{w}) \subset \mathcal {I}^{\mathrm {ND}}_{w}$
 and 
 $\operatorname {\mathrm {Li}}_{P_{w}}(\mathbf {1}) = \widetilde {\pi }^{w}$
. It is clear that
$\operatorname {\mathrm {Li}}_{P_{w}}(\mathbf {1}) = \widetilde {\pi }^{w}$
. It is clear that 
 $P_{w} \neq 0$
. By Lemma 5.1 (1) for
$P_{w} \neq 0$
. By Lemma 5.1 (1) for 
 $M = \operatorname {\mathrm {Supp}}(P_{w})$
, we have
$M = \operatorname {\mathrm {Supp}}(P_{w})$
, we have 
 $\operatorname {\mathrm {Supp}}(P_{w}) \subset \mathcal {I}^{\mathrm {ND}_{0}}_{w}$
. By Lemma 5.1 (2) for
$\operatorname {\mathrm {Supp}}(P_{w}) \subset \mathcal {I}^{\mathrm {ND}_{0}}_{w}$
. By Lemma 5.1 (2) for 
 $M = \mathcal {I}^{\mathrm {ND}_{0}}_{w}$
, there exists a solution
$M = \mathcal {I}^{\mathrm {ND}_{0}}_{w}$
, there exists a solution 
 $(\varepsilon _{\mathfrak {s}}') \in \mathscr {X}_{w}$
 such that
$(\varepsilon _{\mathfrak {s}}') \in \mathscr {X}_{w}$
 such that 
 $\varepsilon ^\prime _{\mathfrak {s}} = \beta _{\mathfrak {s}}$
 for all
$\varepsilon ^\prime _{\mathfrak {s}} = \beta _{\mathfrak {s}}$
 for all 
 $\mathfrak {s} \in \mathcal {I}^{\mathrm {ND}_{0}}_{w}$
. Then by Theorem 4.8, there exists an
$\mathfrak {s} \in \mathcal {I}^{\mathrm {ND}_{0}}_{w}$
. Then by Theorem 4.8, there exists an 
 $\alpha \in \mathbb {F}_{q}(t)$
 for which
$\alpha \in \mathbb {F}_{q}(t)$
 for which 
 $(\varepsilon _{\mathfrak {s}})=\alpha (\varepsilon _{\mathfrak {s}}')$
, and hence we have
$(\varepsilon _{\mathfrak {s}})=\alpha (\varepsilon _{\mathfrak {s}}')$
, and hence we have 
 $P = \alpha (\theta ) P_{w}$
. Then we have
$P = \alpha (\theta ) P_{w}$
. Then we have 
 $$ \begin{align*} 0 = \operatorname{\mathrm{Li}}_{P}(\mathbf{1}) = \operatorname{\mathrm{Li}}_{\alpha (\theta) P_{w}}(\mathbf{1}) = \alpha(\theta) \widetilde{\pi}^{w}. \end{align*} $$
$$ \begin{align*} 0 = \operatorname{\mathrm{Li}}_{P}(\mathbf{1}) = \operatorname{\mathrm{Li}}_{\alpha (\theta) P_{w}}(\mathbf{1}) = \alpha(\theta) \widetilde{\pi}^{w}. \end{align*} $$
Thus, 
 $\alpha = 0$
 and
$\alpha = 0$
 and 
 $P = 0$
.
$P = 0$
.
5.3 Proof of Theorem 1.5
 With the fundamental results established, we can now give a short proof of Theorem 1.5. Given 
 $w\in \mathbb {Z}_{>0}$
, we claim that
$w\in \mathbb {Z}_{>0}$
, we claim that 
 $\mathcal {B}_{w}^{\mathrm {T}}$
 is a basis of the k-vector space
$\mathcal {B}_{w}^{\mathrm {T}}$
 is a basis of the k-vector space 
 $\mathcal {Z}_{w}$
. By Theorem 5.2,
$\mathcal {Z}_{w}$
. By Theorem 5.2, 
 $\left \{ \operatorname {\mathrm {Li}}_{\mathfrak {s}}(\mathbf {1})| \mathfrak {s}\in \mathcal {I}^{\mathrm {ND}}_{w} \right \}$
 is a k-basis of
$\left \{ \operatorname {\mathrm {Li}}_{\mathfrak {s}}(\mathbf {1})| \mathfrak {s}\in \mathcal {I}^{\mathrm {ND}}_{w} \right \}$
 is a k-basis of 
 $\mathcal {Z}_{w}$
. Since
$\mathcal {Z}_{w}$
. Since 
 $|\mathcal {I}^{\mathrm {ND}}_{w}|=|\mathcal {I}^{\mathrm {T}}_{w}|$
 by Proposition 2.1, and
$|\mathcal {I}^{\mathrm {ND}}_{w}|=|\mathcal {I}^{\mathrm {T}}_{w}|$
 by Proposition 2.1, and 
 $\mathcal {B}^{\mathrm {T}}_{w}$
 is a generating set of
$\mathcal {B}^{\mathrm {T}}_{w}$
 is a generating set of 
 $\mathcal {Z}_{w}$
 by Corollary 3.7, we have that
$\mathcal {Z}_{w}$
 by Corollary 3.7, we have that 
 $$\begin{align*}|\mathcal{B}_{w}^{\mathrm{T}}| \geq \dim_{k} \mathcal{Z}_{w}=|\mathcal{I}^{\mathrm{ND}}_{w}|=|\mathcal{I}^{\mathrm{T}}_{w}|\geq |\mathcal{B}_{w}^{\mathrm{T}}|,\end{align*}$$
$$\begin{align*}|\mathcal{B}_{w}^{\mathrm{T}}| \geq \dim_{k} \mathcal{Z}_{w}=|\mathcal{I}^{\mathrm{ND}}_{w}|=|\mathcal{I}^{\mathrm{T}}_{w}|\geq |\mathcal{B}_{w}^{\mathrm{T}}|,\end{align*}$$
whence the desired result follows.
5.4 Generating set of linear relations
 Recall the k-linear map 
 $\mathscr {U}^{\zeta }$
 defined in Definition 3.4, and Theorem 3.6 asserts that for
$\mathscr {U}^{\zeta }$
 defined in Definition 3.4, and Theorem 3.6 asserts that for 
 $\mathfrak {s}\in \mathcal {I}_{w} \setminus \mathcal {I}^{\mathrm {T}}_{w}$
,
$\mathfrak {s}\in \mathcal {I}_{w} \setminus \mathcal {I}^{\mathrm {T}}_{w}$
, 
 $$ \begin{align} \mathscr{L}^{\zeta}\left( [\mathfrak{s}]-\mathscr{U}^{\zeta}(\mathfrak{s}) \right)=0. \end{align} $$
$$ \begin{align} \mathscr{L}^{\zeta}\left( [\mathfrak{s}]-\mathscr{U}^{\zeta}(\mathfrak{s}) \right)=0. \end{align} $$
We prove in the following theorem, which verifies the 
 $\mathscr {B}^{*}$
-version of [Reference Todd30, Conjecture 5.1], that these relations account for all k-linear relations among MZV’s of the same weight.
$\mathscr {B}^{*}$
-version of [Reference Todd30, Conjecture 5.1], that these relations account for all k-linear relations among MZV’s of the same weight.
Theorem 5.3. Let w be a positive integer. Then all the k-linear relations among the MZV’s of weight w are generated by (5.3) for 
 $\mathfrak {s}\in \mathcal {I}_{w} \setminus \mathcal {I}^{\mathrm {T}}_{w}$
. In other words, if we denote by
$\mathfrak {s}\in \mathcal {I}_{w} \setminus \mathcal {I}^{\mathrm {T}}_{w}$
. In other words, if we denote by 
 $\mathscr {L}^{\zeta }_{w}:= \mathscr {L}^{\zeta }|_{\mathcal {H}_{w}}:=\left ( [\mathfrak {s}]\mapsto \zeta _{A}(\mathfrak {s}) \right ) :\mathcal {H}_{w} \twoheadrightarrow \mathcal {Z}_{w}$
 and put
$\mathscr {L}^{\zeta }_{w}:= \mathscr {L}^{\zeta }|_{\mathcal {H}_{w}}:=\left ( [\mathfrak {s}]\mapsto \zeta _{A}(\mathfrak {s}) \right ) :\mathcal {H}_{w} \twoheadrightarrow \mathcal {Z}_{w}$
 and put 
 $$\begin{align*}\mathscr{R}_{w}:=\operatorname{\mathrm{Span}}_{k}\left\{[\mathfrak{s}]-\mathscr{U}^{\zeta}(\mathfrak{s}) \mid \mathfrak{s}\in \mathcal{I}_{w} \setminus \mathcal{I}^{\mathrm{T}}_{w} \right\}\subset \mathcal{H}_{w} ,\end{align*}$$
$$\begin{align*}\mathscr{R}_{w}:=\operatorname{\mathrm{Span}}_{k}\left\{[\mathfrak{s}]-\mathscr{U}^{\zeta}(\mathfrak{s}) \mid \mathfrak{s}\in \mathcal{I}_{w} \setminus \mathcal{I}^{\mathrm{T}}_{w} \right\}\subset \mathcal{H}_{w} ,\end{align*}$$
then
 $$\begin{align*}\operatorname{\mathrm{Ker}}\mathscr{L}^{\zeta}_{w}= \mathscr{R}_{w}.\end{align*}$$
$$\begin{align*}\operatorname{\mathrm{Ker}}\mathscr{L}^{\zeta}_{w}= \mathscr{R}_{w}.\end{align*}$$
Moreover, we have
 $$\begin{align*}\operatorname{\mathrm{Ker}} \mathscr{L}^{\zeta}=\bigoplus_{w\in \mathbb{N}}\mathscr{R}_{w} .\end{align*}$$
$$\begin{align*}\operatorname{\mathrm{Ker}} \mathscr{L}^{\zeta}=\bigoplus_{w\in \mathbb{N}}\mathscr{R}_{w} .\end{align*}$$
Proof. Theorem 3.6 implies the inclusion 
 $\operatorname {\mathrm {Ker}} \mathscr {L}^{\zeta }_{w} \supset \mathscr {R}_{w}$
, and Remark 3.5 implies
$\operatorname {\mathrm {Ker}} \mathscr {L}^{\zeta }_{w} \supset \mathscr {R}_{w}$
, and Remark 3.5 implies 
 $$\begin{align*}\mathscr{R}_{w}=\operatorname{\mathrm{Span}}_{k}\left\{P-\mathscr{U}^{\zeta}(P) \mid P \in \mathcal{H}_{w} \right\}.\end{align*}$$
$$\begin{align*}\mathscr{R}_{w}=\operatorname{\mathrm{Span}}_{k}\left\{P-\mathscr{U}^{\zeta}(P) \mid P \in \mathcal{H}_{w} \right\}.\end{align*}$$
We fix a positive integer e given in Theorem 3.6. Then for each 
 $P \in \mathcal {H}_{w}$
, we have
$P \in \mathcal {H}_{w}$
, we have 
 $$\begin{align*}P \equiv \mathscr{U}^{\zeta}(P) \equiv \cdots \equiv (\mathscr{U}^{\zeta})^{e}(P) \bmod \mathscr{R}_{w}.\end{align*}$$
$$\begin{align*}P \equiv \mathscr{U}^{\zeta}(P) \equiv \cdots \equiv (\mathscr{U}^{\zeta})^{e}(P) \bmod \mathscr{R}_{w}.\end{align*}$$
By these relations and Theorem 3.6, the quotient space 
 $\mathcal {H}_{w} / \mathscr {R}_{w}$
 is spanned by the image of
$\mathcal {H}_{w} / \mathscr {R}_{w}$
 is spanned by the image of 
 $\mathcal {I}^{\mathrm {T}}_{w}$
. It follows that
$\mathcal {I}^{\mathrm {T}}_{w}$
. It follows that 
 $$\begin{align*}|\mathcal{I}^{\mathrm{T}}_{w}| \geq \dim_{k} \mathcal{H}_{w} / \mathscr{R}_{w} \geq \dim_{k} \mathcal{H}_{w} / \operatorname{\mathrm{Ker}} \mathscr{L}^{\zeta}_{w} = \dim_{k} \mathcal{Z}_{w} = |\mathcal{I}^{\mathrm{T}}_{w}|, \end{align*}$$
$$\begin{align*}|\mathcal{I}^{\mathrm{T}}_{w}| \geq \dim_{k} \mathcal{H}_{w} / \mathscr{R}_{w} \geq \dim_{k} \mathcal{H}_{w} / \operatorname{\mathrm{Ker}} \mathscr{L}^{\zeta}_{w} = \dim_{k} \mathcal{Z}_{w} = |\mathcal{I}^{\mathrm{T}}_{w}|, \end{align*}$$
where the last equality comes from Theorem 1.5. So we have 
 $\operatorname {\mathrm {Ker}} \mathscr {L}^{\zeta }_{w}=\mathscr {R}_{w}$
. By [Reference Chang9, Thm. 2.2.1], the last assertion follows.
$\operatorname {\mathrm {Ker}} \mathscr {L}^{\zeta }_{w}=\mathscr {R}_{w}$
. By [Reference Chang9, Thm. 2.2.1], the last assertion follows.
Remark 5.4. According to [Reference Chang9, Thm. 2.2.1], all 
 $\overline {k}$
-linear relations among MZV’s are decent to k-linear relations, and hence, (5.3) accounts for all
$\overline {k}$
-linear relations among MZV’s are decent to k-linear relations, and hence, (5.3) accounts for all 
 $\overline {k}$
-linear relations among MZV’s.
$\overline {k}$
-linear relations among MZV’s.
A Proof of Theorem 3.6
The aim of this appendix is to give a detailed proof of Theorem 3.6.
A.1 Inequalities of depth
Proposition A.1. Let 
 $\bullet \in \left \{\operatorname {\mathrm {Li}},\zeta \right \}$
 and
$\bullet \in \left \{\operatorname {\mathrm {Li}},\zeta \right \}$
 and 
 $\mathfrak {s}, \mathfrak {n} \in \mathcal {I}$
 be indices. Then for each
$\mathfrak {s}, \mathfrak {n} \in \mathcal {I}$
 be indices. Then for each 
 $\mathfrak {u} \in \operatorname {\mathrm {Supp}}(\mathfrak {s} *^{\bullet } \mathfrak {n})$
, we have
$\mathfrak {u} \in \operatorname {\mathrm {Supp}}(\mathfrak {s} *^{\bullet } \mathfrak {n})$
, we have 
 $$ \begin{align*} \max\{ \operatorname{\mathrm{dep}}(\mathfrak{s}), \operatorname{\mathrm{dep}}(\mathfrak{n}) \} \leq \operatorname{\mathrm{dep}}(\mathfrak{u}) \leq \operatorname{\mathrm{dep}}(\mathfrak{s}) + \operatorname{\mathrm{dep}}(\mathfrak{n}). \end{align*} $$
$$ \begin{align*} \max\{ \operatorname{\mathrm{dep}}(\mathfrak{s}), \operatorname{\mathrm{dep}}(\mathfrak{n}) \} \leq \operatorname{\mathrm{dep}}(\mathfrak{u}) \leq \operatorname{\mathrm{dep}}(\mathfrak{s}) + \operatorname{\mathrm{dep}}(\mathfrak{n}). \end{align*} $$
Proof. Put 
 $r := \operatorname {\mathrm {dep}}(\mathfrak {s})$
 and
$r := \operatorname {\mathrm {dep}}(\mathfrak {s})$
 and 
 $\ell := \operatorname {\mathrm {dep}}(\mathfrak {n})$
. We prove the inequalities by induction on
$\ell := \operatorname {\mathrm {dep}}(\mathfrak {n})$
. We prove the inequalities by induction on 
 $r + \ell $
. Note that in the case of
$r + \ell $
. Note that in the case of 
 $r = 0$
 or
$r = 0$
 or 
 $\ell = 0$
 (namely,
$\ell = 0$
 (namely, 
 $\mathfrak {s}=\emptyset $
 or
$\mathfrak {s}=\emptyset $
 or 
 $\mathfrak {n}=\emptyset $
), the result follows from the definition of
$\mathfrak {n}=\emptyset $
), the result follows from the definition of 
 $*^{\bullet }$
.
$*^{\bullet }$
.
 Suppose that 
 $r\geq 1$
 and
$r\geq 1$
 and 
 $\ell \geq 1$
. Since the binary operation
$\ell \geq 1$
. Since the binary operation 
 $*^{\bullet }$
 is commutative, without loss of generality we may assume that
$*^{\bullet }$
 is commutative, without loss of generality we may assume that 
 $r \geq \ell \geq 1$
. We first consider the case that
$r \geq \ell \geq 1$
. We first consider the case that 
 $r> \ell $
. By the induction hypothesis, we have:
$r> \ell $
. By the induction hypothesis, we have: 
- 
• when  $\mathfrak {u} \in \operatorname {\mathrm {Supp}}([s_{1}, \mathfrak {s}_{-} *^{\bullet } \mathfrak {n}])$
, then $\mathfrak {u} \in \operatorname {\mathrm {Supp}}([s_{1}, \mathfrak {s}_{-} *^{\bullet } \mathfrak {n}])$
, then $1 + (r - 1) \leq \operatorname {\mathrm {dep}}(\mathfrak {u}) \leq 1 + (r - 1) + \ell $
; $1 + (r - 1) \leq \operatorname {\mathrm {dep}}(\mathfrak {u}) \leq 1 + (r - 1) + \ell $
;
- 
• when  $\mathfrak {u} \in \operatorname {\mathrm {Supp}}([n_{1}, \mathfrak {s} *^{\bullet } \mathfrak {n}_{-}])$
, then $\mathfrak {u} \in \operatorname {\mathrm {Supp}}([n_{1}, \mathfrak {s} *^{\bullet } \mathfrak {n}_{-}])$
, then $1 + r \leq \operatorname {\mathrm {dep}}(\mathfrak {u}) \leq 1 + r + (\ell - 1)$
; $1 + r \leq \operatorname {\mathrm {dep}}(\mathfrak {u}) \leq 1 + r + (\ell - 1)$
;
- 
• when  $\mathfrak {u} \in \operatorname {\mathrm {Supp}}([s_{1} + n_{1}, \mathfrak {s}_{-} *^{\bullet } \mathfrak {n}_{-}])$
, then $\mathfrak {u} \in \operatorname {\mathrm {Supp}}([s_{1} + n_{1}, \mathfrak {s}_{-} *^{\bullet } \mathfrak {n}_{-}])$
, then $1 + (r - 1) \leq \operatorname {\mathrm {dep}}(\mathfrak {u}) \leq 1 + (r - 1) + (\ell - 1)$
; $1 + (r - 1) \leq \operatorname {\mathrm {dep}}(\mathfrak {u}) \leq 1 + (r - 1) + (\ell - 1)$
;
- 
• when  $\mathfrak {u} \in \operatorname {\mathrm {Supp}}(D^{\zeta }_{\mathfrak {s}, \mathfrak {n}})$
, then there exist j, $\mathfrak {u} \in \operatorname {\mathrm {Supp}}(D^{\zeta }_{\mathfrak {s}, \mathfrak {n}})$
, then there exist j, $\mathfrak {u}'$
 and $\mathfrak {u}'$
 and $\mathfrak {u}"$
 such that $\mathfrak {u}"$
 such that $1 \leq j < s_{1} + n_{1}$
, $1 \leq j < s_{1} + n_{1}$
, $\mathfrak {u}" \in \operatorname {\mathrm {Supp}}(\mathfrak {s}_{-} *^{\zeta } \mathfrak {n}_{-})$
 and $\mathfrak {u}" \in \operatorname {\mathrm {Supp}}(\mathfrak {s}_{-} *^{\zeta } \mathfrak {n}_{-})$
 and $\mathfrak {u}' \in \operatorname {\mathrm {Supp}}((j) *^{\zeta } \mathfrak {u}")$
 with $\mathfrak {u}' \in \operatorname {\mathrm {Supp}}((j) *^{\zeta } \mathfrak {u}")$
 with $\mathfrak {u} = (s_{1} + n_{1} - j, \mathfrak {u}')$
. It follows that $\mathfrak {u} = (s_{1} + n_{1} - j, \mathfrak {u}')$
. It follows that $r - 1 \leq \operatorname {\mathrm {dep}}(\mathfrak {u}") \leq (r - 1) + (\ell - 1)$
, and hence, $r - 1 \leq \operatorname {\mathrm {dep}}(\mathfrak {u}") \leq (r - 1) + (\ell - 1)$
, and hence, $r - 1 \leq \operatorname {\mathrm {dep}}(\mathfrak {u}') \leq 1 + (r - 1) + (\ell - 1)$
. $r - 1 \leq \operatorname {\mathrm {dep}}(\mathfrak {u}') \leq 1 + (r - 1) + (\ell - 1)$
.
In any case, we have 
 $r \leq \operatorname {\mathrm {dep}}(\mathfrak {u}) \leq r + \ell $
. In the case of
$r \leq \operatorname {\mathrm {dep}}(\mathfrak {u}) \leq r + \ell $
. In the case of 
 $r = \ell $
, we can verify that
$r = \ell $
, we can verify that 
 $r \leq \operatorname {\mathrm {dep}}(\mathfrak {u}) \leq 2 r$
 by a similar argument as above.
$r \leq \operatorname {\mathrm {dep}}(\mathfrak {u}) \leq 2 r$
 by a similar argument as above.
Corollary A.2. Let 
 $\mathfrak {s}, \mathfrak {n} \in \mathcal {I}$
 be indices.
$\mathfrak {s}, \mathfrak {n} \in \mathcal {I}$
 be indices. 
- 
(1) Suppose that both  $\mathfrak {s}$
 and $\mathfrak {s}$
 and $\mathfrak {n}$
 are nonempty indices. Let $\mathfrak {n}$
 are nonempty indices. Let $D^{\zeta }_{\mathfrak {s}, \mathfrak {n}}$
 be defined in (2.10). Then for each $D^{\zeta }_{\mathfrak {s}, \mathfrak {n}}$
 be defined in (2.10). Then for each $\mathfrak {u} \in \operatorname {\mathrm {Supp}}(D^{\zeta }_{\mathfrak {s}, \mathfrak {n}})$
, we have $\mathfrak {u} \in \operatorname {\mathrm {Supp}}(D^{\zeta }_{\mathfrak {s}, \mathfrak {n}})$
, we have $$ \begin{align*} \max\{ \operatorname{\mathrm{dep}}(\mathfrak{s}), \operatorname{\mathrm{dep}}(\mathfrak{n}) \} \leq \operatorname{\mathrm{dep}}(\mathfrak{u}) \leq \operatorname{\mathrm{dep}}(\mathfrak{s}) + \operatorname{\mathrm{dep}}(\mathfrak{n}). \end{align*} $$ $$ \begin{align*} \max\{ \operatorname{\mathrm{dep}}(\mathfrak{s}), \operatorname{\mathrm{dep}}(\mathfrak{n}) \} \leq \operatorname{\mathrm{dep}}(\mathfrak{u}) \leq \operatorname{\mathrm{dep}}(\mathfrak{s}) + \operatorname{\mathrm{dep}}(\mathfrak{n}). \end{align*} $$
- 
(2) For any integer  $m \geq 0$
, we let $m \geq 0$
, we let $\alpha ^{\bullet ,m}_{q}$
 be the m-th iteration of $\alpha ^{\bullet ,m}_{q}$
 be the m-th iteration of $\alpha ^{\bullet }_{q}$
 defined in (3.3). Then for each $\alpha ^{\bullet }_{q}$
 defined in (3.3). Then for each $\mathfrak {u} \in \operatorname {\mathrm {Supp}}(\alpha ^{\bullet , m}_{q}(\mathfrak {s}))$
, we have $\mathfrak {u} \in \operatorname {\mathrm {Supp}}(\alpha ^{\bullet , m}_{q}(\mathfrak {s}))$
, we have $$ \begin{align*} \operatorname{\mathrm{dep}}(\mathfrak{u}) \geq \left\{ \begin{array}{@{}ll} 1 + m & (\mathfrak{s} = \emptyset, \ m \geq 1) \\ \operatorname{\mathrm{dep}}(\mathfrak{s}) + m & ({otherwise}) \end{array} \right. \ \ {and} \ \ \operatorname{\mathrm{dep}}(\mathfrak{u}) \leq \operatorname{\mathrm{dep}}(\mathfrak{s}) + 2 m. \end{align*} $$ $$ \begin{align*} \operatorname{\mathrm{dep}}(\mathfrak{u}) \geq \left\{ \begin{array}{@{}ll} 1 + m & (\mathfrak{s} = \emptyset, \ m \geq 1) \\ \operatorname{\mathrm{dep}}(\mathfrak{s}) + m & ({otherwise}) \end{array} \right. \ \ {and} \ \ \operatorname{\mathrm{dep}}(\mathfrak{u}) \leq \operatorname{\mathrm{dep}}(\mathfrak{s}) + 2 m. \end{align*} $$
Proof. This is a direct consequence of Proposition A.1.
A.2 Binary relations
 Let 
 $\bullet \in \{ \operatorname {\mathrm {Li}}, \zeta \}$
. For each
$\bullet \in \{ \operatorname {\mathrm {Li}}, \zeta \}$
. For each 
 $d \in \mathbb {Z}$
 and
$d \in \mathbb {Z}$
 and 
 $R = (P, Q) \in \mathcal {H}^{\oplus 2}$
, we define
$R = (P, Q) \in \mathcal {H}^{\oplus 2}$
, we define 
 $$ \begin{align*} \mathscr{L}^{\bullet}(R) := \mathscr{L}^{\bullet}(P) + \mathscr{L}^{\bullet}(Q) \ \ \mathrm{and} \ \ \mathscr{L}^{\bullet}_{d}(R) := \mathscr{L}^{\bullet}_{d}(P) + \mathscr{L}^{\bullet}_{d + 1}(Q). \end{align*} $$
$$ \begin{align*} \mathscr{L}^{\bullet}(R) := \mathscr{L}^{\bullet}(P) + \mathscr{L}^{\bullet}(Q) \ \ \mathrm{and} \ \ \mathscr{L}^{\bullet}_{d}(R) := \mathscr{L}^{\bullet}_{d}(P) + \mathscr{L}^{\bullet}_{d + 1}(Q). \end{align*} $$
We set
 $$ \begin{align} \mathcal{P}^{\bullet} &:= \{ (P, Q)\in \mathcal{H}^{\oplus 2} \ | \ \mathscr{L}^{\bullet}_{d}(P) + \mathscr{L}^{\bullet}_{d + 1}(Q) = 0 \ \mathrm{for all} \ d \in \mathbb{Z} \} \end{align} $$
$$ \begin{align} \mathcal{P}^{\bullet} &:= \{ (P, Q)\in \mathcal{H}^{\oplus 2} \ | \ \mathscr{L}^{\bullet}_{d}(P) + \mathscr{L}^{\bullet}_{d + 1}(Q) = 0 \ \mathrm{for all} \ d \in \mathbb{Z} \} \end{align} $$
and
 $$ \begin{align} \mathcal{P}^{\bullet}_{w} := \mathcal{P}^{\bullet} \cap \mathcal{H}_{w}^{\oplus 2} \end{align} $$
$$ \begin{align} \mathcal{P}^{\bullet}_{w} := \mathcal{P}^{\bullet} \cap \mathcal{H}_{w}^{\oplus 2} \end{align} $$
for 
 $w \geq 0$
. Elements in
$w \geq 0$
. Elements in 
 $\mathcal {P}^{\bullet }$
 are called binary relations. We note that each binary relation
$\mathcal {P}^{\bullet }$
 are called binary relations. We note that each binary relation 
 $R = (P, Q) \in \mathcal {P}^{\bullet }$
 induces a k-linear relation
$R = (P, Q) \in \mathcal {P}^{\bullet }$
 induces a k-linear relation 
 $\mathscr {L}^{\bullet }(R) = \mathscr {L}^{\bullet }(P) + \mathscr {L}^{\bullet }(Q) = 0$
. Indeed, we have
$\mathscr {L}^{\bullet }(R) = \mathscr {L}^{\bullet }(P) + \mathscr {L}^{\bullet }(Q) = 0$
. Indeed, we have 
 $$ \begin{align*} \mathscr{L}^{\bullet}(P) + \mathscr{L}^{\bullet}(Q) = \sum_{d \in \mathbb{Z}} \mathscr{L}^{\bullet}_{d}(P) + \sum_{d \in \mathbb{Z}} \mathscr{L}^{\bullet}_{d + 1}(Q) = \sum_{d \in \mathbb{Z}} (\mathscr{L}^{\bullet}_{d}(P) + \mathscr{L}^{\bullet}_{d + 1}(Q)) = 0. \end{align*} $$
$$ \begin{align*} \mathscr{L}^{\bullet}(P) + \mathscr{L}^{\bullet}(Q) = \sum_{d \in \mathbb{Z}} \mathscr{L}^{\bullet}_{d}(P) + \sum_{d \in \mathbb{Z}} \mathscr{L}^{\bullet}_{d + 1}(Q) = \sum_{d \in \mathbb{Z}} (\mathscr{L}^{\bullet}_{d}(P) + \mathscr{L}^{\bullet}_{d + 1}(Q)) = 0. \end{align*} $$
The above ideas were introduced by Todd [Reference Todd30].
Example A.3. Thakur proved the identity [Reference Thakur33, Thm. 5]
 $$ \begin{align*} \mathscr{L}^{\zeta}_{d}(q) - L_{1} \mathscr{L}^{\zeta}_{d + 1}(1, q - 1) &= 0 \ \ \ (d \in \mathbb{Z}). \end{align*} $$
$$ \begin{align*} \mathscr{L}^{\zeta}_{d}(q) - L_{1} \mathscr{L}^{\zeta}_{d + 1}(1, q - 1) &= 0 \ \ \ (d \in \mathbb{Z}). \end{align*} $$
Note that by Remark 2.5 we can replace ‘
 $\zeta $
’ by ‘
$\zeta $
’ by ‘
 $\operatorname {\mathrm {Li}}$
’ in the above equation. It follows that for
$\operatorname {\mathrm {Li}}$
’ in the above equation. It follows that for 
 $\bullet \in \left \{\operatorname {\mathrm {Li}}, \zeta \right \}$
, we have a binary relation
$\bullet \in \left \{\operatorname {\mathrm {Li}}, \zeta \right \}$
, we have a binary relation 
 $$ \begin{align} R_{1} := ([q], \ - L_{1} [1, q - 1]) \in \mathcal{P}^{\bullet}_{q}; \end{align} $$
$$ \begin{align} R_{1} := ([q], \ - L_{1} [1, q - 1]) \in \mathcal{P}^{\bullet}_{q}; \end{align} $$
namely, for each 
 $d\in \mathbb {Z}$
, the following equation holds:
$d\in \mathbb {Z}$
, the following equation holds: 
 $$\begin{align*}\mathscr{L}^{\bullet}_{d}(q) - L_{1} \mathscr{L}^{\bullet}_{d + 1}(1, q - 1) = 0.\end{align*}$$
$$\begin{align*}\mathscr{L}^{\bullet}_{d}(q) - L_{1} \mathscr{L}^{\bullet}_{d + 1}(1, q - 1) = 0.\end{align*}$$
A.3 Maps between relations
 In what follows, the essential ideas we use are rooted in [Reference Todd30, Reference Ngo Dac26]. Let 
 $\mathfrak {s} = (s_{1}, \ldots , s_{r}) \in \mathcal {I}_{> 0}$
 be a nonempty index. We recall that
$\mathfrak {s} = (s_{1}, \ldots , s_{r}) \in \mathcal {I}_{> 0}$
 be a nonempty index. We recall that 
 $\mathfrak {s}_{+} := (s_{1}, \ldots , s_{r - 1})$
 and
$\mathfrak {s}_{+} := (s_{1}, \ldots , s_{r - 1})$
 and 
 $\mathfrak {s}_{-} := (s_{2}, \ldots , s_{r})$
, and the operator
$\mathfrak {s}_{-} := (s_{2}, \ldots , s_{r})$
, and the operator 
 $\boxplus : \mathcal {H}^{\oplus 2}\rightarrow \mathcal {H}$
 is defined in Definition 3.1, and the notations
$\boxplus : \mathcal {H}^{\oplus 2}\rightarrow \mathcal {H}$
 is defined in Definition 3.1, and the notations 
 $D_{\mathfrak {s},\mathfrak {n}}^{\mathrm {Li}}$
 in (2.8) and
$D_{\mathfrak {s},\mathfrak {n}}^{\mathrm {Li}}$
 in (2.8) and 
 $D^{\zeta }_{\mathfrak {s}, \mathfrak {n}}$
 in (2.10). For
$D^{\zeta }_{\mathfrak {s}, \mathfrak {n}}$
 in (2.10). For 
 $\bullet \in \left \{\operatorname {\mathrm {Li}},\zeta \right \}$
, we define the maps
$\bullet \in \left \{\operatorname {\mathrm {Li}},\zeta \right \}$
, we define the maps 
 $\mathscr {B}^{\bullet }_{\mathfrak {s}}, \mathscr {C}^{\bullet }_{\mathfrak {s}}:\mathcal {H}_{> 0}^{\oplus 2}\rightarrow \mathcal {H}_{> 0}^{\oplus 2} $
 as follows: For each
$\mathscr {B}^{\bullet }_{\mathfrak {s}}, \mathscr {C}^{\bullet }_{\mathfrak {s}}:\mathcal {H}_{> 0}^{\oplus 2}\rightarrow \mathcal {H}_{> 0}^{\oplus 2} $
 as follows: For each 
 $R = (P, Q) = (\sum _{\mathfrak {n} \in \mathcal {I}_{> 0}} a_{\mathfrak {n}} [\mathfrak {n}], \ \sum _{\mathfrak {n} \in \mathcal {I}_{> 0}} b_{\mathfrak {n}} [\mathfrak {n}]) \in \mathcal {H}_{> 0}^{\oplus 2}$
, we set
$R = (P, Q) = (\sum _{\mathfrak {n} \in \mathcal {I}_{> 0}} a_{\mathfrak {n}} [\mathfrak {n}], \ \sum _{\mathfrak {n} \in \mathcal {I}_{> 0}} b_{\mathfrak {n}} [\mathfrak {n}]) \in \mathcal {H}_{> 0}^{\oplus 2}$
, we set 
 $$ \begin{align*} \mathscr{B}^{\bullet}_{\mathfrak{s}}(R) &:= \left( [\mathfrak{s}, P] + [\mathfrak{s}, Q] + (\mathfrak{s} \boxplus Q) + [\mathfrak{s}_{+}, D^{\bullet}_{s_{r}, Q}], \ 0 \right), \\ \mathscr{C}^{\bullet}_{\mathfrak{s}}(R) &:= \sum_{\mathfrak{n} = (n_{1}, \mathfrak{n}_{-}) \in \mathcal{I}_{> 0}} \left( a_{\mathfrak{n}} [n_{1} + s_{1}, \mathfrak{n}_{-} *^{\bullet} \mathfrak{s}_{-}] + a_{\mathfrak{n}} [n_{1}, \mathfrak{n}_{-} *^{\bullet} \mathfrak{s}] + a_{\mathfrak{n}} D^{\bullet}_{\mathfrak{n}, \mathfrak{s}}, \ b_{\mathfrak{n}} [n_{1}, \mathfrak{n}_{-} *^{\bullet} \mathfrak{s}] \right), \end{align*} $$
$$ \begin{align*} \mathscr{B}^{\bullet}_{\mathfrak{s}}(R) &:= \left( [\mathfrak{s}, P] + [\mathfrak{s}, Q] + (\mathfrak{s} \boxplus Q) + [\mathfrak{s}_{+}, D^{\bullet}_{s_{r}, Q}], \ 0 \right), \\ \mathscr{C}^{\bullet}_{\mathfrak{s}}(R) &:= \sum_{\mathfrak{n} = (n_{1}, \mathfrak{n}_{-}) \in \mathcal{I}_{> 0}} \left( a_{\mathfrak{n}} [n_{1} + s_{1}, \mathfrak{n}_{-} *^{\bullet} \mathfrak{s}_{-}] + a_{\mathfrak{n}} [n_{1}, \mathfrak{n}_{-} *^{\bullet} \mathfrak{s}] + a_{\mathfrak{n}} D^{\bullet}_{\mathfrak{n}, \mathfrak{s}}, \ b_{\mathfrak{n}} [n_{1}, \mathfrak{n}_{-} *^{\bullet} \mathfrak{s}] \right), \end{align*} $$
where
 $$\begin{align*}D^{\bullet}_{s, Q} := \sum_{\mathfrak{n} \in \mathcal{I}_{> 0}} b_{\mathfrak{n}} D^{\bullet}_{s, \mathfrak{n}}.\end{align*}$$
$$\begin{align*}D^{\bullet}_{s, Q} := \sum_{\mathfrak{n} \in \mathcal{I}_{> 0}} b_{\mathfrak{n}} D^{\bullet}_{s, \mathfrak{n}}.\end{align*}$$
For any integer 
 $m\geq 0$
, we further define the map
$m\geq 0$
, we further define the map 
 $\mathscr {BC}^{\bullet , m}_{q}: \mathcal {H}_{> 0}^{\oplus 2}\rightarrow \mathcal {H}_{> 0}^{\oplus 2}$
 given by
$\mathscr {BC}^{\bullet , m}_{q}: \mathcal {H}_{> 0}^{\oplus 2}\rightarrow \mathcal {H}_{> 0}^{\oplus 2}$
 given by 
 $$\begin{align*}\mathscr{BC}^{\bullet, m}_{q}(R) := \left( [q^{\{m\}}, P], \ L_{1}^{m} \alpha^{\bullet, m}_{q}(Q) \right). \end{align*}$$
$$\begin{align*}\mathscr{BC}^{\bullet, m}_{q}(R) := \left( [q^{\{m\}}, P], \ L_{1}^{m} \alpha^{\bullet, m}_{q}(Q) \right). \end{align*}$$
It is clear that these maps are k-linear endomorphisms on 
 $\mathcal {H}_{> 0}^{\oplus 2}$
.
$\mathcal {H}_{> 0}^{\oplus 2}$
.
Proposition A.4. Let 
 $\bullet \in \left \{\operatorname {\mathrm {Li}},\zeta \right \}$
. For each
$\bullet \in \left \{\operatorname {\mathrm {Li}},\zeta \right \}$
. For each 
 $\mathfrak {s} \in \mathcal {I}_{> 0}$
, and integers
$\mathfrak {s} \in \mathcal {I}_{> 0}$
, and integers 
 $m, w$
 satisfying
$m, w$
 satisfying 
 $m \geq 0, w> 0$
, the maps
$m \geq 0, w> 0$
, the maps 
 $\mathscr {B}^{\bullet }_{\mathfrak {s}}$
,
$\mathscr {B}^{\bullet }_{\mathfrak {s}}$
, 
 $\mathscr {C}^{\bullet }_{\mathfrak {s}}$
 and
$\mathscr {C}^{\bullet }_{\mathfrak {s}}$
 and 
 $\mathscr {BC}^{\bullet , m}_{q}$
 satisfy
$\mathscr {BC}^{\bullet , m}_{q}$
 satisfy 
 $$ \begin{align*} \mathscr{B}^{\bullet}_{\mathfrak{s}}(\mathcal{P}^{\bullet}_{w}) \subset \mathcal{P}^{\bullet}_{w + \operatorname{\mathrm{wt}}(\mathfrak{s})}, \ \ \ \mathscr{C}^{\bullet}_{\mathfrak{s}}(\mathcal{P}^{\bullet}_{w}) \subset \mathcal{P}^{\bullet}_{w + \operatorname{\mathrm{wt}}(\mathfrak{s})} \ \ \ \mathrm{and} \ \ \ \mathscr{BC}^{\bullet, m}_{q}(\mathcal{P}^{\bullet}_{w}) \subset \mathcal{P}^{\bullet}_{w + m q}, \end{align*} $$
$$ \begin{align*} \mathscr{B}^{\bullet}_{\mathfrak{s}}(\mathcal{P}^{\bullet}_{w}) \subset \mathcal{P}^{\bullet}_{w + \operatorname{\mathrm{wt}}(\mathfrak{s})}, \ \ \ \mathscr{C}^{\bullet}_{\mathfrak{s}}(\mathcal{P}^{\bullet}_{w}) \subset \mathcal{P}^{\bullet}_{w + \operatorname{\mathrm{wt}}(\mathfrak{s})} \ \ \ \mathrm{and} \ \ \ \mathscr{BC}^{\bullet, m}_{q}(\mathcal{P}^{\bullet}_{w}) \subset \mathcal{P}^{\bullet}_{w + m q}, \end{align*} $$
where 
 $\mathcal {P}^{\bullet }_w$
 is defined in (A.2).
$\mathcal {P}^{\bullet }_w$
 is defined in (A.2).
Proof. When 
 $R \in \mathcal {P}^{\bullet }_{w}$
, it is clear that
$R \in \mathcal {P}^{\bullet }_{w}$
, it is clear that 
 $$ \begin{align*} \mathscr{B}^{\bullet}_{\mathfrak{s}}(R) \in \mathcal{H}_{w + \operatorname{\mathrm{wt}}(\mathfrak{s})}^{\oplus 2}, \ \ \mathscr{C}^{\bullet}_{\mathfrak{s}}(R) \in \mathcal{H}_{w + \operatorname{\mathrm{wt}}(\mathfrak{s})}^{\oplus 2} \ \ \mathrm{and} \ \ \mathscr{BC}^{\bullet}_{\mathfrak{s}}(R) \in \mathcal{H}_{w + \operatorname{\mathrm{wt}}(\mathfrak{s})}^{\oplus 2}. \end{align*} $$
$$ \begin{align*} \mathscr{B}^{\bullet}_{\mathfrak{s}}(R) \in \mathcal{H}_{w + \operatorname{\mathrm{wt}}(\mathfrak{s})}^{\oplus 2}, \ \ \mathscr{C}^{\bullet}_{\mathfrak{s}}(R) \in \mathcal{H}_{w + \operatorname{\mathrm{wt}}(\mathfrak{s})}^{\oplus 2} \ \ \mathrm{and} \ \ \mathscr{BC}^{\bullet}_{\mathfrak{s}}(R) \in \mathcal{H}_{w + \operatorname{\mathrm{wt}}(\mathfrak{s})}^{\oplus 2}. \end{align*} $$
Thus, it suffices to show that 
 $\mathscr {B}^{\bullet }_{\mathfrak {s}}(R), \mathscr {C}^{\bullet }_{\mathfrak {s}}(R), \mathscr {BC}^{\bullet , m}_{q}(R) \in \mathcal {P}^{\bullet }$
.
$\mathscr {B}^{\bullet }_{\mathfrak {s}}(R), \mathscr {C}^{\bullet }_{\mathfrak {s}}(R), \mathscr {BC}^{\bullet , m}_{q}(R) \in \mathcal {P}^{\bullet }$
.
 For each 
 $R = (\sum _{\mathfrak {n} \in \mathcal {I}_{w}} a_{\mathfrak {n}} [\mathfrak {n}], \ \sum _{\mathfrak {n} \in \mathcal {I}_{w}} b_{\mathfrak {n}} [\mathfrak {n}]) \in \mathcal {P}^{\bullet }_{w}$
, the corresponding equalities
$R = (\sum _{\mathfrak {n} \in \mathcal {I}_{w}} a_{\mathfrak {n}} [\mathfrak {n}], \ \sum _{\mathfrak {n} \in \mathcal {I}_{w}} b_{\mathfrak {n}} [\mathfrak {n}]) \in \mathcal {P}^{\bullet }_{w}$
, the corresponding equalities 
 $$ \begin{align*} \sum_{\mathfrak{n} \in \mathcal{I}_{w}} a_{\mathfrak{n}} \mathscr{L}^{\bullet}_{i}(\mathfrak{n}) + \sum_{\mathfrak{n} \in \mathcal{I}_{w}} b_{\mathfrak{n}} \mathscr{L}^{\bullet}_{i + 1}(\mathfrak{n}) = 0 \ \ \ (i \in \mathbb{Z}) \end{align*} $$
$$ \begin{align*} \sum_{\mathfrak{n} \in \mathcal{I}_{w}} a_{\mathfrak{n}} \mathscr{L}^{\bullet}_{i}(\mathfrak{n}) + \sum_{\mathfrak{n} \in \mathcal{I}_{w}} b_{\mathfrak{n}} \mathscr{L}^{\bullet}_{i + 1}(\mathfrak{n}) = 0 \ \ \ (i \in \mathbb{Z}) \end{align*} $$
hold. Thus, for each 
 $s \geq 1$
 and
$s \geq 1$
 and 
 $d \in \mathbb {Z}$
, we have
$d \in \mathbb {Z}$
, we have 
 $$ \begin{align*} 0 &= \mathscr{L}^{\bullet}_{d}(s) \sum_{i < d} \left( \sum_{\mathfrak{n} \in \mathcal{I}_{w}} a_{\mathfrak{n}} \mathscr{L}^{\bullet}_{i}(\mathfrak{n}) + \sum_{\mathfrak{n} \in \mathcal{I}_{w}} b_{\mathfrak{n}} \mathscr{L}^{\bullet}_{i + 1}(\mathfrak{n}) \right) \\ &= \sum_{\mathfrak{n} \in \mathcal{I}_{w}} a_{\mathfrak{n}} \mathscr{L}^{\bullet}_{d}(s) \mathscr{L}^{\bullet}_{< d}(\mathfrak{n}) + \sum_{\mathfrak{n} \in \mathcal{I}_{w}} b_{\mathfrak{n}} \mathscr{L}^{\bullet}_{d}(s) \mathscr{L}^{\bullet}_{< d}(\mathfrak{n}) + \sum_{\mathfrak{n} \in \mathcal{I}_{w}} b_{\mathfrak{n}} \mathscr{L}^{\bullet}_{d}(s) \mathscr{L}^{\bullet}_{d}(\mathfrak{n}) \\ &= \sum_{\mathfrak{n} \in \mathcal{I}_{w}} a_{\mathfrak{n}} \mathscr{L}^{\bullet}_{d}(s, \mathfrak{n}) + \sum_{\mathfrak{n} \in \mathcal{I}_{w}} b_{\mathfrak{n}} \mathscr{L}^{\bullet}_{d}(s, \mathfrak{n}) + \sum_{\mathfrak{n} = (n_{1}, \mathfrak{n}_{-}) \in \mathcal{I}_{w}} b_{\mathfrak{n}} \mathscr{L}^{\bullet}_{d}(s + n_{1}, \mathfrak{n}_{-}) + \sum_{\mathfrak{n} \in \mathcal{I}_{w}} b_{\mathfrak{n}} \mathscr{L}^{\bullet}_{d}(D^{\bullet}_{s, \mathfrak{n}}) \\ &= \mathscr{L}^{\bullet}_{d}(\mathscr{B}^{\bullet}_{s}(R)), \end{align*} $$
$$ \begin{align*} 0 &= \mathscr{L}^{\bullet}_{d}(s) \sum_{i < d} \left( \sum_{\mathfrak{n} \in \mathcal{I}_{w}} a_{\mathfrak{n}} \mathscr{L}^{\bullet}_{i}(\mathfrak{n}) + \sum_{\mathfrak{n} \in \mathcal{I}_{w}} b_{\mathfrak{n}} \mathscr{L}^{\bullet}_{i + 1}(\mathfrak{n}) \right) \\ &= \sum_{\mathfrak{n} \in \mathcal{I}_{w}} a_{\mathfrak{n}} \mathscr{L}^{\bullet}_{d}(s) \mathscr{L}^{\bullet}_{< d}(\mathfrak{n}) + \sum_{\mathfrak{n} \in \mathcal{I}_{w}} b_{\mathfrak{n}} \mathscr{L}^{\bullet}_{d}(s) \mathscr{L}^{\bullet}_{< d}(\mathfrak{n}) + \sum_{\mathfrak{n} \in \mathcal{I}_{w}} b_{\mathfrak{n}} \mathscr{L}^{\bullet}_{d}(s) \mathscr{L}^{\bullet}_{d}(\mathfrak{n}) \\ &= \sum_{\mathfrak{n} \in \mathcal{I}_{w}} a_{\mathfrak{n}} \mathscr{L}^{\bullet}_{d}(s, \mathfrak{n}) + \sum_{\mathfrak{n} \in \mathcal{I}_{w}} b_{\mathfrak{n}} \mathscr{L}^{\bullet}_{d}(s, \mathfrak{n}) + \sum_{\mathfrak{n} = (n_{1}, \mathfrak{n}_{-}) \in \mathcal{I}_{w}} b_{\mathfrak{n}} \mathscr{L}^{\bullet}_{d}(s + n_{1}, \mathfrak{n}_{-}) + \sum_{\mathfrak{n} \in \mathcal{I}_{w}} b_{\mathfrak{n}} \mathscr{L}^{\bullet}_{d}(D^{\bullet}_{s, \mathfrak{n}}) \\ &= \mathscr{L}^{\bullet}_{d}(\mathscr{B}^{\bullet}_{s}(R)), \end{align*} $$
where the third equality comes from Proposition 2.7. This means that 
 $\mathscr {B}^{\bullet }_{s}(R) \in \mathcal {P}^{\bullet }$
. Note that for each
$\mathscr {B}^{\bullet }_{s}(R) \in \mathcal {P}^{\bullet }$
. Note that for each 
 $\mathfrak {s} = (s_{1}, \ldots , s_{r}) \in \mathcal {I}_{> 0}$
, we have
$\mathfrak {s} = (s_{1}, \ldots , s_{r}) \in \mathcal {I}_{> 0}$
, we have 
 $\mathscr {B}^{\bullet }_{\mathfrak {s}}(R) \in \mathcal {P}^{\bullet }$
 since from the definition of
$\mathscr {B}^{\bullet }_{\mathfrak {s}}(R) \in \mathcal {P}^{\bullet }$
 since from the definition of 
 $\mathscr {B}^{\bullet }_{\mathfrak {s}}$
 we have
$\mathscr {B}^{\bullet }_{\mathfrak {s}}$
 we have 
 $$ \begin{align*} \mathscr{B}^{\bullet}_{\mathfrak{s}} = \mathscr{B}^{\bullet}_{s_{1}} \circ \cdots \circ \mathscr{B}^{\bullet}_{s_{r}}. \end{align*} $$
$$ \begin{align*} \mathscr{B}^{\bullet}_{\mathfrak{s}} = \mathscr{B}^{\bullet}_{s_{1}} \circ \cdots \circ \mathscr{B}^{\bullet}_{s_{r}}. \end{align*} $$
Similarly, we have
 $$ \begin{align*} 0 &= \left( \sum_{\mathfrak{n} \in \mathcal{I}_{w}} a_{\mathfrak{n}} \mathscr{L}^{\bullet}_{d}(\mathfrak{n}) + \sum_{\mathfrak{n} \in \mathcal{I}_{w}} b_{\mathfrak{n}} \mathscr{L}^{\bullet}_{d + 1}(\mathfrak{n}) \right) \mathscr{L}^{\bullet}_{< d + 1}(\mathfrak{s}) \\ &= \sum_{\mathfrak{n} \in \mathcal{I}_{w}} a_{\mathfrak{n}} \mathscr{L}^{\bullet}_{d}(\mathfrak{n}) \mathscr{L}^{\bullet}_{d}(\mathfrak{s}) + \sum_{\mathfrak{n} = (n_{1}, \mathfrak{n}_{-}) \in \mathcal{I}_{w}} a_{\mathfrak{n}} \mathscr{L}^{\bullet}_{d}(n_{1}) \mathscr{L}^{\bullet}_{< d}(\mathfrak{n}_{-}) \mathscr{L}^{\bullet}_{< d}(\mathfrak{s}) \\ & \ \ \ + \sum_{\mathfrak{n} = (n_{1}, \mathfrak{n}_{-}) \in \mathcal{I}_{w}} b_{\mathfrak{n}} \mathscr{L}^{\bullet}_{d + 1}(n_{1}) \mathscr{L}^{\bullet}_{< d + 1}(\mathfrak{n}_{-}) \mathscr{L}^{\bullet}_{< d + 1}(\mathfrak{s}) \\ & = \sum_{\mathfrak{n} = (n_{1}, \mathfrak{n}_{-}) \in \mathcal{I}_{w}} a_{\mathfrak{n}} \left( \mathscr{L}^{\bullet}_{d}([n_{1} + s_{1}, \mathfrak{n}_{-} *^{\bullet} \mathfrak{s}_{-}]) + \mathscr{L}^{\bullet}_{d}(D^{\bullet}_{\mathfrak{n}, \mathfrak{s}}) \right) + \sum_{\mathfrak{n} = (n_{1}, \mathfrak{n}_{-}) \in \mathcal{I}_{w}} a_{\mathfrak{n}} \mathscr{L}^{\bullet}_{d}([n_{1}, \mathfrak{n}_{-} *^{\bullet} \mathfrak{s}]) \\ & \ \ \ + \sum_{\mathfrak{n} = (n_{1}, \mathfrak{n}_{-}) \in \mathcal{I}_{w}} b_{\mathfrak{n}} \mathscr{L}^{\bullet}_{d + 1}([n_{1}, \mathfrak{n}_{-} *^{\bullet} \mathfrak{s}]) \\ & = \mathscr{L}^{\bullet}_{d}(\mathscr{C}^{\bullet}_{\mathfrak{s}}(R)), \end{align*} $$
$$ \begin{align*} 0 &= \left( \sum_{\mathfrak{n} \in \mathcal{I}_{w}} a_{\mathfrak{n}} \mathscr{L}^{\bullet}_{d}(\mathfrak{n}) + \sum_{\mathfrak{n} \in \mathcal{I}_{w}} b_{\mathfrak{n}} \mathscr{L}^{\bullet}_{d + 1}(\mathfrak{n}) \right) \mathscr{L}^{\bullet}_{< d + 1}(\mathfrak{s}) \\ &= \sum_{\mathfrak{n} \in \mathcal{I}_{w}} a_{\mathfrak{n}} \mathscr{L}^{\bullet}_{d}(\mathfrak{n}) \mathscr{L}^{\bullet}_{d}(\mathfrak{s}) + \sum_{\mathfrak{n} = (n_{1}, \mathfrak{n}_{-}) \in \mathcal{I}_{w}} a_{\mathfrak{n}} \mathscr{L}^{\bullet}_{d}(n_{1}) \mathscr{L}^{\bullet}_{< d}(\mathfrak{n}_{-}) \mathscr{L}^{\bullet}_{< d}(\mathfrak{s}) \\ & \ \ \ + \sum_{\mathfrak{n} = (n_{1}, \mathfrak{n}_{-}) \in \mathcal{I}_{w}} b_{\mathfrak{n}} \mathscr{L}^{\bullet}_{d + 1}(n_{1}) \mathscr{L}^{\bullet}_{< d + 1}(\mathfrak{n}_{-}) \mathscr{L}^{\bullet}_{< d + 1}(\mathfrak{s}) \\ & = \sum_{\mathfrak{n} = (n_{1}, \mathfrak{n}_{-}) \in \mathcal{I}_{w}} a_{\mathfrak{n}} \left( \mathscr{L}^{\bullet}_{d}([n_{1} + s_{1}, \mathfrak{n}_{-} *^{\bullet} \mathfrak{s}_{-}]) + \mathscr{L}^{\bullet}_{d}(D^{\bullet}_{\mathfrak{n}, \mathfrak{s}}) \right) + \sum_{\mathfrak{n} = (n_{1}, \mathfrak{n}_{-}) \in \mathcal{I}_{w}} a_{\mathfrak{n}} \mathscr{L}^{\bullet}_{d}([n_{1}, \mathfrak{n}_{-} *^{\bullet} \mathfrak{s}]) \\ & \ \ \ + \sum_{\mathfrak{n} = (n_{1}, \mathfrak{n}_{-}) \in \mathcal{I}_{w}} b_{\mathfrak{n}} \mathscr{L}^{\bullet}_{d + 1}([n_{1}, \mathfrak{n}_{-} *^{\bullet} \mathfrak{s}]) \\ & = \mathscr{L}^{\bullet}_{d}(\mathscr{C}^{\bullet}_{\mathfrak{s}}(R)), \end{align*} $$
where the third equality comes from Proposition 2.7. Thus, we have 
 $\mathscr {C}^{\bullet }_{\mathfrak {s}}(R) \in \mathcal {P}^{\bullet }$
.
$\mathscr {C}^{\bullet }_{\mathfrak {s}}(R) \in \mathcal {P}^{\bullet }$
.
Finally, we have
 $$ \begin{align*} \mathcal{P}^{\bullet} &\ni \mathscr{B}^{\bullet}_{q}(R) - \sum_{\mathfrak{n} \in \mathcal{I}_{w}} b_{\mathfrak{n}} \mathscr{C}^{\bullet}_{\mathfrak{n}}(R_{1}) \\ &= \sum_{\mathfrak{n} = (n_{1}, \mathfrak{n}_{-}) \in \mathcal{I}_{w}} \left( a_{\mathfrak{n}} [q, \mathfrak{n}] + b_{\mathfrak{n}} [q, \mathfrak{n}] + b_{\mathfrak{n}} [q + n_{1}, \mathfrak{n}_{-}] + b_{\mathfrak{n}} D^{\bullet}_{q, \mathfrak{n}}, \ 0 \right) \\ & \ \ \ \ \ - \sum_{\mathfrak{n} = (n_{1}, \mathfrak{n}_{-}) \in \mathcal{I}_{w}} b_{\mathfrak{n}} \left( \left( [q + n_{1}, \mathfrak{n}_{-}] + [q, \mathfrak{n}] + D^{\bullet}_{q, \mathfrak{n}} \right), \ - L_{1} [1, (q - 1) *^{\bullet} \mathfrak{n}] \right) \\ &= \sum_{\mathfrak{n} \in \mathcal{I}_{w}} \left( a_{\mathfrak{n}} [q, \mathfrak{n}], \ b_{\mathfrak{n}} L_{1} \alpha^{\bullet}_{q}(\mathfrak{n}) \right) \\ &= \mathscr{BC}^{\bullet}_{q}(R), \end{align*} $$
$$ \begin{align*} \mathcal{P}^{\bullet} &\ni \mathscr{B}^{\bullet}_{q}(R) - \sum_{\mathfrak{n} \in \mathcal{I}_{w}} b_{\mathfrak{n}} \mathscr{C}^{\bullet}_{\mathfrak{n}}(R_{1}) \\ &= \sum_{\mathfrak{n} = (n_{1}, \mathfrak{n}_{-}) \in \mathcal{I}_{w}} \left( a_{\mathfrak{n}} [q, \mathfrak{n}] + b_{\mathfrak{n}} [q, \mathfrak{n}] + b_{\mathfrak{n}} [q + n_{1}, \mathfrak{n}_{-}] + b_{\mathfrak{n}} D^{\bullet}_{q, \mathfrak{n}}, \ 0 \right) \\ & \ \ \ \ \ - \sum_{\mathfrak{n} = (n_{1}, \mathfrak{n}_{-}) \in \mathcal{I}_{w}} b_{\mathfrak{n}} \left( \left( [q + n_{1}, \mathfrak{n}_{-}] + [q, \mathfrak{n}] + D^{\bullet}_{q, \mathfrak{n}} \right), \ - L_{1} [1, (q - 1) *^{\bullet} \mathfrak{n}] \right) \\ &= \sum_{\mathfrak{n} \in \mathcal{I}_{w}} \left( a_{\mathfrak{n}} [q, \mathfrak{n}], \ b_{\mathfrak{n}} L_{1} \alpha^{\bullet}_{q}(\mathfrak{n}) \right) \\ &= \mathscr{BC}^{\bullet}_{q}(R), \end{align*} $$
where the second equality comes from the definition of 
 $\alpha ^{\bullet }_{q}$
 given in (3.3). Since
$\alpha ^{\bullet }_{q}$
 given in (3.3). Since 
 $$ \begin{align*} \mathscr{BC}^{\bullet, m}_{q} = \mathscr{BC}^{\bullet}_{q} \circ \cdots \circ \mathscr{BC}^{\bullet}_{q} \ \ (m\mathrm{th\ iterate\ of}\ \mathscr{BC}^{\bullet}_{q}), \end{align*} $$
$$ \begin{align*} \mathscr{BC}^{\bullet, m}_{q} = \mathscr{BC}^{\bullet}_{q} \circ \cdots \circ \mathscr{BC}^{\bullet}_{q} \ \ (m\mathrm{th\ iterate\ of}\ \mathscr{BC}^{\bullet}_{q}), \end{align*} $$
it shows that 
 $\mathscr {BC}^{\bullet , m}_{q}(R) \in \mathcal {P}^{\bullet }$
.
$\mathscr {BC}^{\bullet , m}_{q}(R) \in \mathcal {P}^{\bullet }$
.
 Let 
 $\mathfrak {s} \in \mathcal {I}$
. We write
$\mathfrak {s} \in \mathcal {I}$
. We write 
 $\mathfrak {s} = (s_{1}, \ldots ) = (\mathfrak {s}^{\mathrm {T}}, q^{\{ m \}}, \mathfrak {s}')$
 with
$\mathfrak {s} = (s_{1}, \ldots ) = (\mathfrak {s}^{\mathrm {T}}, q^{\{ m \}}, \mathfrak {s}')$
 with 
 $\mathfrak {s}^{\mathrm {T}} \in \mathcal {I}^{\mathrm {T}}$
,
$\mathfrak {s}^{\mathrm {T}} \in \mathcal {I}^{\mathrm {T}}$
, 
 $m \geq 0$
 and
$m \geq 0$
 and 
 $\mathfrak {s}' = (s^\prime _{1}, \ldots )$
 with
$\mathfrak {s}' = (s^\prime _{1}, \ldots )$
 with 
 $s^\prime _{1}> q$
 or
$s^\prime _{1}> q$
 or 
 $\mathfrak {s}' = \emptyset $
, and set
$\mathfrak {s}' = \emptyset $
, and set 
 $\operatorname {\mathrm {Init}}(\mathfrak {s}) := (\mathfrak {s}^{\mathrm {T}}, q^{\{ m \}})$
 and
$\operatorname {\mathrm {Init}}(\mathfrak {s}) := (\mathfrak {s}^{\mathrm {T}}, q^{\{ m \}})$
 and 
 $\ell _{1} := \operatorname {\mathrm {dep}}(\operatorname {\mathrm {Init}}(\mathfrak {s}))$
. When
$\ell _{1} := \operatorname {\mathrm {dep}}(\operatorname {\mathrm {Init}}(\mathfrak {s}))$
. When 
 $\mathfrak {s}' \neq \emptyset $
, we set
$\mathfrak {s}' \neq \emptyset $
, we set 
 $$\begin{align*}\mathfrak{s}" := (s^\prime_{1} - q, \mathfrak{s}^\prime_{-}) = (s_{\ell_{1} + 1} - q, \mathfrak{s}^\prime_{-}).\end{align*}$$
$$\begin{align*}\mathfrak{s}" := (s^\prime_{1} - q, \mathfrak{s}^\prime_{-}) = (s_{\ell_{1} + 1} - q, \mathfrak{s}^\prime_{-}).\end{align*}$$
We recall 
 $\mathscr {U}^{\bullet }(\mathfrak {s})$
 given in Definition 3.4 by
$\mathscr {U}^{\bullet }(\mathfrak {s})$
 given in Definition 3.4 by 
 $$ \begin{align*} \mathscr{U}^{\bullet}(\mathfrak{s}) := \left\{ \begin{array}{@{}ll} - [\mathfrak{s}^{\mathrm{T}}, q^{\{m + 1\}}, \mathfrak{s}"] + L_{1}^{m + 1} [\mathfrak{s}^{\mathrm{T}}, \alpha_{q}^{\bullet, m + 1}(\mathfrak{s}")] & \\ \hspace{5.0em} + L_{1}^{m + 1} (\mathfrak{s}^{\mathrm{T}} \boxplus \alpha_{q}^{\bullet, m + 1}(\mathfrak{s}")) - [\mathfrak{s}^{\mathrm{T}}, q^{\{m\}}, D^{\bullet}_{q, \mathfrak{s}"}] & (\mathfrak{s}' \neq \emptyset) \\[0.5em] L_{1}^{m} [\mathfrak{s}^{\mathrm{T}}, \alpha_{q}^{\bullet, m}(\emptyset)] + L_{1}^{m} (\mathfrak{s}^{\mathrm{T}} \boxplus \alpha_{q}^{\bullet, m}(\emptyset)) & (\mathfrak{s}' = \emptyset) \end{array}. \right. \end{align*} $$
$$ \begin{align*} \mathscr{U}^{\bullet}(\mathfrak{s}) := \left\{ \begin{array}{@{}ll} - [\mathfrak{s}^{\mathrm{T}}, q^{\{m + 1\}}, \mathfrak{s}"] + L_{1}^{m + 1} [\mathfrak{s}^{\mathrm{T}}, \alpha_{q}^{\bullet, m + 1}(\mathfrak{s}")] & \\ \hspace{5.0em} + L_{1}^{m + 1} (\mathfrak{s}^{\mathrm{T}} \boxplus \alpha_{q}^{\bullet, m + 1}(\mathfrak{s}")) - [\mathfrak{s}^{\mathrm{T}}, q^{\{m\}}, D^{\bullet}_{q, \mathfrak{s}"}] & (\mathfrak{s}' \neq \emptyset) \\[0.5em] L_{1}^{m} [\mathfrak{s}^{\mathrm{T}}, \alpha_{q}^{\bullet, m}(\emptyset)] + L_{1}^{m} (\mathfrak{s}^{\mathrm{T}} \boxplus \alpha_{q}^{\bullet, m}(\emptyset)) & (\mathfrak{s}' = \emptyset) \end{array}. \right. \end{align*} $$
It is clear that 
 $\mathscr {U}^{\bullet }(\mathfrak {s}) \in \mathcal {H}_{\operatorname {\mathrm {wt}}(\mathfrak {s})}$
.
$\mathscr {U}^{\bullet }(\mathfrak {s}) \in \mathcal {H}_{\operatorname {\mathrm {wt}}(\mathfrak {s})}$
.
Theorem A.5 (Theorem 3.6 (1)).
 For each 
 $P \in \mathcal {H}$
, we have
$P \in \mathcal {H}$
, we have 
 $\mathscr {L}^{\bullet }(\mathscr {U}^{\bullet }(P)) = \mathscr {L}^{\bullet }(P)$
.
$\mathscr {L}^{\bullet }(\mathscr {U}^{\bullet }(P)) = \mathscr {L}^{\bullet }(P)$
.
Proof. We may assume that 
 $P = \mathfrak {s} \in \mathcal {I}$
 as above. By the definition of
$P = \mathfrak {s} \in \mathcal {I}$
 as above. By the definition of 
 $\mathscr {U}^{\bullet }$
, it suffices to show the desired result in the case
$\mathscr {U}^{\bullet }$
, it suffices to show the desired result in the case 
 $\mathfrak {s} \notin \mathcal {I}^{\mathrm {T}}$
. We first consider the case that
$\mathfrak {s} \notin \mathcal {I}^{\mathrm {T}}$
. We first consider the case that 
 $\mathfrak {s}' \neq \emptyset $
. Recall that
$\mathfrak {s}' \neq \emptyset $
. Recall that 
 $R_1$
 is given in (A.3) and
$R_1$
 is given in (A.3) and 
 $\alpha ^{\bullet }_{q}$
 is defined in (3.3). Note that by definition, we have
$\alpha ^{\bullet }_{q}$
 is defined in (3.3). Note that by definition, we have 
 $$ \begin{align*} \mathscr{BC}^{\bullet, m}_{q}\left( (\mathscr{C}^{\bullet}_{\mathfrak{s}"}(R_{1}))\right) &= \mathscr{BC}^{\bullet, m}_{q} \left( [\mathfrak{s}'] + [q, \mathfrak{s}"] + D^{\bullet}_{q, \mathfrak{s}"}, \ - L_{1} \alpha^{\bullet}_{q}(\mathfrak{s}") \right) \\ &= \left( [q^{\{m\}}, \mathfrak{s}'] + [q^{\{m + 1\}}, \mathfrak{s}"] + [q^{\{m\}}, D^{\bullet}_{q, \mathfrak{s}"}], \ - L_{1}^{m + 1} \alpha^{\bullet, m + 1}_{q}(\mathfrak{s}") \right). \end{align*} $$
$$ \begin{align*} \mathscr{BC}^{\bullet, m}_{q}\left( (\mathscr{C}^{\bullet}_{\mathfrak{s}"}(R_{1}))\right) &= \mathscr{BC}^{\bullet, m}_{q} \left( [\mathfrak{s}'] + [q, \mathfrak{s}"] + D^{\bullet}_{q, \mathfrak{s}"}, \ - L_{1} \alpha^{\bullet}_{q}(\mathfrak{s}") \right) \\ &= \left( [q^{\{m\}}, \mathfrak{s}'] + [q^{\{m + 1\}}, \mathfrak{s}"] + [q^{\{m\}}, D^{\bullet}_{q, \mathfrak{s}"}], \ - L_{1}^{m + 1} \alpha^{\bullet, m + 1}_{q}(\mathfrak{s}") \right). \end{align*} $$
If 
 $\mathfrak {s}^{\mathrm {T}} = \emptyset $
, we can express
$\mathfrak {s}^{\mathrm {T}} = \emptyset $
, we can express 
 $$ \begin{align} \mathscr{BC}^{\bullet, m}_{q}(\mathscr{C}^{\bullet}_{\mathfrak{s}"}(R_{1})) = \left( [\mathfrak{s}] + [\mathfrak{s}^{\mathrm{T}}, q^{\{m + 1\}}, \mathfrak{s}"] + [\mathfrak{s}^{\mathrm{T}}, q^{\{m\}}, D^{\bullet}_{q, \mathfrak{s}"}], \ - L_{1}^{m + 1} [\mathfrak{s}^{\mathrm{T}}, \alpha^{\bullet, m + 1}_{q}(\mathfrak{s}")] \right). \end{align} $$
$$ \begin{align} \mathscr{BC}^{\bullet, m}_{q}(\mathscr{C}^{\bullet}_{\mathfrak{s}"}(R_{1})) = \left( [\mathfrak{s}] + [\mathfrak{s}^{\mathrm{T}}, q^{\{m + 1\}}, \mathfrak{s}"] + [\mathfrak{s}^{\mathrm{T}}, q^{\{m\}}, D^{\bullet}_{q, \mathfrak{s}"}], \ - L_{1}^{m + 1} [\mathfrak{s}^{\mathrm{T}}, \alpha^{\bullet, m + 1}_{q}(\mathfrak{s}")] \right). \end{align} $$
If 
 $\mathfrak {s}^{\mathrm {T}} \neq \emptyset $
, we have
$\mathfrak {s}^{\mathrm {T}} \neq \emptyset $
, we have 
 $$ \begin{align} &\mathscr{B}^{\bullet}_{\mathfrak{s}^{\mathrm{T}}}(\mathscr{BC}^{\bullet, m}_{q}(\mathscr{C}^{\bullet}_{\mathfrak{s}"}(R_{1}))) \\ &= \left( [\mathfrak{s}] + [\mathfrak{s}^{\mathrm{T}}, q^{\{m + 1\}}, \mathfrak{s}"] + [\mathfrak{s}^{\mathrm{T}}, q^{\{m\}}, D^{\bullet}_{q, \mathfrak{s}"}] - L_{1}^{m + 1} [\mathfrak{s}^{\mathrm{T}}, \alpha^{\bullet, m + 1}_{q}(\mathfrak{s}")] - L_{1}^{m + 1} [\mathfrak{s}^{\mathrm{T}} \boxplus \alpha^{\bullet, m + 1}_{q}(\mathfrak{s}")], \ 0 \right), \nonumber \end{align} $$
$$ \begin{align} &\mathscr{B}^{\bullet}_{\mathfrak{s}^{\mathrm{T}}}(\mathscr{BC}^{\bullet, m}_{q}(\mathscr{C}^{\bullet}_{\mathfrak{s}"}(R_{1}))) \\ &= \left( [\mathfrak{s}] + [\mathfrak{s}^{\mathrm{T}}, q^{\{m + 1\}}, \mathfrak{s}"] + [\mathfrak{s}^{\mathrm{T}}, q^{\{m\}}, D^{\bullet}_{q, \mathfrak{s}"}] - L_{1}^{m + 1} [\mathfrak{s}^{\mathrm{T}}, \alpha^{\bullet, m + 1}_{q}(\mathfrak{s}")] - L_{1}^{m + 1} [\mathfrak{s}^{\mathrm{T}} \boxplus \alpha^{\bullet, m + 1}_{q}(\mathfrak{s}")], \ 0 \right), \nonumber \end{align} $$
where we use Remark 2.6 and the fact 
 $[\mathfrak {s}^{\mathrm {T}}_{+},0]=0\in \mathcal {H}$
 from Remark 2.3.
$[\mathfrak {s}^{\mathrm {T}}_{+},0]=0\in \mathcal {H}$
 from Remark 2.3.
 Next, we suppose that 
 $\mathfrak {s}' = \emptyset $
. Then
$\mathfrak {s}' = \emptyset $
. Then 
 $m \geq 1$
 and we have
$m \geq 1$
 and we have 
 $$ \begin{align*} \mathscr{BC}^{\bullet, m - 1}_{q}(R_{1}) = \left( [q^{\{m\}}], \ L_{1}^{m - 1} \alpha^{\bullet, m - 1}_{q}(- L_{1} [1, q - 1]) \right) = \left( [q^{\{m\}}], \ - L_{1}^{m} \alpha^{\bullet, m}_{q}(\emptyset) \right). \end{align*} $$
$$ \begin{align*} \mathscr{BC}^{\bullet, m - 1}_{q}(R_{1}) = \left( [q^{\{m\}}], \ L_{1}^{m - 1} \alpha^{\bullet, m - 1}_{q}(- L_{1} [1, q - 1]) \right) = \left( [q^{\{m\}}], \ - L_{1}^{m} \alpha^{\bullet, m}_{q}(\emptyset) \right). \end{align*} $$
If 
 $\mathfrak {s}^{\mathrm {T}} = \emptyset $
, then we have
$\mathfrak {s}^{\mathrm {T}} = \emptyset $
, then we have 
 $$ \begin{align} \mathscr{BC}^{\bullet, m - 1}_{q}(R_{1}) = \left( [\mathfrak{s}], \ - L_{1}^{m} [\mathfrak{s}^{\mathrm{T}}, \alpha^{\bullet, m}_{q}(\emptyset)] \right), \end{align} $$
$$ \begin{align} \mathscr{BC}^{\bullet, m - 1}_{q}(R_{1}) = \left( [\mathfrak{s}], \ - L_{1}^{m} [\mathfrak{s}^{\mathrm{T}}, \alpha^{\bullet, m}_{q}(\emptyset)] \right), \end{align} $$
and if 
 $\mathfrak {s}^{\mathrm {T}} \neq \emptyset $
, then by Remark 2.6 and
$\mathfrak {s}^{\mathrm {T}} \neq \emptyset $
, then by Remark 2.6 and 
 $[\mathfrak {s}^{\mathrm {T}}_{+},0]=0\in \mathcal {H}$
, we have
$[\mathfrak {s}^{\mathrm {T}}_{+},0]=0\in \mathcal {H}$
, we have 
 $$ \begin{align} \mathscr{B}^{\bullet}_{\mathfrak{s}^{\mathrm{T}}}(\mathscr{BC}^{\bullet, m - 1}_{q}(R_{1})) = \left( [\mathfrak{s}] - L_{1}^{m} [\mathfrak{s}^{\mathrm{T}}, \alpha^{\bullet, m}_{q}(\emptyset)] - L_{1}^{m} (\mathfrak{s}^{\mathrm{T}} \boxplus \alpha^{\bullet, m}_{q}(\emptyset)), \ 0 \right). \end{align} $$
$$ \begin{align} \mathscr{B}^{\bullet}_{\mathfrak{s}^{\mathrm{T}}}(\mathscr{BC}^{\bullet, m - 1}_{q}(R_{1})) = \left( [\mathfrak{s}] - L_{1}^{m} [\mathfrak{s}^{\mathrm{T}}, \alpha^{\bullet, m}_{q}(\emptyset)] - L_{1}^{m} (\mathfrak{s}^{\mathrm{T}} \boxplus \alpha^{\bullet, m}_{q}(\emptyset)), \ 0 \right). \end{align} $$
 Recall from (A.3) that 
 $R_{1}\in \mathcal {P}_{q}^{\bullet }$
. It follows by Theorem A.4 that the left-hand side (LHS) of each of the equations (A.4), (A.5), (A.6) and (A.7) belongs to
$R_{1}\in \mathcal {P}_{q}^{\bullet }$
. It follows by Theorem A.4 that the left-hand side (LHS) of each of the equations (A.4), (A.5), (A.6) and (A.7) belongs to 
 $\mathcal {P}_{\operatorname {\mathrm {wt}}(\mathfrak {s})}^{\bullet }$
. Thus, in any case of the four equations above, we have that
$\mathcal {P}_{\operatorname {\mathrm {wt}}(\mathfrak {s})}^{\bullet }$
. Thus, in any case of the four equations above, we have that 
 $$ \begin{align*} 0 = \mathscr{L}^{\bullet}(\mathrm{LHS}) = \mathscr{L}^{\bullet}(\mathrm{RHS}) = \mathscr{L}^{\bullet}(\mathfrak{s}) - \mathscr{L}^{\bullet}(\mathscr{U}^{\bullet}(\mathfrak{s})), \end{align*} $$
$$ \begin{align*} 0 = \mathscr{L}^{\bullet}(\mathrm{LHS}) = \mathscr{L}^{\bullet}(\mathrm{RHS}) = \mathscr{L}^{\bullet}(\mathfrak{s}) - \mathscr{L}^{\bullet}(\mathscr{U}^{\bullet}(\mathfrak{s})), \end{align*} $$
whence we obtain
 $$\begin{align*}\mathscr{L}^{\bullet}(\mathfrak{s})=\mathscr{L}^{\bullet}(\mathscr{U}^{\bullet}(\mathfrak{s})).\\[-35pt]\end{align*}$$
$$\begin{align*}\mathscr{L}^{\bullet}(\mathfrak{s})=\mathscr{L}^{\bullet}(\mathscr{U}^{\bullet}(\mathfrak{s})).\\[-35pt]\end{align*}$$
We set
 $$ \begin{align*} \mathscr{U}^{\bullet}_{1}(\mathfrak{s}) &:= \left\{ \begin{array}{ll} - [\mathfrak{s}^{\mathrm{T}}, q^{\{m + 1\}}, \mathfrak{s}"] + L_{1}^{m + 1} [\mathfrak{s}^{\mathrm{T}}, \alpha_{q}^{\bullet, m + 1}(\mathfrak{s}")] & (\mathfrak{s}' \neq \emptyset) \\ L_{1}^{m} [\mathfrak{s}^{\mathrm{T}}, \alpha_{q}^{\bullet, m}(\emptyset)] & (\mathfrak{s}' = \emptyset) \end{array} \right., \\ \mathscr{U}^{\bullet}_{2}(\mathfrak{s}) &:= \left\{ \begin{array}{ll} L_{1}^{m + 1} (\mathfrak{s}^{\mathrm{T}} \boxplus \alpha_{q}^{\bullet, m + 1}(\mathfrak{s}")) & (\mathfrak{s}' \neq \emptyset) \\ L_{1}^{m} (\mathfrak{s}^{\mathrm{T}} \boxplus \alpha_{q}^{\bullet, m}(\emptyset)) & (\mathfrak{s}' = \emptyset) \end{array} \right., \\ \mathscr{U}^{\bullet}_{3}(\mathfrak{s}) &:= \left\{ \begin{array}{ll} - [\mathfrak{s}^{\mathrm{T}}, q^{\{m\}}, D^{\bullet}_{q, \mathfrak{s}"}] & (\mathfrak{s}' \neq \emptyset) \\ 0 & (\mathfrak{s}' = \emptyset) \end{array} \right.. \end{align*} $$
$$ \begin{align*} \mathscr{U}^{\bullet}_{1}(\mathfrak{s}) &:= \left\{ \begin{array}{ll} - [\mathfrak{s}^{\mathrm{T}}, q^{\{m + 1\}}, \mathfrak{s}"] + L_{1}^{m + 1} [\mathfrak{s}^{\mathrm{T}}, \alpha_{q}^{\bullet, m + 1}(\mathfrak{s}")] & (\mathfrak{s}' \neq \emptyset) \\ L_{1}^{m} [\mathfrak{s}^{\mathrm{T}}, \alpha_{q}^{\bullet, m}(\emptyset)] & (\mathfrak{s}' = \emptyset) \end{array} \right., \\ \mathscr{U}^{\bullet}_{2}(\mathfrak{s}) &:= \left\{ \begin{array}{ll} L_{1}^{m + 1} (\mathfrak{s}^{\mathrm{T}} \boxplus \alpha_{q}^{\bullet, m + 1}(\mathfrak{s}")) & (\mathfrak{s}' \neq \emptyset) \\ L_{1}^{m} (\mathfrak{s}^{\mathrm{T}} \boxplus \alpha_{q}^{\bullet, m}(\emptyset)) & (\mathfrak{s}' = \emptyset) \end{array} \right., \\ \mathscr{U}^{\bullet}_{3}(\mathfrak{s}) &:= \left\{ \begin{array}{ll} - [\mathfrak{s}^{\mathrm{T}}, q^{\{m\}}, D^{\bullet}_{q, \mathfrak{s}"}] & (\mathfrak{s}' \neq \emptyset) \\ 0 & (\mathfrak{s}' = \emptyset) \end{array} \right.. \end{align*} $$
It is clear that 
 $\mathscr {U}^{\bullet }_{i}(\mathfrak {s}) \in \mathcal {H}_{\operatorname {\mathrm {wt}}(\mathfrak {s})}$
 for
$\mathscr {U}^{\bullet }_{i}(\mathfrak {s}) \in \mathcal {H}_{\operatorname {\mathrm {wt}}(\mathfrak {s})}$
 for 
 $1 \leq i \leq 3$
 and
$1 \leq i \leq 3$
 and 
 $\mathscr {U}^{\bullet }(\mathfrak {s}) = \mathscr {U}^{\bullet }_{1}(\mathfrak {s}) + \mathscr {U}^{\bullet }_{2}(\mathfrak {s}) + \mathscr {U}^{\bullet }_{3}(\mathfrak {s})$
.
$\mathscr {U}^{\bullet }(\mathfrak {s}) = \mathscr {U}^{\bullet }_{1}(\mathfrak {s}) + \mathscr {U}^{\bullet }_{2}(\mathfrak {s}) + \mathscr {U}^{\bullet }_{3}(\mathfrak {s})$
.
Lemma A.6. Let 
 $\mathfrak {s} \in \mathcal {I} \setminus \mathcal {I}^{\mathrm {T}}$
. Then the following hold:
$\mathfrak {s} \in \mathcal {I} \setminus \mathcal {I}^{\mathrm {T}}$
. Then the following hold: 
- 
(1) If  $\mathfrak {n} \in \operatorname {\mathrm {Supp}}(\mathscr {U}^{\bullet }_{1}(\mathfrak {s}))$
, then $\mathfrak {n} \in \operatorname {\mathrm {Supp}}(\mathscr {U}^{\bullet }_{1}(\mathfrak {s}))$
, then $\operatorname {\mathrm {dep}}(\mathfrak {n})> \operatorname {\mathrm {dep}}(\mathfrak {s})$
. $\operatorname {\mathrm {dep}}(\mathfrak {n})> \operatorname {\mathrm {dep}}(\mathfrak {s})$
.
- 
(2) If  $\mathfrak {n} \in \operatorname {\mathrm {Supp}}(\mathscr {U}^{\bullet }_{2}(\mathfrak {s}))$
, then $\mathfrak {n} \in \operatorname {\mathrm {Supp}}(\mathscr {U}^{\bullet }_{2}(\mathfrak {s}))$
, then $\operatorname {\mathrm {dep}}(\mathfrak {n}) \geq \operatorname {\mathrm {dep}}(\mathfrak {s})$
 and $\operatorname {\mathrm {dep}}(\mathfrak {n}) \geq \operatorname {\mathrm {dep}}(\mathfrak {s})$
 and $\operatorname {\mathrm {Init}}(\mathfrak {n})> \operatorname {\mathrm {Init}}(\mathfrak {s})$
 (using lexicographical order). $\operatorname {\mathrm {Init}}(\mathfrak {n})> \operatorname {\mathrm {Init}}(\mathfrak {s})$
 (using lexicographical order).
- 
(3) If  $\mathfrak {n} \in \operatorname {\mathrm {Supp}}(\mathscr {U}^{\bullet }_{3}(\mathfrak {s}))$
, then $\mathfrak {n} \in \operatorname {\mathrm {Supp}}(\mathscr {U}^{\bullet }_{3}(\mathfrak {s}))$
, then $\operatorname {\mathrm {dep}}(\mathfrak {n}) \geq \operatorname {\mathrm {dep}}(\mathfrak {s})> \ell _{1} := \operatorname {\mathrm {dep}}(\operatorname {\mathrm {Init}}(\mathfrak {s}))$
, $\operatorname {\mathrm {dep}}(\mathfrak {n}) \geq \operatorname {\mathrm {dep}}(\mathfrak {s})> \ell _{1} := \operatorname {\mathrm {dep}}(\operatorname {\mathrm {Init}}(\mathfrak {s}))$
, $\operatorname {\mathrm {Init}}(\mathfrak {n}) \geq \operatorname {\mathrm {Init}}(\mathfrak {s})$
 and $\operatorname {\mathrm {Init}}(\mathfrak {n}) \geq \operatorname {\mathrm {Init}}(\mathfrak {s})$
 and $1 \leq n_{\ell _{1} + 1} < s_{\ell _{1} + 1}$
. $1 \leq n_{\ell _{1} + 1} < s_{\ell _{1} + 1}$
.
Proof. First, we note that since 
 $\mathfrak {s} \notin \mathcal {I}^{\mathrm {T}}$
, if
$\mathfrak {s} \notin \mathcal {I}^{\mathrm {T}}$
, if 
 $\mathfrak {s}' \kern1.3pt{=}\kern1.3pt \emptyset $
, then
$\mathfrak {s}' \kern1.3pt{=}\kern1.3pt \emptyset $
, then 
 $m \kern1.3pt{\geq}\kern1.3pt 1$
. By Corollary A.2, we have
$m \kern1.3pt{\geq}\kern1.3pt 1$
. By Corollary A.2, we have 
 $\operatorname {\mathrm {dep}}(\mathfrak {n}) \kern1.3pt{\geq}\kern1.3pt \operatorname {\mathrm {dep}}(\mathfrak {s})$
 for all
$\operatorname {\mathrm {dep}}(\mathfrak {n}) \kern1.3pt{\geq}\kern1.3pt \operatorname {\mathrm {dep}}(\mathfrak {s})$
 for all 
 $1 \leq i \leq 3$
 and
$1 \leq i \leq 3$
 and 
 $\mathfrak {n} \in \operatorname {\mathrm {Supp}}(\mathscr {U}^{\bullet }_{i}(\mathfrak {s}))$
 and
$\mathfrak {n} \in \operatorname {\mathrm {Supp}}(\mathscr {U}^{\bullet }_{i}(\mathfrak {s}))$
 and 
 $\operatorname {\mathrm {dep}}(\mathfrak {n})> \operatorname {\mathrm {dep}}(\mathfrak {s})$
 for all
$\operatorname {\mathrm {dep}}(\mathfrak {n})> \operatorname {\mathrm {dep}}(\mathfrak {s})$
 for all 
 $\mathfrak {n} \in \operatorname {\mathrm {Supp}}(\mathscr {U}^{\bullet }_{1}(\mathfrak {s}))$
.
$\mathfrak {n} \in \operatorname {\mathrm {Supp}}(\mathscr {U}^{\bullet }_{1}(\mathfrak {s}))$
.
 By the definition of 
 $\alpha _{q}^{\bullet }$
, when
$\alpha _{q}^{\bullet }$
, when 
 $\mathfrak {n} \in \operatorname {\mathrm {Supp}}(\mathscr {U}^{\bullet }_{2}(\mathfrak {s}))$
, we can write
$\mathfrak {n} \in \operatorname {\mathrm {Supp}}(\mathscr {U}^{\bullet }_{2}(\mathfrak {s}))$
, we can write 
 $\mathfrak {n} = \mathfrak {s}^{\mathrm {T}} \boxplus [1, \mathfrak {n}_{0}]$
 for some
$\mathfrak {n} = \mathfrak {s}^{\mathrm {T}} \boxplus [1, \mathfrak {n}_{0}]$
 for some 
 $\mathfrak {n}_{0} \in \mathcal {I}$
. We may assume
$\mathfrak {n}_{0} \in \mathcal {I}$
. We may assume 
 $\mathfrak {s}^{\mathrm {T}}\neq \emptyset $
 since if
$\mathfrak {s}^{\mathrm {T}}\neq \emptyset $
 since if 
 $\mathfrak {s}^{\mathrm {T}}=\emptyset $
, we have
$\mathfrak {s}^{\mathrm {T}}=\emptyset $
, we have 
 $\mathscr {U}^{\bullet }_{2}(\mathfrak {s})=0$
 by the definition of
$\mathscr {U}^{\bullet }_{2}(\mathfrak {s})=0$
 by the definition of 
 $\boxplus $
. Let
$\boxplus $
. Let 
 $j:=\operatorname {\mathrm {dep}} \mathfrak {s}^{\mathrm {T}}$
 and so
$j:=\operatorname {\mathrm {dep}} \mathfrak {s}^{\mathrm {T}}$
 and so 
 $s_{j}<q$
. Since
$s_{j}<q$
. Since 
 $s_{j} + 1 \leq q$
, we have
$s_{j} + 1 \leq q$
, we have 
 $\operatorname {\mathrm {Init}}(\mathfrak {n}) = (s_{1}, \ldots , s_{j - 1}, s_{j} + 1, \ldots )> (\mathfrak {s}^{\mathrm {T}}, q^{\{m\}}) = \operatorname {\mathrm {Init}}(\mathfrak {s})$
.
$\operatorname {\mathrm {Init}}(\mathfrak {n}) = (s_{1}, \ldots , s_{j - 1}, s_{j} + 1, \ldots )> (\mathfrak {s}^{\mathrm {T}}, q^{\{m\}}) = \operatorname {\mathrm {Init}}(\mathfrak {s})$
.
 Let 
 $\mathfrak {n} = (n_{1}, \ldots ) \in \operatorname {\mathrm {Supp}}(\mathscr {U}^{\bullet }_{3}(\mathfrak {s}))$
. We may assume that
$\mathfrak {n} = (n_{1}, \ldots ) \in \operatorname {\mathrm {Supp}}(\mathscr {U}^{\bullet }_{3}(\mathfrak {s}))$
. We may assume that 
 $\mathfrak {s}' \neq \emptyset $
 and
$\mathfrak {s}' \neq \emptyset $
 and 
 $\bullet = \zeta $
. In particular,
$\bullet = \zeta $
. In particular, 
 $\operatorname {\mathrm {dep}}(\mathfrak {s})> \ell _{1}$
. Note that any
$\operatorname {\mathrm {dep}}(\mathfrak {s})> \ell _{1}$
. Note that any 
 $\mathfrak {n}^{\dagger } \in \operatorname {\mathrm {Supp}}(D^{\zeta }_{q, \mathfrak {s}"})$
 can be written as
$\mathfrak {n}^{\dagger } \in \operatorname {\mathrm {Supp}}(D^{\zeta }_{q, \mathfrak {s}"})$
 can be written as 
 $\mathfrak {n}^{\dagger } = (s_{\ell _{1} + 1} - i, \mathfrak {n}^{\dagger }_{-})$
 for some
$\mathfrak {n}^{\dagger } = (s_{\ell _{1} + 1} - i, \mathfrak {n}^{\dagger }_{-})$
 for some 
 $1 \leq i < s_{\ell _{1} + 1}$
 and
$1 \leq i < s_{\ell _{1} + 1}$
 and 
 $\mathfrak {n}^{\dagger }_{-} \in \mathcal {I}$
. Then by the definition of
$\mathfrak {n}^{\dagger }_{-} \in \mathcal {I}$
. Then by the definition of 
 $\mathscr {U}^{\bullet }_3(\mathfrak {s})$
, we have
$\mathscr {U}^{\bullet }_3(\mathfrak {s})$
, we have 
 $\mathfrak {n} = (\mathfrak {s}^{\mathrm {T}}, q^{\{m\}}, \mathfrak {n}^{\dagger }) = (\mathfrak {s}^{\mathrm {T}}, q^{\{m\}}, s_{\ell _{1} + 1} - i, \mathfrak {n}^{\dagger }_{-})$
. Thus,
$\mathfrak {n} = (\mathfrak {s}^{\mathrm {T}}, q^{\{m\}}, \mathfrak {n}^{\dagger }) = (\mathfrak {s}^{\mathrm {T}}, q^{\{m\}}, s_{\ell _{1} + 1} - i, \mathfrak {n}^{\dagger }_{-})$
. Thus, 
 $\operatorname {\mathrm {Init}}(\mathfrak {n}) = (\mathfrak {s}^{\mathrm {T}}, q^{\{m\}}, \ldots ) \geq (\mathfrak {s}^{\mathrm {T}}, q^{\{m\}}) = \operatorname {\mathrm {Init}}(\mathfrak {s})$
 and
$\operatorname {\mathrm {Init}}(\mathfrak {n}) = (\mathfrak {s}^{\mathrm {T}}, q^{\{m\}}, \ldots ) \geq (\mathfrak {s}^{\mathrm {T}}, q^{\{m\}}) = \operatorname {\mathrm {Init}}(\mathfrak {s})$
 and 
 $n_{\ell _{1} + 1} = s_{\ell _{1} + 1} - i < s_{\ell _{1} + 1}$
.
$n_{\ell _{1} + 1} = s_{\ell _{1} + 1} - i < s_{\ell _{1} + 1}$
.
Theorem A.7 (Theorem 3.6 (2)).
 For each 
 $P \in \mathcal {H}$
, there exists
$P \in \mathcal {H}$
, there exists 
 $e \geq 0$
 such that
$e \geq 0$
 such that 
 $\operatorname {\mathrm {Supp}}((\mathscr {U}^{\bullet })^{e}(P)) \subset \mathcal {I}^{\mathrm {T}}$
, where
$\operatorname {\mathrm {Supp}}((\mathscr {U}^{\bullet })^{e}(P)) \subset \mathcal {I}^{\mathrm {T}}$
, where 
 $(\mathscr {U}^{\bullet })^{0}$
 is defined to be the identity map and for
$(\mathscr {U}^{\bullet })^{0}$
 is defined to be the identity map and for 
 $e\in \mathbb {Z}_{>0}$
,
$e\in \mathbb {Z}_{>0}$
, 
 $(\mathscr {U}^{\bullet })^{e}$
 is defined to be the e-th iteration of
$(\mathscr {U}^{\bullet })^{e}$
 is defined to be the e-th iteration of 
 $\mathscr {U}^{\bullet }$
.
$\mathscr {U}^{\bullet }$
.
Proof. We may assume that 
 $P = \mathfrak {s} = (s_{1}, \ldots ) \in \mathcal {I}_{w}$
 for some
$P = \mathfrak {s} = (s_{1}, \ldots ) \in \mathcal {I}_{w}$
 for some 
 $w \geq 0$
. By Lemma A.6, for each index
$w \geq 0$
. By Lemma A.6, for each index 
 $\mathfrak {n} = (n_{1}, \ldots ) \in \operatorname {\mathrm {Supp}}(\mathscr {U}^{\bullet }(\mathfrak {s}))$
, one of the following conditions holds:
$\mathfrak {n} = (n_{1}, \ldots ) \in \operatorname {\mathrm {Supp}}(\mathscr {U}^{\bullet }(\mathfrak {s}))$
, one of the following conditions holds: 
- 
(1)  $\mathfrak {s} \in \mathcal {I}^{\mathrm {T}}_{w}$
 (and hence $\mathfrak {s} \in \mathcal {I}^{\mathrm {T}}_{w}$
 (and hence $\mathfrak {n} = \mathfrak {s}$
); $\mathfrak {n} = \mathfrak {s}$
);
- 
(2)  $\mathfrak {s} \notin \mathcal {I}^{\mathrm {T}}_{w}$
, $\mathfrak {s} \notin \mathcal {I}^{\mathrm {T}}_{w}$
, $\operatorname {\mathrm {dep}}(\mathfrak {n})> \operatorname {\mathrm {dep}}(\mathfrak {s})$
; $\operatorname {\mathrm {dep}}(\mathfrak {n})> \operatorname {\mathrm {dep}}(\mathfrak {s})$
;
- 
(3)  $\mathfrak {s} \notin \mathcal {I}^{\mathrm {T}}_{w}$
, $\mathfrak {s} \notin \mathcal {I}^{\mathrm {T}}_{w}$
, $\operatorname {\mathrm {dep}}(\mathfrak {n}) = \operatorname {\mathrm {dep}}(\mathfrak {s})$
, $\operatorname {\mathrm {dep}}(\mathfrak {n}) = \operatorname {\mathrm {dep}}(\mathfrak {s})$
, $\operatorname {\mathrm {Init}}(\mathfrak {n})> \operatorname {\mathrm {Init}}(\mathfrak {s})$
 (using lexicographical order); $\operatorname {\mathrm {Init}}(\mathfrak {n})> \operatorname {\mathrm {Init}}(\mathfrak {s})$
 (using lexicographical order);
- 
(4)  $\mathfrak {s} \notin \mathcal {I}^{\mathrm {T}}_{w}$
, $\mathfrak {s} \notin \mathcal {I}^{\mathrm {T}}_{w}$
, $\operatorname {\mathrm {dep}}(\mathfrak {n}) = \operatorname {\mathrm {dep}}(\mathfrak {s})$
, $\operatorname {\mathrm {dep}}(\mathfrak {n}) = \operatorname {\mathrm {dep}}(\mathfrak {s})$
, $\operatorname {\mathrm {Init}}(\mathfrak {n}) = \operatorname {\mathrm {Init}}(\mathfrak {s})$
, $\operatorname {\mathrm {Init}}(\mathfrak {n}) = \operatorname {\mathrm {Init}}(\mathfrak {s})$
, $n_{\operatorname {\mathrm {dep}}(\operatorname {\mathrm {Init}}(\mathfrak {n})) + 1} < s_{\operatorname {\mathrm {dep}}(\operatorname {\mathrm {Init}}(\mathfrak {s})) + 1}$
. $n_{\operatorname {\mathrm {dep}}(\operatorname {\mathrm {Init}}(\mathfrak {n})) + 1} < s_{\operatorname {\mathrm {dep}}(\operatorname {\mathrm {Init}}(\mathfrak {s})) + 1}$
.
This means that 
 $\mathfrak {n} = \mathfrak {s} \in \mathcal {I}^{\mathrm {T}}_{w}$
 or
$\mathfrak {n} = \mathfrak {s} \in \mathcal {I}^{\mathrm {T}}_{w}$
 or 
 $$ \begin{align*} (\operatorname{\mathrm{dep}}(\mathfrak{n}); \operatorname{\mathrm{Init}}(\mathfrak{n}); - n_{\operatorname{\mathrm{dep}}(\operatorname{\mathrm{Init}}(\mathfrak{n})) + 1})> (\operatorname{\mathrm{dep}}(\mathfrak{s}); \operatorname{\mathrm{Init}}(\mathfrak{s}); - s_{\operatorname{\mathrm{dep}}(\operatorname{\mathrm{Init}}(\mathfrak{s})) + 1}) \end{align*} $$
$$ \begin{align*} (\operatorname{\mathrm{dep}}(\mathfrak{n}); \operatorname{\mathrm{Init}}(\mathfrak{n}); - n_{\operatorname{\mathrm{dep}}(\operatorname{\mathrm{Init}}(\mathfrak{n})) + 1})> (\operatorname{\mathrm{dep}}(\mathfrak{s}); \operatorname{\mathrm{Init}}(\mathfrak{s}); - s_{\operatorname{\mathrm{dep}}(\operatorname{\mathrm{Init}}(\mathfrak{s})) + 1}) \end{align*} $$
in 
 $\{ 0, 1, \ldots , w \} \times \operatorname {\mathrm {Init}}(\mathcal {I}_{w}) \times \{ - w, \ldots , - 2, - 1 \}$
 with the lexicographical order. Here, when
$\{ 0, 1, \ldots , w \} \times \operatorname {\mathrm {Init}}(\mathcal {I}_{w}) \times \{ - w, \ldots , - 2, - 1 \}$
 with the lexicographical order. Here, when 
 $\operatorname {\mathrm {Init}}(\mathfrak {s}) = \mathfrak {s}$
 (resp.
$\operatorname {\mathrm {Init}}(\mathfrak {s}) = \mathfrak {s}$
 (resp. 
 $\operatorname {\mathrm {Init}}(\mathfrak {n}) = \mathfrak {n}$
), temporarily we put
$\operatorname {\mathrm {Init}}(\mathfrak {n}) = \mathfrak {n}$
), temporarily we put 
 $s_{\operatorname {\mathrm {dep}}(\operatorname {\mathrm {Init}}(\mathfrak {s})) + 1} := 1$
 (resp.
$s_{\operatorname {\mathrm {dep}}(\operatorname {\mathrm {Init}}(\mathfrak {s})) + 1} := 1$
 (resp. 
 $n_{\operatorname {\mathrm {dep}}(\operatorname {\mathrm {Init}}(\mathfrak {n})) + 1} := 1$
). Since this totally ordered set is finite, this procedure will stop after a finite number of steps.
$n_{\operatorname {\mathrm {dep}}(\operatorname {\mathrm {Init}}(\mathfrak {n})) + 1} := 1$
). Since this totally ordered set is finite, this procedure will stop after a finite number of steps.
Acknowledgments
We are grateful to D. Brownawell, M. Papanikolas and J. Yu for many helpful discussions and their encouragement when writing up the manuscript. We thank the referee for careful reading and providing some helpful comments, which improve the presentation of this paper. We further thank NCTS and Kyushu University for their hospitality and partial financial support regarding our collaboration.
Competing interest
The authors have no competing interest to declare.
Funding statement
Chieh-Yu Chang was supported by NSTC Grant Number 111-2628-M-007-002-, and MOST Grant Number MOST Grant 107-2628-M-007-002-MY4. Yen-Tsung Chen was partially supported by MOST Grant Number 107-2628-M-007-002-MY4. Yoshinori Mishiba was supported by JSPS KAKENHI Grant Numbers JP18K13398 and JP23K03073.
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
